PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Punjab State Board PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements Important Questions and Answers.

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Long Answer Type Questions

Question 1.
What do you understand by Dobereiner’s triads? Give some examples to support it.
Answer:
In 1817, a German Chemist, Dobereiner, gave a classification in which the similar elements were arranged in groups of three called Triads. The arrangement was such that the atomic mass of the middle element was almost the average of the atomic masses of the first and third elements. For example, if A, B and C are the elements present in the triad, then

Atomic mass of B =\(\frac{\text { Atomic mass of } \mathrm{A}+\text { Atomic mass of } \mathrm{C}}{2}\)

Examples of triads.
A few examples of triads are listed as given ahead :
1. Lithium, Sodium. Potassium
Atomic mass of Lithium (Li) = 7
Atomic mass of Potassium (K) = 39
Atomic mass of Sodium (Na) = \(\frac{39+7}{2}\) = 23
Actual atomic mass of sodium = 23

This group of triads is called Alkali Metal Group. All the elements present are metals, have valency equal to one (1) and dissolve in water to form soluble hydroxides called alkalis.

2. Calcium, Strontium, Barium
Atomic mass of Calcium (Ca) = 40
Atomic mass of Barium (Ba) = 137
Atomic mass of Strontium (Sr) = \(\frac{137+40}{2}=\frac{177}{2}\) = 88.5
Actual atomic mass of strontium = 88

This group of triads is called Alkaline Earth Metals Group. All the elements present are metals, have valency equal to two (2) and their oxides dissolve in water to form hydroxides which are alkaline in nature.

Question 2.
(a) What was Dobereiner’s basis of classifying elements?
Answer:
Dobereiner gave a classification in which the elements were arranged in a group of three elements called triads. The arrangement was such that the atomic masses of the middle elements were almost the average of the atomic masses of the first and third elements.

(b) What is the basis of classification of elements according to Mendeleev?
Answer:
The major contribution in the classification of the elements is by Mendeleev, a Russian chemist. He studied in detail the properties of the elements and made a very important observation. He stated that when elements are arranged in order of increasing atomic masses, the elements with similar properties recur after a definite gap. He based his classification of law called Mendeleev’s Periodic Law. The law may be stated as:

Physical and chemical properties of the elements are periodic function of their atomic weights or atomic masses.

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 3.
Give a brief discussion of the Mendeleev’s classification of the elements.
Answer:
Mendeleev’s classification of the elements is based upon the Mendeleev’s periodic law. The law helped him to develop a table called Mendeleev’s Periodic Table. The table has been divided into vertical columns which are called Groups and horizontal rows which are known as Periods.

These are briefly discussed as follows :
1. Groups: These are the vertical rows. There are in all eight groups. The elements present in first seven groups are called Normal Elements. The elements present in group VIII are called the Transition Elements. Each group (I to VII) has been further divided into sub-groups which are called A and B. The inert gas or noble gas elements (He, Ne, Ar, Kr, Xe) were not known at that time. Therefore, they were not shown in the table. All the elements placed in a group have the same valency. Ail the elements present in a sub-group have the similar properties. For example, group I-B includes element Cu (Copper), Ag (Silver) and Au (Gold). They have similar properties.

2. Periods: In the periodic table horizontal rows are called periods. There were in all six periods in the original periodic table. The seventh period was added later on and this is not shown in the periodic table. The properties of the elements present in a period change systematically. For example, in every period, the first element is a typical metal. As we move from left to right, the metallic character gradually decreases and non- metallic character increases. For example, in period 2, the first element Li (Lithium) is a metal while the last element F (Fluorine) is a non-metal. The Mendeleev’s Periodic Table is shown below :

Mendeleev’S Periodic Table
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 1

Question 4.
(a) Why do we classify elements?
Answer:
To simplify and systematize the study of known elements.

(b) What were the two criteria used by Mendeleev in creating his Periodic Table?
Answer:

  1. Mendeleev arranged the elements in order of increasing atomic masses.
  2. Mendeleev considered the compounds formed by the elements oxygen and hydrogen.

(c) Why did Mendeleev leave some gaps in his Periodic Table?
Answer:
For the discovery of new elements.

(d) In Mendeleev’s Periodic Table, why was there no mention of Noble gases like7 Helium, Neon and Argon?
Answer:
Because noble gases were not known at that time.

(e) Would you place the two isotopes of chlorine, Cl-35 and Cl-37 in different slots because of their different atomic masses or in the same slot because their chemical properties are the same? Justify your answer.
Answer:
In the same slot because Cl-35 and Cl-37 have same chemical properties.

Question 5.
How did Mendeleev’s Periodic Table help in the discovery of new elements?
Answer:
When Mendeleev gave the periodic table, only 63 elements were known. The classification was based on two major properties :

  • Elements are arranged in order of increasing atomic masses.
  • Elements present in a group have similar properties.

Many elements were not known at the time the periodic table was given. Therefore, Mendeleev left gaps for these elements in the periodic table. But the properties of these elements could be predicted. For example, let us suppose that Rb (Rubidium) a member of group IA was not known when Mendeleev framed the periodic table. But its properties could be predicted. It was expected to be a metal with valency equal to 1. It was expected to be soluble in water to form a soluble hydroxide RbOH which is an alkali. This helped in the discovery of the element. In this manner, a number of elements could be discovered.

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 6.
Discuss some major merits of the Mendeleev’s Periodic Table.
Answer:
Merits of Mendeleev’s Periodic Table
Mendeleev’s periodic table was the first proper systematic classification of the elements. The important merits of the table are listed as follows :
1. Systematic study of elements. With the classification of elements into groups and periods, their study became quite systematic. For example, if the properties of one particular element in a group are known, those of the other elements could be predicted. Actually, elements placed in a group are expected to show similar characteristics.

2. Correction of wrong atomic masses. The periodic table helped in correcting the atomic masses of some of the elements because the elements were arranged in order of their increasing atomic masses.

3. Prediction of new elements. At the time Mendeleev gave the periodic table, only 63 elements were known. While arranging these elements in groups and periods, certain gaps were left. These gaps represented some undiscovered elements. But the properties of these unknown elements could be predicted from their positions in the respective groups. This helped, later on, to discover these elements.

Question 7.
On the basis of Mendeleev’s Periodic Table given following, answer the questions that follow the table :
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 2
(a) Name the element which is in
(i) 1st group and 3rd period
Answer:
Sodium

(ii) VII group and 2nd period.
Answer:
Fluorine

(b) Suggest the formula for the following :
(i) oxide of nitrogen
Answer:
N2O5

(ii) hydride of oxygen.
Answer:
H2O.

(c) In group VIII of the Periodic Table, why does cobalt with atomic mass 58.93 appear before nickel having atomic mass 58.71?
Answer:
Because the elements with similar properties could be grouped together.

(d) Besides gallium, which two other elements have since been discovered for which Mendeleev had left gaps in his Periodic Table?
Answer:
Scandium and Germanium.

(e) Using atomic masses of Li, Na and K, find the average atomic mass of Li and K and compare it with the atomic mass of Na. State the conclusion drawn from this activity.
Answer:
Average atomic mass of Li and K = \(\frac{6.939+39.102}{2}=\frac{46.04}{2}\) = 23.02
Atomic mass of Na = 22.99
Hence Atomic mass of Na = Average of atomic masses of Li and K = \(\frac{46.04}{2}\) = 23.02

Question 8.
Point out the major defects in Mendeleev’s Periodic Table.
Answer:
Defects in Mendeleev’s Periodic Table:
Mendeleev’s periodic table was quite helpful in the classification of the elements.

But it had certain defects also. These are discussed as follows :
1. Position of hydrogen. Hydrogen was placed at the top of group LA. It is a non-metal where all other elements included in the group are metals.

2. Position of isotopes. The periodic table is based on the basis of the atomic masses of the elements and the elements with different atomic masses must be given separate places in the table. If this is correct, all the isotopes of an element must be allotted separate positions. For example, there are three isotopes for hydrogen and they must be given three separate places in the table. But only one position for hydrogen has been given.

3. Wrong order of atomic masses of some elements. In the table, the elements are arranged in order of increasing atomic masses. This means that the element with higher atomic mass must be placed after the element with the lower atomic mass. But in the table, there are some anomalies. For example, Co (Cobalt) with atomic mass 58-9 should be placed after Ni (Nickel) with atomic mass 58-7. But it has been placed before nickel.

4. Elements with similar properties placed in different groups. In the periodic table, it has been found that the elements with similar properties are placed in different groups. For example, copper and mercury have many common properties. But copper has been placed in group I B and mercury in group II B.

5. No similarity in the elements placed in sub-groups. The elements present in different sub-groups of the same group are expected to have common properties. But these are quite different. For example, elements in group I A are very soft and reactive metals but elements in group IB are hard and less reactive in nature.

6. No explanation for the cause of periodicity. Mendeleev was not in a position to explain why the elements included in a group show similar properties.

Question 9.
Give a brief description of Long Form of Periodic Table.
Answer:
The Long form of periodic table has been formed by arranging the elements in order of increasing atomic numbers. It is based upon Modern periodic law which states that the properties of the elements are the periodic function of their atomic numbers. Just as in case of the Mendeleev’s table, this periodic table has also been divided into Periods and Groups.
(A) Groups
These are the vertical columns. In all, there are eighteen groups in the table. The details of the groups are as follows :

Long Form of Periodic Table of Modern Periodic Table
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 3

  • Group 1: The elements present in group I or 1 are called Alkali Metals.
  • Group 2: The elements which are present in group IIA or 2 are called Alkaline Earth Metals.
  • Groups 13 to Group 18: There are in all six groups. The Groups 13 to 16 are named after the first element present in the family. For example, Group IIIA or 13 is called Boron Family because first member is boron.
  • Group 17 consists of a family called Halogen Family.
  • The group 18 is also called zero group because the elements have zero valency. These elements are ail gases. They have very little tendency to take part in chemical combination. These are also called Noble Gases.

In the latest Long Form of Periodic Table, groups of Alkali metals and Alkaline erttH metals are given numbers 1 and 2. The transition of elements are numbered from its,2 The non-metals are included in groups 13 to 18.

Group No. Name of Family
Group 13 Boron Family
Group 14 Carbon Family
Group 15 Nitrogen Family
Group 16 Oxygen Family
Group 17 Halogens
Group 18 or zero group  Noble Gases
  • Group 3 to Group 12: There are in all ten groups. These are all metals and are called Transition elements. When we go down each group, the metallic character further increases.
  • Group 3: Group 3 also includes fourteen elements belonging to Lanthanide family. These are called Lanthanides because they start after Lanthanum (La) with Z = 57. These are present in the 6th period as shown in the table.
  • It also includes another fourteen elements called Actinides. These are present in 7th period. These are so called as they come after Actinium (Ac) with Z = 89. These are placed at the bottom of the table for convenience.

(B) Periods
Periods are the horizontal rows which are present in the Long Form of Periodic Table. Different periods have different number of elements and their atomic numbers are continuous. There are in all seven periods. The seventh period is still incomplete. The number of elements which are included in each period are given below :

Period No. of elements Name of the Period
1 2 Shortest Period
2 8 Short Period
3 8 Short Period
4 18 Long Period
5 18 Long Period
6 32 Longest Period
7 20 Incomplete Period

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 10.
What is periodicity? What is the cause of periodicity?
Answer:
Periodicity may be defined as the repetition of the similar properties of the elements placed in a group and separated by definite gaps of atomic numbers (8, 8, 18, 18, 32).

Cause of Periodicity. The properties of the elements, particularly the chemical properties, are linked with number of electrons present in the outermost shell of their atoms which is also called Valence shell. Elements with similar valence shell electronic configurations are expected to have similar properties.

It may be noted that all the elements which are present in a group have the same number of electrons in the valence shells of their atoms. In other words, the same valence shell electronic arrangement gets repeated after definite gaps of atomic numbers (8, 8, 18, 18, 32). Therefore, the elements placed in a group show similar properties.

Example, Let us write the electronic distribution of the first four members of the alkali metals present in group I.
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 4
All the four elements have one electron each in the valence shell of their atoms. They have, therefore, similar properties.

Question 11.
(a) What were the two major shortcomings of Mendeleev’s periodic table? How have these been removed in the modern periodic table?
Answer:
The shortcomings of Mendeleev’s periodic table are :

  • Isotopes of an element find different positions in periodic table.
  • Some chemically similar elements have been separated and some dissimilar elements are placed together.

In these Modern Periodic Table
Modern Table

  • Isotopes of an element occupy the same position because they have same atomic number.
  • The similar elements are grouped together and dissimilar elements are separated.

(b) Two elements X and Y have atomic numbers 12 and 16 respectively. Write the electronic configuration for these elements. To which period of the modern periodic table do these two elements belong? What type of bond will be formed between them and why?
Answer:

Element Electronic Configuration Period
X12 2, 8, 2 3rd
Y16 2, 8, 6 3rd

They will form ionic bonds because two electrons are transferred from X to Y so that they get their octets complete :
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 5

Question 12.
Why is Long Form of Periodic Table regarded better than Mendeleev’s Periodic Table?
Or
How could Modern Periodic Table remove various anomalies of Mendeleev’s Periodic Table?
Answer:
Long Form of Periodic Table is regarded better than the Mendeleev’s periodic table due to the following reasons:

  • It is based upon atomic number which is considered better than the atomic mass because the properties of the elements are related to the atomic number.
  • It explains why the elements placed in a group show similar properties but Mendeleev’s Periodic Table gives no explanation for the same.
  • All groups in the Periodic Table are independent groups and there are no sub¬groups as in Mendeleev’s Periodic Table.
  • Many defects in the Mendeleev’s Periodic Table have been removed.
  • There is no confusion regarding the position of isotopes because all the isotopes of an element have the same atomic number.
  • The periodic table is more systematic than the Mendeleev’s table and is easy to remember.

Question 13.
The following tables shows the position of six elements A, B, C, D, E and F in the periodic table.
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 6
Using the above table answer the following questions :
(a) Which element will form only covalent compounds?
Answer:
E

(b) Which element is a metal with valency 2?
Answer:
D

(c) Which element is non-metal with valency of 3?
Answer:
B

(d) Out of D and E, which one has a bigger atomic radius and why?
Answer:
D

(e) Write a common name for the family of elements C and F,
Answer:
The noble gases.

Question 14.
The question refers to the elements of the periodic table with atomic number from 3 to 18.
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 7
(a) Which of these :
(i) is/are noble gas?
Answer:
H, P

(ii) is it a halogen?
Answer:
G, O

(iii) is an alkali metal?
Answer:
A, I

(iv) is it a metal with valency 2?
Answer:
A, I

(b) Write the electronic arrangement of G.
Answer:
G has the electronic configuration = 2, 7

(c) If A combines with F, what would be the formula of resulting compound?
Answer:

Short Answer Type Questions

Question 1.
Atomic number is considered to be a more appropriate parameter than atomic mass classification of elements in a periodic table. Why?
How does atomic size of elements vary on moving from
(i) Left to right in a period.
(ii) from top to bottom in a group.
Give reasons for your answers.
Answer:

  • This is because atomic number is a more fundamental property of an atom.
  • As we move from left to right along a period atomic radius decreases due to increase in effective nuclear charge.
  • As we move from top to bottom in a group, atomic radius increases. This is due to addition of new electronic shells.

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 2.
Define periodic law. Why was it necessary to change the basis of classification from atomic masses to atomic numbers?
Answer:
Periodic Law: The properties of elements are a periodic function of their atomic numbers. It was necessary to change the basis of classification from atomic masses to atomic numbers because atomic number and not atomic mass is the fundamental property of an element.

Question 3.
What do you understand by the term periodicity? Do the properties of two elements placed in a group the same? Illustrate.
Answer:
The repetition of the similar properties of the elements placed in a group and separated by definite gaps of atomic numbers (8, 8, 18, 18, 32) is called periodicity. The elements placed in a group show similar properties, e.g. consider group 1 elements.

Element Symbol Electronic configuration
Lithium (3) Li – 2, 1
Sodium (11) Na – 2, 8, 1
Potassium (19) K – 2, 8, 8, 1
Rubidium (37) Rb – 2, 8, 18, 8, 1
Cesium (55) Cs – 2, 8, 18, 18, 1
Francium (87) Fr – 2, 8, 18, 32, 18, 8, 1

These elements show similar properties because they have similar outer electronic configurations.

Question 4.
What was wrong with Dobereiner’s classification of elements?
Answer:
Dobereiner classified the elements in group of three in such a way that the atomic mass of the middle element was the mean of the first and the third elements. But he could not find many triads of elements. Therefore, the classification was rejected.

Question 5.
What properties do ail elements in the same column of the periodic table as boron have in common?
Answer:
The elements of Boron family in the periodic table show

  • Tricovalency
  • Form trihalides
  • Form trioxides
  • React with halogens to form halides.

Question 6.
Indicate the atomic number of elements of period 3 of Modern periodic table :
(a) non-metals
Answer:
14, 15, 16, 17

(b) elements forming negative ions.
Answer:
15, 16, 17

(c) elements with high melting points.
Answer:
11, 12, 13, 14

(d) elements forming positive ions.
Mention the atomic number only.
Answer:
11, 12, 13

Question 7.
Define atomic radius. Give its units.
Answer:
Atomic radius. It may be defined as the distance between the centre of nucleus and the outermost shell of an isolated atom.

Also the atomic radius of a non-metallic element is defined as half the distance between the nuclei of two atoms bound by a single covalent bond.
Units = Å or pm (picometre)
e.g. atomic radius of hydrogen atom = 37 pm.

Question 8.
How does atomic radius vary down a group and along a period?
Answer:
Variation in a group. The atomic radius generally increases from top to bottom in a group due to the addition of a new shell.
Variation along a period. The atomic radius decreases on moving from left to right due to the increase in nuclear charge.

Question 9.
Write down the electronic configuration of elements with atomic numbers 2, 14, 17, 19. Indicate the group of the periodic table to which they belong.
Answer:
The information is being given in a tabular form.

Atomic number Electronic configuration K L M N Group
2 2 18
14 2, 8, 4 14
17 2, 8, 7 17
19 2, 8, 8, 1 1

Question 10.
Locate the following group in the periodic table :
(a) Alkali metals
Answer:
Alkali metals: Group 1 or IA

(b) Halogens
Answer:
Halogens: Group 17 or VIIA

(c) Alkaline earth metals
Answer:
Alkaline earth metals: Group 2 or IIA

(d) Noble gases.
Answer:
Noble gases: Group 18 or zero

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 11.
What properties do the elements in the same vertical column of the periodic table as fluorine have in common?
Answer:
These are :

  • They form diatomic molecules F2, Cl2, Br2 I2
  • They are non-metals.
  • They show a valency of one.

Question 12.
Write the chemical electronic configuration of nitrogen (N = 7) and phosphorous (P = 15).
Answer:
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 8

Question 13.
(i) Name the members of the alkaline earth family.
Answer:
The members of the alkaline earth family are :
Be, Mg, Ca, Sr, Ba, Ra.

(ii) To which group do they belong?
Answer:
They belong to group 2.

(iii) Which member is radioactive in nature?
Answer:
The radioactive member in them is Radium (Ra).

(iv) Which member is the least reactive?
Answer:
The least reactive member of the family is Beryllium (Be).

Question 14.
Why are the members of group 1 called alkali metals?
Answer:
The members of group 1 are called alkali metals because all of them are water soluble. They react with water to form soluble hydroxides. The soluble hydroxides of the metals are called alkalies.
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 9

Question 15.
An atom has the electronic configuration 2, 8, 7.
(a) What is the atomic number of this element?
Answer:
The atomic number of the element = Total number of electrons
= 2 + 8 + 7 = 17

(b) To which of the following elements would it be chemically similar? (atomic numbers are given) N (7), F (9), P (15), Ar (18).
Answer:
The electronic configurations of given atom and N, F, P and Ar are.

Atom Electronic configuration
K L M
2 8 7
N 2 5
F 2 7
P 2 8 5
Ar 2 8 8

Since F has same number of electrons in the outermost shell as the given atom. Hence, the given atom is chemically similar to F.

Question 16.
What physical and chemical properties of elements were used by Mendeleev in creating his periodic table? List two observations which posed a challenge to Mendeleev’s Periodic Law.
Answer:
He selected the compounds of the elements with oxygen and hydrogen. He gave a table based upon atomic weights of the elements.

Limitations of Mendeleev’s Classification

  • The position of hydrogen was uncertain.
  • The isotopes of elements were not given proper positions in the periodic table.

Question 17.
(a) What are amphoteric oxides? Choose the amphoteric oxides from amongst the following oxides :
Na2O, ZnO, Al2O3, CO2, HaO
Answer:
The oxides which can react both with acids as well as bases to produce salts and water.

(b) Why is it that non-metals do not displace hydrogen from dilute acids?
Answer:
This is because non-metals cannot lose electrons and cannot reduce H+ ions from acid to H2.

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 18.
What are noble gas elements? Why are they so called?
Answer:
Noble gas elements are the. elemehts present in group 18 of the periodic table which is also called zero group, It means that the valency of the elements is zero. Actually, whereas the first member helium has two electrons in its only shell, the atoms of the remaining elements (Neon, Argon, Krypton, Xenon and Radon) have eight electrons in their outermost shells. They do not have any tendency to combine with atoms of other elements. Hence, they show zero valency. These are also called noble gases because they do not take part in chemical combination.

Question 19.
How is metallic character of an element defined? How does the metallic character of the elements change in a group?
Answer:
The metallic character of an element may be expressed in terms of its tendency to lose electrons and to form positive ion.
M (Element) → M+ + e

In a group the metallic character increases’ downwards. For example, among the elements of group 2, Beryllium (Be) is the least metallic. At the same time, radium (Ra) which is the last element is maximum metallic in nature.

Question 20.
Why do the elements present in a group show similar chemical properties?
Answer:
The properties of the elements, particularly the chemical properties are related to valence shell electronic distribution. The elements with the same valence shell electronic distribution have the similar chemical properties. For example, the members, of alkaline earth metal family (Group 2) have two electrons in the valence shell of their atoms. They therefore, show similar chemical properties.

Question 21.
How does the reactivity of the metals vary in a group?
Answer:
In a group, containing metals, the reactivity increases down the group. For example, in the metals of group 1 (Alkali metals), Lithium reacts with water very slowly. Sodium is more reactive and potassium is. still more reactive than sodium.

Question 22.
Name the elements present in the second period. Give their electronic configuration.
Answer:
The second period of the Long Form of Periodic Table has eight elements. The first element is Lithium and the last element is Neon. The electronic configuration of the elements are given below:
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 10

Question 23.
Why do not the elements present in a period show same valency?
Answer:
The valency of the element is related to the number of electrons in the outermost energy shell of its atom. Since the elements present in a period have different number of valence electrons or outermost electrons, they show different valencies.

Question 24.
The metallic character of the elements in a period decreases from left to the right. Justify.
Answer:
In every period, as we move from left to right, the metallic character of the elements decreases gradually. This is shown with the elements present in the third period.
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 11

Question 25.
Give symbols for :
(a) a metal belonging to second group of the periodic table.
Answer:
The metal belonging to second group is calcium (Ca).

(b) a metal belonging to the third group of the periodic table.
Answer:
The metal belonging to third group is aluminium (Al).

(c) two non-metals belonging to the halogen family.
Answer:
The two non-metals of halogen family are fluorine (F) and chlorine (Cl).

Question 26.
Write electronic structures of:
(i) Potassium
(ii) Lithium
(iii) Fluorine.
Answer:
The electronic configurations of the atoms are given below :
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 12

Question 27.
Name two other elements which are in the same family as
(i) carbon
Answer:
Carbon belongs to the group 16. Two other elements are silicon (Si) and germanium (Ge).

(ii) fluorine
Answer:
Fluorine belongs to group 17. Two other elements are chlorine (Cl) and bromine (Br).

(iii) sodium.
Answer:
Sodium belongs to group 1. Two other elements are lithium (Li) and potassium (K).

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 28.
Carbon (atomic number 6) and silicon (atomic number 14) are elements in the same group of the periodic table. Give the electronic arrangements of the carbon and silicon atoms and state the groups in which these elements occur.
Answer:
The required information may be given in a tabular form as follows :

Element Atomic no. Electronic arrangement Group
Carbon (C) 6 2, 4 14
Silicon (Si) 14 2, 8, 4 14

Question 29.
Sodium and aluminium have atomic numbers of 11 and 13 respectively. They are separated by one element in the periodic table and have valencies of 1 and 3 respectively. Chlorine and potassium are also separated by one element in the periodic table (their atomic numbers are 17 and 19 respectively) and yet both have valency of one. Explain your answer.
Answer:
Sodium and aluminium: The electronic configurations of the elements are given below :
Sodium (Na) = 2, 8, 1
Aluminium (Al) = 2, 8, 3

The valency in this case is given by the number of valence electrons. Therefore, the valency of sodium is 1 and that of aluminium is 3.

Chlorine and potassium: The electronic configurations of the elements are given below :
Chlorine (Cl) = 2, 8, 7
Potassium (K) = 2, 8, 1

Question 30.
Give the atomic number and electronic distribution of:
(i) The third alkali metal
Answer:
Potassium (19) 2, 8, 8, 1

(ii) The second alkaline earth metal
Answer:
Magnesium (12) 2, 8, 2

(iii) The first halogen
Answer:
Fluorine (9) 2, 7

(iv) The second noble gas.
Answer:
Neon (10) 2, 8.

Question 31.
Observe the following elements in the Modern Periodic Table.
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 13
Name the elements A, B, C and D. Also indicate noble gas
Answer:
(A) Lithium
(B) Chlorine
(C) Neon
(D) Potassium C is a noble gas

Question 32.
Match the following :

(a) Fluorine (i) Metalloid
(b) Neon (ii) Halogen
(c) Sodium (iii) Noble gas
(d) Arsenic (iv) Alkali metal

Answer:

(a) Fluorine (ii) Halogen
(b) Neon (iii) Noble gas
(c) Sodium (iv) Alkali metal
(d) Arsenic (i) Metalloid

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 33.
How many electrons can be present in the valence shells of metal atoms and non-metal atoms?
Answer:
Metal atoms have 1, 2 or 3 electrons in their valence shells whereas non-metal atoms have 4 to 7 electrons in their valence shells.

Question 34.
How are the various groups of the Modern Periodic Table designated according to the IUPAC system and old system?
Answer:
The designations of various groups of the Modern periodic table are :
PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements 14

Question 35.
What are the uses of Modern Periodic Table?
Answer:

  • Systematic study of the elements. In the periodic table, the elements with similar properties are placed together in the same group. If we know the properties of one element of the group, the properties of other elements belonging to the same group can be predicted. Thus, there is no need to study the properties of all the elements.
  • Properties of an element can be predicted from the position of the element in the periodic table. For example, if the element belongs to group IA or IIA it is likely to be a reactive metal, and if it belongs to group VII A it is likely to be a reactive non-metal.
  • It has led to the discovery of many new elements.

Very Short Answer Type Questions

Question 1.
How many elements have been discovered so far?
Answer:
114.

Question 2.
How are elements classified?
Answer:
The elements have been classified on the basis of their properties.

Question 3.
Why are group IA elements called alkali metals?
Answer:
This is because all these elements are metals and their oxides and hydroxides give alkaline solutions in water.

Question 4.
What is the basis of Modern Periodic table?
Answer:
It is based upon Modern Periodic law.

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 5.
Name the family to which halogens belongs?
Answer:
Halogen family.

Question 6.
Name the second elements of group 14.
Answer:
Silicon.

Question 7.
How many valence electrons and present in halogen elements?
Answer:
Seven.

Question 8.
How many elements are present in 4th period?
Answer:
18.

Question 9.
How many electrons are present in Mg2+ ion?
Answer:
Ten.

Question 10.
Out of Na and Mg which was larger size?
Answer:
Na

Question 11.
What is the valency of nitrogen?
Answer:
Three.

Question 12.
Out of Na and K which is more reactive?
Answer:
Sodium (Na).

Question 13.
Name the group number of halogen family.
Answer:
Group 17 (or VII-A).

Question 14.
Name the last element of third period?
Answer:
Argon.

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 15.
What is Dobereiner’s Triad?
Answer:
A group of three elements having similar properties is called Dobereiner’s Triad.

Question 16.
A, B and constitute the Dobereiner s Traid. Atomic mass of A and C are 7 and 23 respectively. Calculate atomic mass of B.
Answer:
\(\frac{7+23}{2}=\frac{30}{2}\) = 15

Question 17.
Name the elements discovered after Mendeleev’s Periodic Table?
Answer:
Scandium (Se), Gallium (Ga), Germanium (Ge) etc.

Question 18.
Name the groups and periods in Mendeleev’s Periodic Table?
Answer:
8 groups and 7 periods.

Question 19.
How does atomic radii as we move from left along a period in the Periodic Table?
Answer:
It decreases.

Question 20.
An element has the electronic configuration 2, 8, 3. What is its group number in Modern Periodic Table?
Answer:
Group 13.

Question 21.
Give the basis of Dobereiner’s classification.
Answer:
Doberenier Triads.

Question 22.
Give the characteristics of Dobereiner’s Triads.
Answer:
The atomic mass of the central element is the average of masses of the other two elements.

Question 23.
What is the drawback of Doberenier’s Triads?
Answer:
All the known elements could be grouped into Triads.

Question 24.
There are three alements A, B and C. The atomic masses of A and C are 7 and 39. What is the atomic mass of B on the bais of Dobereiner’s Traids?
Answer:
Atomic mass of B = \(\frac{7+39}{2}\) = 23.

Question 25.
There are three elements X, Y, Z. Atomic masses of X and Z are 35.5 and 127. What will be atomic mass of Y on the basis of Dobereiner’s Traids?
Answer:
Atomic mass of Y
\(\frac{35.5+127}{2}=\frac{162.5}{2}\) = 81.25

Question 26.
Write Newland’s Law of Octaves for classification of elements.
Answer:
When the elements are arranged in order of increasing atomic masses, eighth elements has properties similar to the first element.

Question 27.
How many element were classified by Newland.
Answer:
Upto mass number 40.

Question 28.
Indicate the group number and period number of P in the modern Periodic Table.
Answer:
Group-15, Period-3.

Question 29.
An element has the electronic configuration 2, 8, 8, 2. Indicate its group and Period in the Modern Periodic Table.
Answer:
Group-12, Period-4.

Question 30.
An element M is in the group 13 of Modern Periodic Table write the formula of its oxide.
Answer:
M2O3.

Question 31.
Give the groups and periods in the Modern Periodic Table.
Answer:
Group-18, Periods-7.

Question 32.
Give the electronic configuration of 17Cl35. Also indicate its position in the Periodic Table.
Answer:
Electronic configuation of 17Cl35 = 2, 8, 7
Period number = 3
Group number =17. (VII A)

Question 33.
Give the name and electronic configuation of element with atomic number 9.
Answer:
Fluorine and it has the electronic configuation = 2, 7.

Question 34.
What is Modern Periodic Law?
Answer:
It states that the properties of the elements are the periodic functions of their atomic numbers.

Question 35.
Who gave Newland’s Law of Octaves.
Answer:
Newland.

Question 36.
Define Mendeleev’s periodic law.
Answer:
It states that the properties of the elements are the periodic functions of their atomic masses.

Question 37.
What is the basis of Mendeleev’s Modern Table?
Answer:
It is based upon Mendeleev periodic law and in this table the elements are arranged in order of increasing atomic masses.

Question 38.
How many groups are present in Mendeleev’s Period Table.
Answer:
Eight.

Question 39.
Name the next elements after P in Modern Periodic Table.
Answer:
Sulphur (S).

Question 40.
Give the group number of nitrogen and phosphorus.
Answer:
They belong to group number 15.

Question 41.
Out of Mg and Al which is more metallic?
Answer:
Mg.

Question 42.
Out of Be, Mg, Ca, Al which does not belong to same group?
Answer:
Al.

Question 43.
In which group noble gases are present?
Answer:
Group 18 or group zero.

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 44.
Na and S are present in the third period of Modern Periodic Table. Which is more metallic and why?
Answer:
Na is more metallic due to larger size than S.

Question 45.
What is metallic character?
Answer:
It is the tendency of an atom of the element to form positive ions by losing electrons.

Question 46.
What is the trend in metallic character on moving from left to right along a period?
Answer:
It decreases.

Multiple Choice Questions:

Question 1.
Who gave Law of octaves?
(A) Newland
(B) Dobereiner
(C) Mendeleef
(D) Lother Mayer.
Answer:
(A) Newland

Question 2.
In Mendeleef’s periodic table which element was discovered in the gap between Boron and Aluminium ?
(A) Na
(B) Ca
(C) Ga
(D) Ba.
Answer:
(C) Ga

Question 3.
According to Mendeleef’s periodic law, the elements are arranged in order of A increasing:
(A) Atomic numbers
(B) Decreasing atomic number
(C) Increasing atomic masses
(D) Decreasing atomic masses.
Answer:
(C) Increasing atomic masses

Question 4.
Which element occupied gap left in Mendeleers periodic table?
(A) Germanium
(B) chlorine
(C) Oxygen
(D) Silicon.
Answer:
(A) Germanium

Question 5.
An element has the electronic configuration 2, 8, 2. It is present in group:
(A) 2
(B) is
(C) 8
(D) 10.
Answer:
(A) 2

Question 6.
Which element shows metallic character?
(A) 2, 8, 2
(B) 2, 8, 4
(C) 2, 8, 8
(D) 2, 7.
Answer:
(A) 2, 8, 2

Question 7.
Which shell is largest shell?
(A) K
(B)L
(C) M
(D) N.
Answer:
(D) N

Fill in the blanks :

Question 1.
Out of Na and Mg, ______ has bigger size.
Answer:
Na.

Question 2.
Number of elements known in Mendeleefs periodic table were ______
Answer:
63.

Question 3.
Oxygen and sulphur belong to same ______
Answer:
group.

Question 4.
The elements of group 17 are called ______
Answer:
halogens.

PSEB 10th Class Science Important Questions Chapter 5 Periodic Classification of Elements

Question 5.
The valency of the members of noble gas family is ______
Answer:
zero.

Question 6.
The halogens belong to group ______
Answer:
17.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Punjab State Board PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life Important Questions and Answers.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Long Answer Type Questions

Question 1.
Describe the structure of the plant cell.
Answer:
A generalized plant cell consists of three distinct parts viz, cell wall, cell membrane or plasma membrane and protoplasm.
1. Cell wall. It is the outermost covering of a cell made up of a non-living substance called cellulose. Is is permeable. It provides shape, strength and protection to cell.

2. Cell membrane or Plasma membrane. It is thin, delicate and elastic protoplasmic covering lying internal to the cell wall. The plasma membrane controls the entrance and exit of molecules and ions.

3. Cytoplasm. It consists of a number of living and non-living structures. The living structures are called cytoplasmic organelles or cell organelles and include structures like endoplasmic reticulum, ribosomes, golgi apparatus, mitochondria, lysosomes, plastids, vacuoles etc.
(a) Plastids. Plastids are spherical or discoid bodies containing different types of pigments in them. They are of three types viz. chloroplasts, chromoplasts and leucoplasts. The chloroplasts contain a green pigment in them, called chlorophyll. They play a vital role in the process of photosynthesis. The chromoplasts contain pigments other than chlorophyll. They impart various colours to flowers and fruits. Leucoplasts are colourless plastids. They are concerned with the storage of starch.
(b) Mitochondria are power house of cell.
(c) Ribosomes are of 70 S type. They are site for protein synthesis.
(d) Endoplasmic reticulum is network of membranes.
(e) Vacuoles. These are fluid-filled bubble-like structures bounded by a membrane, called tonoplast. They are mostly found in plant cell. Vacuoles provide turgidity and rigidity to cell.

4. Nucleus. It is a dense spherical body bounded by a membrane, called nuclear membrane. Embedded within the nuclear sap are found a number of thread-like structures called chromosomes with genes on them. The nucleus controls the various metabolic activities of the cell.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 2.
Draw a well labelled diagram of ultrastructure of plant cell.
Answer:
Ultrastructure of plant cell
PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life 1

Question 3.
Describe the structure of nucleus. Write its functions.
Answer:
A true nucleus is present in all the eukaryotic cells except mammalian RBCs, sieve tube cells, tracheids and vessels. It directs life processes of cells. It is formed of four components:
(a) Nuclear membrane. It is a two-layered envelope around the nuclear sap. It is porous (with nuclear pores) and semipermeable membrane. Outer membrane is studded with ribosomes and may be continuous with RER. It regulates exchange of materials between nucleoplasm and cytoplasm.
PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life 2
(b) Nucleoplasm. It is a semifluid colloidal substance in which nucleoli and chromatin fibres are present.
(c) Nucleolus. It is dense, spherical, naked and darkly stained structure and is the site of formation and storehouse of rRNAs.
(d) Ovomatin fibres. These are long, fine and darkly stained threads which collectively form nuclear reticulum. During prophase of mitosis and meiosis, these condense to form a species-specific number of rods, called chromosomes. These are with genes which are chemically formed of DNA and act as units of heredity and variations.
Functions of the nucleus:
The nucleus performs the following important functions:

  • The nucleus controls all the cellular activities of the cell.
  • Tire nucleus plays an important role in transmission of hereditary characters from parents to offsprings.
  • The nucleus plays a vital role in cell division.

Question 4.
Write short notes on:
(a) Chloroplast
(b) Endoplasmic reticulum
(c) Golgi bodies
Answer:
Structure and functions of a chloroplast:
A chloroplast is formed of two membranes and two chambers, so resembles a mitochon-drion. Outer membrane is freely permeable while inner membrane is semi permeable. Inner chamber is filled with a denser and granular proteinaceous (about 50%) ground substance called stroma or matrix. It is site of dark reaction or CO2 fixation of photosynthesis and has a number of grana, 70 S ribosomes and DNA molecules (circular and naked).
1. Grana are site for light reactions of photosynthesis.
2. Function of Chloroplasts: These are sites of photosynthesis, so are called “kitchens of cell.”
PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life 3
(b) Endoplasmic reticulum
There are two forms of endoplasmic reticulum. They are the following:

  • Rough type (RER): Ribosomes are associated with rough endoplasmic reticulum.
  • Smooth type (SER): Golgi apparatuses are associated with smooth endoplasmic reticulum.

Components of ER
PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life 4
Functions of Rough and Smooth Endoplasmic reticulum

Functions of Endoplasmic Reticulum:

  1. The endoplasmic reticulum acts as secretory, storage, circulatory and nervous system of the cell. Its functions depend upon its location, nature and cell type.
  2. It provides an ultrastructural skeletal framework of the cell.
  3. ER provide channels for quick transport of materials.
  4. It provides surface for attachment of ribosomes.
  5. It provides materials, lipids and proteins for biogenesis of membranes.

Functions of Smooth Endoplasmic Reticulum:

  1. Detoxification of drugs and poison.
  2. Formation of visual pigment from Vitamin A in retinal cells.
  3. Synthesis of fats inside the cells of adipose tissue.
  4. Synthesis of steroids and hormones.

(c) Golgi complex or Golgi Apparatus:
The golgi complex is usually located near the cell nucleus and in animal cells it is frequently disposed around the centriole pair. It normally consists of numerous sets of membrane-bound, smooth surface cisternae. Each cisterna is flat, disc-shaped and curved like a shallow bowl.
PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life 5
It has lumen which is bounded by a single membrane. Each set of flattened disc-shaped cistemae forms a structure that resembles stack of plates, called a Golgi stack or dictyosome (as referred in the plants).

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 5.
Discuss the structure and function of mitochondrion.
Answer:
Structure. Mitochondria are ‘power house’ of cells. It has two mitochondrial membranes and two chambers. Outer mitochondrial membrane is smooth and porous while inner mitochondrial membrane is produced into finger-like processes called cristae to increase the surface area for the distribution of respiratory enzymes of electron transport chain.

Cristae are studded with regularly placed knob-like oxysomes which take part in energy releasing reactions. Inner chamber is filled with a granular matrix having respiratory enzymes. Matrix present in inner chamber also contains DNA, RNA and ribosomes.
PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life 6
Functions of mitochondria:

  1. These are called power houses or power plants or ATP mills as these are site of aerobic oxidation (cellular respiration) of glucose to produce energy-rich ATP molecules.
  2. They provide biological intermediates for the synthesis of various biomolecules such as fatty acids, amino acids, steroids etc.

Question 6.
Write a note on prokaryotic cell.
Answer:

  1. The prokaryotes have a single membrane.
  2. Cells which have respiratory enzymes associated with plasma membrane.
  3. Circular DNA without proteins, forming a single prochromosome called nucleoid and lying in direct contact with cytoplasm.
  4. They have 70 S ribosomes.
  5. They lack membrane-bound organelles and sap vacuoles.
  6. They do not show cyclosis, phagocytosis, pinocytosis and exocytosis.
  7. Cell division by fission or budding.
  8. Examples. Bacteria, Blue green algae and Mycoplasma.

Question 7.
Write a short note on eukaryotic cell.
Answer:

  1. The eukaryotic cells have double membrane and plasma membrane devoid of respiratory enzymes.
  2. These cells have linear DNA associated with proteins forming two to many chromosomes enclosed by a nuclear envelope. Thus proper well defined nucleus is present.
  3. There are present 80 S ribosomes.
  4. Many membrane-bound organelles such as mitochondria, chloroplasts, lysosomes etc., and sap vacuoles present.
  5. Form mitotic apparatus in cell division and undergo meiosis.
  6. They may show cyclosis, phagocytosis, pinocytosis and exocytosis.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 8.
Draw the ultrastructure of a typical animal cell.
Answer:
An animal cell has three functional regions. Plasma membrane, cytoplasm and nucleus.
PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life 7

Short Answer Type Questions

Question 1.
What is cell and cell theory?
Answer:
Cell. 1. Structural and functional unit of life is called cell.
2. A cell is mass of protoplasm formed of different types of inorganic and organic biomolecules and externally bounded by a thin and semipermeable plasma membrane.
Cell Theory. M.J. Schleiden and Theodore Schwann (1938-39) proposed cell theory. The cell theory can be stated as follows:
(a) The body of all living organisms is composed of cells. Cell is a unit of structure and function of life.
(b) New cells are formed from the pre-existing cells only (R. Virchow).
(c) The life is passed from one generation to the next generation through a single cell.

Question 2.
What is a prokaryotic cell?
Answer:
Prokaryotic cell, (pro = primitive, karyon = nucleus) It is characterized by an incipient nucleus called nucleoid formed of single and circular chromosome. It is formed of double-stranded DNA but not associated with histone proteins. It is not enclosed by nuclear membrane.

  • Membrane-bound cell organelles such as mitochondria, chloroplasts etc. are absent.
  • Examples: Bacteria, Blue-green algae, Mycoplasma etc.

Question 3.
What is a eukaryotic cell?
Answer:
A eukaryotic (eu = good; karyon = nucleus) cell has true nucleus which has two or more linear chromosomes lying in the nucleoplasm and is surrounded by a double and porous nuclear membrane. Membrane bound organelles present. 80 S Ribosomes present (S = Svedberg unit).

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 4.
Explain structural and functional organisation of unicellular and multicellular organism.
Answer:

  • Unicellular organism, in such organisms, a single cell carries out all life processes with the help of organelles. They are also called acellular organisms.
  • Multicellular organism. A multicellular organism is made up of large number of cells.
  • The cells are differentiated to share varied functions performed by unicellular organisms. Whatever the case may be, all multicellular organisms start their life from a single cell.
  • The multicellular organism represents itself in two forms – as an individual and as a member of assembly of cells.
  • Advantages of Multicellularity:
    • The division of labour in a multicellular organism increases the efficiency of the organism.
    • It promotes the chance of survival.

Question 5.
What do you mean by:
1. Organelle
2. Inclusions
Answer:
1. Organelle, it is a living structure of cell with a specific function.
2. Inclusions. The lifeless structures in a cell, which may or may not have a definite function are called inclusions. These are vacuoles, excretory products, starch grains etc.

Question 6.
Distinguish between cell wall and cell membrane.
Answer:
Differences between cell wall and cell membrane

Cell wall Cell membrane
1. It is present only in plant cells where it lies outside the cell membrane.

2. Dead in nature and permeable.

3. Composed of cellulose.

4. It is thick in nature.

1. It ocurs in animal cells and plant cells.

2. Living membrane and is semi-permeable.

3. Composed of lipids and proteins.

4. Comparatively very thin.

Question 7.
Name the two nucleic acids present in cell.
Answer:

  • DNA (Deoxyribose nucleic acid): It is the genetic material. It is passed on from parents to next generation, It regulates the functioning of cells.
  • RNA (Ribose nucleic acid): It is structural component of ribosome. It plays role in protein systhesis.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 8.
Why are mitochondria called “power house of cell”?
Answer:
Mitochondria are site of generation, transport and storage of ATP. Adenosine triphosphate (ATP) is the energy currency of the cell.

Question 9.
Explain lysosomes.
Answer:

  • Lysosomes. They are single membrane bound vescicular structures. They are present in cytoplasm of eukaryotic cells. They contain digestive enzymes.
  • They exist in four different forms thus exhibit polymorphism.
  • They are involved in autolysis and hence called as ‘suicidal bags.’

Question 10.
List the functions of vacuoles.
Answer:
Functions of vacuoles

  1. They act as storage sacs for solid or liquid contents of cell.
  2. They help the cell to remain turgid and rigid.
  3. Vacuoles play an important role in growth.
  4. In some freshwater unicellular organisms, specialised vacuoles play an important role in expelling excess water and some wastes from, cells. It is called osmoregulation.

Question 11.
What is centrosome? List two functions of centrosome.
Answer:
Centrosome: It consists of granule like two centrioles; surrounded by clear area of cytoplasm called centrosphere. It is present in animal cells only.
Functions of centrosome:

  • They help in spindle formation during cell divison in animal cell.
  • They act as basal bodies and give rise to motile structures, i.e. cilia and flagella.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 12.
Differentiate smooth endoplasmic reticulum (SLR) and rough endoplasmic reticulum (RER).
Answer:
Differences between SER and RER:

SER RER
1. It does not bear ribosomes over the surface of its membranes which are smooth.

2. It is engaged in the synthesis of glycogen, lipids and steroids.

3. It gives rise to sphaerosomes.

1. It possesses ribosomes attached to its membranes which are rough.

2. The reticulum takes part in the synthesis of proteins and enzymes.

3. It helps in the formation of lysosomes through golgi apparatus.

Question 13.
What are ribosomes? Write their kinds and chemical composition.
Answer:
Structure of Ribosome. The ribosomes are ribonucleoproteinic, obovate, spheroid without membrane structures. They are having two sub-units, one is larger sub-unit having dome-shaped structure and the other smaller sub-unit forming a cap-like structure. They are composed of ribosomal RNA (rRNA) and proteins.
Type of ribosomes:
1. 70 S ribosomes. They are present in both prokaryotic and eukaryotic cell.
2. 80 S ribosomes. They are present in eukaryotic cell.
PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life 8
Functions of ribosomes:
They are the site of protein synthesis as they contain enzymes involved in protein synthesis.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 14.
Write functions of cell wall.
Answer:
Functions of cell wall:

  1. It provides shape and rigidity to the cell
  2. It protects the protoplast.
  3. It permits cells of bacteria, fungi and plants to withstand very dilute external environment without bursting.
  4. It increases the size of cell by continuous absorption.
  5. It is involved in the movement of materials in and out of the cell.

Question 15.
Give the functions of plasma membrane.
Answer:
Functions of plasma membrane:

  1. It maintains individuality of cells.
  2. It provides shape to the cell.
  3. It keeps the cell contents in place and distinct from the environmental materials.
  4. It protects the cell from injury.
  5. It regulates the flow of material into and out of the cell. It allows only the selected substances to move across it.
  6. It forms organelles of cell.

Question 16.
Define the following:

  1. Cytoplasm
  2. Hyaloplasm
  3. Nucleoplasm.

Answer:

  1. Cytoplasm: The clear, translucent, colourless, viscous, fluid in which are present various cell inclusions and organelles is called cytoplasm.
  2. Hyaloplasm: The clear homogeneous ground substance of cytoplasm is termed hyaloplasm (cytoplasmic matrix).
  3. Nucleoplasm: Clear transparent homogeneous fluid inside the nucleus is called ucleoplasm.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 17.
State the differences between cilia and flagella.
Answer:
Differences between cilia and flagella:

Cilia Flagella
1. They are short hair-like structures with an average length of 5-10 mm.

2. They are present all over the surface of cell of the organism.

3. They are more in number usually 100 to a few thousand per cell.

4. They beat perpendicularly and simultaneously.

5. The cilia produce a sweeping or pendular stroke.

1. They are long, whip-like structures with an average length of 150 mm.

2. They are usually present on one end of cell.

3. They are less in number usually 1 or 2 per cell.

4. They beat freely.

5. The flagella produce undulatory motion.

Question 18.
State the differences between grana and stroma.
Answer:
Differences between grana and stroma:

Grana Stroma
1. It consists of flatfened sac-like structures which are piled up one above the other like stacks of coins.

2. They contain photosynthetic pigments on them.

3. They are made of lipoproteins.

1. It is matrix or ground substance of chloroplast in which different structures like grana and lamellae are embedded.

2. Pigments are absent.

3. It is composed of watery proteinaceous substance.

Question 19.
Write functions of cell wall.
Answer:
Function of cell wall:

  1. It protects the cell from mechanical damage and infection.
  2. It helps in cell-to-cell interaction.
  3. It acts as a barrier to unwanted molecules.
  4. It provides rigidity and mechanical support to the cells.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 20.
How will you examine cells of onion peel.
Answer:
Examination of Onion Feel

  1. Take out the onion peel from the inner side of the scale of the bulb.
  2. Put this transparent peel into water and cut a small piece.
  3. Stain it with safranin solution. It will make the nucleus more distinct.
  4. Put it on the slide and place it in glycerine.
  5. Observe under low power microscope, then change it to high power and study the following:

Observation:

  • Regular, rectangular-shaped cells are placed close to each other.
  • Cell has a prominent cell wall, cytoplasm and nucleus. The vacuole occupies the central position.

Question 21.
What are possible shapes of cells? Explain with simple sketches.
Answer:
Shapes of cells

  1. Shapes of the cells differ not only in different organisms but also in different parts of same organism. They may be oval, spherical, discoid, cuboidal, columnar, spindle-shaped etc.
  2. The shape of the cell is usually related with its function.
  3. Some other factors controlling the shape of cell are function, age, pressure, cell wall and internal or external skeleton.
  4. Amoeba and leucocytes go on changing their shapes to enable them to engulf the materials.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life 9

Question 22.
Differentiate between diffusion and osmosis
Answer:
Differences between diffusion and osmosis:

Diffusion Osmosis
1. Diffusion is the net downward movement of a given substance (ions, atoms or molecules, etc.) along the free energy gradient from the place of its higher concentration to an area of its lesser concentration.

2. The diffusion may occur in any medium and the diffusing particles may be solid, liquid or gas.

3. Presence of semipermeable membrane is not required.

Osmosis is a special type of diffusion of solvent molecules from low concentration of solution to higher concentration of solution when the two are separated by a semipermeable membrane.

2. The osmosis occurs in liquid medium and only the solvent molecules move from one place to another.

3. Presence of semi-permeable membrane in between the two solutions is required.

Question 23.
Which organelle is called as protein factory of the cell?
Answer:
Ribosomes provide space for the synthesis of proteins in the cell. Hence, they are called protein factories. It synthesises various proteins and enzymes for the cell. Haemoglobin is an example of a protein made by free ribosomes in the young red blood corpuscles.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 24.
Differentiate Ribosome and Lysosome.
Answer:
Differences between ribosome and lysosome:

Ribosome Lysosome
1. Ribosome is an oval to rounded granular structure which is not covered ever by any membrane.

2. It consists of two unequal nucieoprotein subunits.

3. It takes part in protein synthesis.

1. Lysosome is a rounded membrane lined vesicle containing number of hydrolytic enzymes.

2. It does not consists of nucieoprotein.

3. It takes part in digestion, scavenging and defence against pathogens.

Question 25.
What are plastids? Name its three types.
Answer:
Plastids. These are double membrane bound organelles found in plant cell. These are of three types:

  • Chromoplasts
  • Chloroplasts
  • Leucoplasts.

Question 26.
Write functions of plastids.
Answer:
Functions of plastids

  1. Chloroplasts are the site of photosynthesis so called as kitchen of the cell.
  2. Chromoplasts provide colour to flowers and fruits.
  3. Leucoplasts are site of storage of food.
  4. Granum is site of light reaction, while stroma is the site of dark reaction.

Question 27.
What are the functions of lysosomes?
Answer:
Functions of lysosomes:

  1. Take part in intracellular digestion of foreign particle.
  2. They provide energy during starvation.
  3. They help in defence against bacterial and viral infection.
  4. Lysosome removes cellular debris.

Question 28.
Name the various organelles of cell and mention the most important function of each.
Answer:
Names and functions of cellular organelles:

Name of cell organelle Function
1. Plasma membrane Protects the cell organelles and separates the contents of cell from external environment.
2. Cell wall (plant cell only) Provides strength and rigidity to the cell. It permits the bacterial and plant cells to withstand very dilute external medium without bursting.
3. Cytoplasm Contains machinery and metabolites for carrying out the instructions sent from nucleus.
4. Cytoplasmic matrix Contains raw materials and enzymes for metabolism.
5. Endoplasmic reticulum It is responsible for transportation of extracellular and intracellular chemical molecules. It is also the site for synthesis of various molecules.
6. Ribosomes These are sites for protein synthesis.
7. Golgi complex Complexing, packaging and dispatching various materials to various targets inside and outside the cells.
8. Mitochondria

 

Site for respiratory reactions and energy liberation in the form of ATP.

 

9. Lysosomes (animal cells only) Centrosome (animal cells only) Plastids (plants only).
Cilia and flagella.
Vacuoles.
Nucleus.
Helps in waste disposal system and autolysis. Forms spindle during cell division.
Responsible for photosynthesis.
Provide movement to cell.
Storage sacs for liquid and solid contents. Regulates growth and reproduction of cell.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 29.
Differentiate cytoplasm and nucleoplasm.
Answer:
Differences between cytoplasm and nucleoplasm

Cytoplasm Nucleoplasm
1. Part of protoplasm that lies outside 1. Part of protoplasm that lies inside the
2. It appears to be homogeneous semi-fluid jelly-like substance 2. It is transparent.
3. It contains number of inorganic substances forming clear true solution and organic substances lipids, protein and carbohydrates forming a polyphasic colloidal system. 3. Nucleoplasm is colloidal substance having similar composition to cytoplasm, but contains more of nucleo- tides.
4. Suspended in it are various organelles and inclusions. 4. Suspended in it is chromatin.

Question 30.
What will happen to a cell if its nucleus is removed?
Answer:
Cell will die with passage of time as nucleus is the controlling centre of all functions of cell.

Very Short Answer Type Questions

Question 1.
What is the structural and functional unit of life?
Answer:
Cell.

Question 2.
Name three functional regions of a cell.
Answer:

  • Plasma membrane
  • Nucleus
  • Cytoplasm.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 3.
Name the orgnelles present in the cells.
Answer:
Mitochondria, Ribosomes, Endoplasmic Reticulum, Golgi bodies, Centrosome, Lysosomes, Plastids.

Question 4.
Name the organelle present in plant cell only.
Answer:
Plastids.

Question 5.
What is the main component of nucleus?
Answer:
Chromatin network which takes up the shape of chromosomes at the time of cell division.

Question 6.
Give six examples of single celled organisms.
Answer:
Paramecium, Amoeba, Chlamydomonas, Euglena, Trypanosoma and Malarial parasite.

Question 7.
Who coined the term ‘Protoplasm’ for the fluid substance of cell?
Answer:
Purkinje (1839).

Question 8.
How it was made possible to observe the complex structures of cell?
Answer:
Discovery of electron microscope.

Question 9.
Name the organelle which takes part in protein synthesis.
Answer:
Ribosomes.

Question 10.
Which is the longest cell in plants.
Answer:
Sclerenchyma.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 11.
Name the smallest and largest cells.
Answer:

  • Smallest cell – Mycoplasma.
  • Largest cell-Ostrich egg.

Question 12.
Name the smallest and largest cell of human body.
Answer:

  • Smallest cell – of kidney.
  • Largest cell-neuron (nerve cell).

Question 13.
List the factors which denote size of cell.
Answer:

  1. Structure
  2. Location
  3. Function.

Question 14.
What are the two main components of protoplasm?
Answer:
Cytoplasm and nucleoplasm.

Question 15.
Which cell organelle is called suicidal bag?
Answer:
Lysosome.

Question 16.
What is the primary function of lysosome?
Answer:
A centre of intracellular digestion, so is called digestive bag.

Question 17.
Name the cell organelle responsible for protein synthesis.
Answer:
Ribosomes.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 18.
Expand DNA.
Answer:
Deoxyribose nucleic acid.

Question 19.
Expand RNA.
Answer:
Ribose nucleic acid.

Question 20.
Who examined thin slice of cork under microscope?
Answer:
Robert Hooke.

Question 21.
What is cork?
Answer:
Cork is obtained from the bark of a tree.

Question 22.
Who coined the term cell?
Answer:
Robert Hooke.

Question 23.
Who examined the living cells for first time?
Answer:
A.V. Leeuwenhoek.

Question 24.
What are unicelluar organisms?
Answer:
The organisms formed of single cell e.g. Amoeba.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 25.
What are multicellular organisms?
Answer:
The organisms formed of a large number of cells are termed as multicellular organisms e.g. human beings.

Question 26.
Write examples of multicellular organisms.
Answer:
Fungi, plants and animals.

Question 27.
Write two features of cells of onion peel.
Answer:
Presence of cell wall and large central vacuole.

Question 28.
What is the contribution of Robert Brown in cell biology?
Answer:
Discovered nucleus in the cells of orchid.

Question 29.
What are the two types of cells on the basis of nature of nucleus? *
Answer:
Prokaryotic and Eukaryotic cells.

Question 30.
Name any two prokaryotic cells.
Answer:

  • Bacterial cell
  • Blue-green algae

Question 31.
Who proposed the cell theory?
Answer:
M.J. Schleiden and Theodore Schwann.

Question 32.
What is cell theory?
Answer:
All plants and animals are made up of cells and cell is the structural and functional unit of life.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 33.
Give the contribution of Rudolf Virchow in the field of biology.
Answer:
He stated “omnis cellula e cellula” which means new cells are formed by the growth and division of pre-existing cells.

Question 34.
What is the number of cells present in an adult person?
Answer:
100 trillion (1014).

Question 35.
Which is the smallest measuring unit in the field of cell biology?
Answer:
Angstrom (A).

Question 36.
In which year electron microscope was invented?
Answer:
1940.

Question 37.
What is the nature of plasma membrane?
Answer:
It is formed of lipids and proteins.

Question 38.
Give the primary function of plasma membrane.
Answer:
It regulates exchange of materials between the cytoplasm and extracellular fluid.

Question 39.
Give one term for a semifluid ground substance present between plasma membrane and nucleus.
Answer:
Cytoplasm.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 40.
What is diffusion?
Answer:
Diffusion. The movement of substance from a region of higher concentration to a region of lower concentration is called diffusion.

Question 41.
What is the term for movement of water into and out of cell across a semipermeable membrane?
Answer:
Osmosis.

Question 42.
Define plasmolysis.
Answer:
Loss of water from a plant cell resulting in shrinkage or contraction of cell away from cell wall.

Question 43.
Give the common name of the mitochondria.
Answer:
Powerhouses or ATP mills.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 44.
Expand ATP.
Answer:
ATP. Adenosine triphosphate

Question 45.
Name two semi-autonomous cell organelles.
Answer:
Mitochondria and plastids.

Question 46.
Which type of enzymes are located inside the mitochondria?
Answer:
Respiratory enzymes.

Question 47.
Name the largest-sized cell organelle.
Answer:
Plastid (chloroplast).

Question 48.
Name three types of plastids.
Answer:
Leucoplasts, chloroplasts and chromoplasts.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 49.
Which cell organelle is called kitchen of cell and why?
Answer:
Chloroplast. It is site of photosynthesis in green plants. During this process plant prepare their own food by trapping solar energy and use COz and water as raw materials.

Question 50.
What are chromoplasts?
Answer:
These are coloured plastids with yellow, orange or red coloured plastids.

Question 51.
Write the chemical composition of cell wall.
Answer:
Cellulose.

Question 52.
What is the role of cell wall?
Answer:
Cell wall provide structural support to plant cell.

Question 53.
Which chemical is used to strain plant cell?
Answer:
Iodine, Safranin, methylene blue.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 54.
Give one major difference between SER and RER.
Answer:
SER is without ribosomes and is involved in lipid synthesis, while RER is with ribosome-studded cistemae and is involved in protein synthesis.

Question 55.
List two general functions of ER.
Answer:

  • ER acts as channels for transport of materials within the cell.
  • It also act as cytoskeleton.

Question 56.
Write one function of SER.
Answer:
Detoxification of many poisons and drugs.

Question 57.
Give the primary function of Golgi body.
Answer:
Cell secretion and acts as condensation membrane.

Question 58.
Which plastids are involved in storage of food?
Answer:
Leucoplasts.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 59.
What is the main difference between cell organelles and cell inclusions?
Answer:
Cell organelles are living structures of cytoplasm, while cell inclusions are non-living structures of cytoplasm.

Question 60.
Name the vacuolar membrane.
Answer:
Tonoplast.

Question 61.
Why is nucleus called director of cell?
Answer:
It controls and directs all the cellular activities.

Question 62.
Which organelle plays central role in cellular reproduction?
Answer:
Nucleus.

Question 63.
What is nature of nuclear membrane?
Answer:
It is two-layered, lipoproteinaceous, porous and semipermeable.

Question 64.
What is primary function of nuclear membrane?
Answer:
Regulates exchange of materials between nucleoplasm and cytoplasm.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 65.
What are the functional units of chromosomes?
Answer:
Genes.

Question 66.
What is the chemical nature of a chromosome?
Answer:
DNA and basic protein histones, so is called Deoxyribonucleoprotein (DNP).

Question 67.
Give the primary function of DNA of chromatin fibre.
Answer:
DNA acts as genetic material and helps in transmission of characters from par¬ents to offsprings.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 68.
What is the function of vacuole in plant cell?
Answer:
Vacuoles are full of cell sap and provide rigidity and turgidity to cell vacuoles, temporarily stores wastes.

Question 69.
Write functions of contractile vacuole in plant cell.
Answer:
Osmoregulation and expelling wastes from the cell.

Question 70.
Name the organelle which contains chlorophyll.
Answer:
Chloroplast.

Question 71.
What are two functions of plasma membrane?
Answer:

  • Provides shape to cell
  • Keeps intact the contents of cell.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 72.
What is osmosis?
Answer:
It is a special type of diffusion of solvent molecules from low concentration of solution to higher concentration solution separated by semipermeable membrane.

PSEB 10th Class Science Solutions Chapter 5 Periodic Classification of Elements

Punjab State Board PSEB 10th Class Science Book Solutions Chapter 5 Periodic Classification of Elements Textbook Exercise Questions and Answers.

PSEB Solutions for Class 10 Science Chapter 5 Periodic Classification of Elements

PSEB 10th Class Science Guide Periodic Classification of Elements Textbook Questions and Answers

Question 1.
Which of the following statements is not a correct statement about the trends when going from left to right across the periods of periodic table.
(а) The elements become less metallic in nature.
(b) The number of valence electrons increases.
(c) The atoms lose their electrons more easily.
(d) The oxides become more acidic.
Answer:
(c) The atoms lose their electrons more easily.

Question 2.
Element X forms a chloride with the formula XCl2, which is a solid with a high melting point. X would most likely be in the same group of the periodic table as :
(a) Na
(b) Mg
(c) Al
(d) Si
Answer:
(b) Mg

Question 3.
Which element has :
(а) two shells, both of which are completely filled with electrons?
Answer:
Neon

(b) the electronic configuration 2, 8, 2?
Answer:
Magnesium

(c) a total of three shells, with four electrons in its valence shell?
Answer:
Silicon

(d) a total of two shells, with three electrons in its valence shell?
Answer:
Boron

(e) twice as many electrons in its second shell as in its first shell?
Answer:
Carbon.

Question 4.
(a) What property do all elements in the same column of the periodic table as Boron have in common?
Answer:
All elements of this column have 3 electrons in their valence shell like Boron.

(b) What property do all elements in the same column of the periodic table as Fluorine have in common?
Answer:
All elements of this column have 7 electrons in their valence shell like fluorine.

Question 5.
An atom has electronic configuration 2, 8, 7.
(а) What is the atomic number of this element?
Answer:
17

(b) To which of the following element would it be chemically similar? (atomic numbers are given in parenthesis).
N (7), F (9), P (15), Ar (18).
Answer:
F (9) (2, 7)

Question 6.
The position of three elements A, B and C in the periodic table are as shown below :
PSEB 10th Class Science Solutions Chapter 5 Periodic Classification of Elements 1
(а) State whether A is a metal or non-metal.
Answer:
A is non-metal.

(b) State whether C is more reactive or less reactive than A.
Answer:
C is less reactive than A.

(c) Will C be larger or smaller in size than B.
Answer:
C has smaller size than B.

(d) Which type of ion, cation or anion, will be formed by element A?
Answer:
Anion, A-.

PSEB 10th Class Science Solutions Chapter 5 Periodic Classification of Elements

Question 7.
Nitrogen (atomic number 7) and phosphorus (atomic number 15) belong to group 15 of the periodic table. Write the electronic configurations of these two elements. Which of these will be more electronegative? Why?
Answer:

K L M
N7 has electronic configuration 2 5
P15 has electronic configuration 2 8 7

Nitrogen is more electronegative than Phosphorus due to smaller size.

Question 8.
How does the electronic configuration of an atom relate to its position in the Modern Periodic Table?
Answer:
By knowing the electronic configuration of an element, we can know its period number from the number of shells present in its atom and from number of electrons in the valence shell of its atoms we can know its group number, e.g. let us consider the case of sodium atom.

Atomic number of sodium = 11
Its electronic configuration = 2, 8, 1 (K) (L) (M)
∴ Number of shells = 3
∴ Sodium belongs to 3rd period.

Also sodium atom has one electron in its valence shell.
∴ It is present in first group.
∴ Sodium lies in the first group and third period of Modern Periodic Table.

Question 9.
In the Modern Periodic Table, calcium (atomic number 20) is surrounded by elements with atomic numbers 12,19, 21 and 38. Which of these have physical and chemical properties resembling calcium?
Answer:
Element with atomic numbers 12 and 38 because they have two electrons in their valence shells like calcium (2, 8, 8, 2).

Question 10.
Compare and contrast the arrangement of elements in Mendeleev’s Periodic table and the Modern Periodic table.
Answer:
Similarities :

  • In both the elements are arranged in groups and periods.
  • In both similar elements are placed in same group.
  • Both the classification make the study of elements simple and systematic.

Differences :

Mendeleev’s Periodic Table Modern Periodic Table
1. The elements are arranged in order of increasing mass numbers. 1. The elements are arranged in order of increasing atomic numbers.
2. It has 8 vertical columns called groups. 2. It contains eighteen vertical columns called groups.
3. Groups like group VIII ‘have been divided into sub groups A and B. 3. Each group is an independent group.
4. Inert gases are not included in this table. 4. Inert gases are included in this periodic table.

Science Guide for Class 10 PSEB Periodic Classification of Elements InText Questions and Answers

Question 1.
Did Dobereiner’s triads also exist in the columns of Newlands’ octaves? Compare and find out.
Answer:
Yes, Dobereiner’s triads also existed in columns of Newlands’ octaves. These are:

H Li Be
F Na Mg
Cl K Ca

Question 2.
What were the limitations of Dobereiner’s classification?
Answer:

  • Dobereiner could find only three triads from the elements known at that time.
  • It is applicable only to a few elements.

PSEB 10th Class Science Solutions Chapter 5 Periodic Classification of Elements

Question 3.
What were the limitations of Newlands’ law of octaves?
Answer:

  • It is applicable upto calcium only.
  • Sometimes two elements were put in the same slot.
  • After the discovery of noble gas, law of octave is not valid.

Question 4.
Use Mendeleev’s periodic table to predict the formulae for the oxides of following elements :
K, C, Al, Si, Ba.
Answer:
K2O, CO2, Al2O3, SiO2, BaO.

Question 5.
Besides Gallium, which other elements have since been discovered to fill the gaps left by Mendeleev in his periodic table? (any two)
Answer:
Scandium and Germanium.

Question 6.
What were the criteria used by Mendeleev in creating his periodic table?
Answer:

  • The formulae of hydrides and oxides formed by an element wrere treated as one of the basic properties of an element for its classification.
  • It is based upon Mendeleev’s periodic law which predicts that the properties of the elements are the periodic function of their atomic masses.

Question 7.
Why do you think the noble gases are placed in a separate group?
Answer:
These gases were discovered very late because they are very inert and placing them in a separate group, does not disturb the existing order put forward by Mendeleev.

Question 8.
How could Modern Periodic Table remove various anomalies of Mendeleev Periodic Table?
Answer:

  • Isotopes of an elements occupy same position in the periodic table due to same atomic number.
  • There is a logical separation of elements into subgroups.
  • It is based upon the fundamental property of an element i.e. atomic number.

Question 9.
Name two elements you would expect to show same kind of chemical reactivity as magnesium. What is the basis for your choice?
Answer:
Calcium and Strontium because they have same number of valence electrons.

Question 10.
Name :
(а) three elements that have only a single electron in their outermost shells.
Answer:
Lithium, Sodium and Potassium.

(b) two elements that have two electrons in their outermost shells.
Answer:
Magnesium, Calcium.

(c) three elements with filled outermost shells.
Answer:
Neon, Argon, Krypton.

Question 11.
(a) Lithium, Sodium, Potassium are all metals that react with water to liberate hydrogen gas. Is there any similarity in the atoms of these elements?
Answer:
One electron in their valence shells and are metals.

(b) Helium is an unreactive gas and neon is a gas of extremely low reactivity. What, if anything, do their atoms have in common?
Answer:
Eight electrons in their valence shells.

Question 12.
In the modern periodic table, of the first ten elements, which are metals?
Answer:
Lithium and Beryllium.

PSEB 10th Class Science Solutions Chapter 5 Periodic Classification of Elements

Question 13.
By considering their position in the periodic table, which one of the following elements would you expect to have the most metallic characteristics?
Ga Ge As Se Be.
Answer:
Gallium.

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Punjab State Board PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds Important Questions and Answers.

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Long Answer Type Questions

Question 1.
What is allotropy? Name the allotropes of carbon. Are they chemically same? Compare their physical properties.
Answer:
Allotropy: The phenomenon of existence of two or more different physical forms of the same chemical element, with same chemical properties is called allotropy.

Allotropes of carbon

  • Diamond
  • Graphite

Similarity in chemical composition:
If both the allotropes in equal amount are heated in air then both will release same amount of carbon dioxide and will not leave any residue. Therefore this proves that both are same in chemical composition.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 1

Comparison of Physical Properties

Property Diamond Graphite
1. Appearance Transparent Black, shiny
2. Hardness Very hard Soft, slippery/ smooth in touch
3. Heat conductivity Very less Medium conductor
4. Electric conductivity Bad conductor Good conductor
5. Density (kg/m3) 3 – 510 2 – 250
6. Purity Purest Less pure than diamond
7. Melting point 3500°C 3000°C
8. Uses/Applications Jewellery, drilling purpose Lubricants. Drycells, Electric Arcs, Pencils, Lead,

Question 2.
What is covalent bond? Write its properties.
Answer:
The chemical bond formed by sharing of electrons between atoms of same or different non-metal elements is known as covalent bond.

Properties of Covalent bond/bonds.

  • They hax e strong bonds within molecules but their inter molecular bond is weak.
  • They have low boiling points.
  • They have low melting points.
  • Their compounds are bad conductors of electricity.

Question 3.
(a) Why does carbon form largest number of compounds?
Answer:
This is due to its tetracovalency and catenation.

(b) Why are some of these called saturated and other unsaturated compounds?
Answer:
The compounds containing C – C single bond are called saturated compounds and the compound containing
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 2
bonds are called unsaturated compounds.

(c) Which of these two is more reactive?
Answer:
Unsaturated compounds are more reactive than saturated compounds.

(d) Write the names of the compounds
(i) CH3 – CH2 – Br
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 3

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 4
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 5

Question 4.
Write about nomenclature of carbon compounds.
Answer:
The names of compounds in a homologous series are based on the name of basic carbon chain modified by a prefix’ ‘phrase before’ or ‘suffix’ ‘phrase after’ indicating the nature of the functional group. For example, the names of various alcohols are methanol, ethanol, propanol and butanol.

Naming of carbon compound can be done by the following method :

  • Identify the number of carbon atoms in the compound. A compound having three carbon atoms will have the name propane.
  • In case a functional group is present, it is indicated in the name of the compound with either a ‘prefix’ or a ‘suffix’. Like chloro propane, bromo propane, propanal, propanone etc.
  • If the name of functional group is to be given on the basis of suffix, the name of the carbon chain is modified by deleting the final ‘e’ and adding the appropriate suffix. For example, a chain having three carbons with a Ketone group will be given name in the following manner.
    Propane-‘e’ = propan + ‘one’ = propanone.
  • If the carbon chain is unsaturated then the final ‘ane’ in the name of carbon chain is substituted by ‘ene’ or ‘yne’. For example, a three-carbon chain with a double bond would be called propene and if it has triple bond, it would be called propyne.

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 5.
Write down the chemical properties of carbon compounds.
Answer:
The main chemical properties of carbon compounds are :
1. Burning: Carbons in all its allotropic forms burns in the presence of oxygen and produces heat, light and C02, For example :
C + O2 → CO2 + heat and light
CH4 + 2O2 → CO2 + 2H2O + Heat and light
CH3CH2OH + 3O2 → 2CO2 + 3H2O + Heat and light.
Saturated hydrocarbons burn with a clear flame whereas unsaturated hydrocarbons burn with sooty yellow flame.

2. Oxidation: Carbon compounds can easily be oxidised by burning. Alkaline potassium permanganate or acidified potassium permanganate converts alcohols into acids.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 6

3. Addition reaction: Unsaturated hydrocarbons make saturated hydrocarbons by adding hydrogen to itself in the presence of catalysts like nickel and palladium. The reaction is commonly used in hydrogenation of vegetable oils using nickel catalyst.

Vegetable oils generally have long unsaturated carbon chain while animal fats have saturated carbon chains.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 7

4. Substitution reaction: Saturated hydrocarbons are fairly unreactive and are inert in the presence of most reagents. However, in the presence of sunlight, chlorine gets combined with hydrocarbons in a quick reaction. Chlorine replaces very quickly the hydrogen atoms in the chemical reaction one by one due to which number of products are usually formed with the higher homologous of alkanes.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 8

Question 6.
(a) What is an alcohol? Give two examples.
Answer:
Alcohol is a simple compound of carbon, hydrogen and oxygen. If one hydrogen atom is replaced by hydroxyl (-OH) group in alkene, alcohol is produced. General formula of alcohol is CnH2n+2

Examples :

  • In Methane (CH4) when hydrogen atom is replaced by hydroxyl (- OH) group, methanol (CH3OH) is formed.
  • Ethanol (C2H5OH) is produced with the help of ethane

(b) How is synthetic ethanol produced? Also write.
Answer:
Synthetic ethanol is prepared by reacting ethane with water in the presence of phosphoric acid (H3P04).
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 9
Properties of Ethanol :

  • It is a colourless liquid with specific colour.
  • Its boiling point is 351 K and melting point is 156 K.
  • It is soluble in water in any proportion.
  • It doesn’t show any reaction with litmus because it is neutral.
  • It burns with blue flame in air to produce carbon dioxide and water.
    C2H5OH + 3O2 → 2CO2 + 3H2O
  • It reacts with oxygen or potassium dichromate (K2Cr2O7) to produce ethanoic acid.
    C2H5OH + O2 → CH3COOH + H2O
  • It reacts with sodium metal.
    2C2H5OH + 2Na → 2C2H5ONa + H2
  • It reacts with acetic acid in the presence of concentrated H2SO4. When this mixture is heated and poured in ice cold solution of sodium carbonate, a sweet smell is produced.

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 10

Question 7.
Give important properties of monocarboxylic acids. Also give its uses.
Or
Give important properties of ethanoic acid (Acetic acid). Also give its uses.
Answer:
Important properties of monocarboxylic acid :
1. Ethanoic acid or acetic acid is colourless liquid and is soluble in water, 5-8% solution of acetic acid in water is called vinegar.

2. Pure ethanoic acid melts at 290 K and freezes during winter in cold climates and looks like ice. Hence it is called glacial acetic acid.

3. Esterification: When an acid is heated with an alcohol in the presence of cone. H2S04, an ester is produced. This is a slow reversible reaction and is called esterification.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 11
Esters are sweet-smelling substances.

4. Action with a base
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 12

5. Action with carbonates and bicarbonates
Ethanoic acid decomposes carbonates and bicarbonates producing salt, carbon dioxide and water.
2CH3COOH + Na2CO3 → 2CH3COONa + H2O + CO2
CH3COOH + NaHCO3 → CH3COONa + H2O + CO2

Uses of ethanoic acid :

  • It is used in the manufacture of dyes, perfumes and rayon.
  • It is used in the manufacture of plastics, rubber and silk industries.
  • It is used as a solvent.
  • It is used as a vinegar in cooking, as food dressing and for preparing pickles.
  • It is used for the manufacture of chemicals like acetone, acetic anhydride, etc.
  • It is used for making white lead [2PbCO3. Pb(OH)2]

Question 8.
Explain the following terms :
(i) Esterification
Answer:
Alcohols are treated with carboxylic acids in the presence of concentrated sulphuric acid to form ester and this process in known as esterification.

Method: Mix ethyl alcohol with acetic acid in a test tube. Few drops of concentrated sulphuric acid is added and test tube is heated mildly in hot tub of water. Instantaneously sweet smell of ester is diffused in whole room.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 13
It is an example of esterification. Ester is used in ice-cream, cold drinks, medicines, make up etc.

(ii) Saponification
Answer:
Saponification: Breaking down of fats is called saponification.

It is performed by heating vegetable or animal oils with 40% solution of caustic soda. Fats and base react to produce soap and glycerol.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 14
Concentrated common salt solution is added to crystallize soap from water. Soap floats on the surface of water, after cooling. Soap is extracted from water and desired colour and smell are added and is given desired shape.

(iii) Decarboxylation
Answer:
Decarboxylation: Methane is produced when sodium or potassium salt of ethanoic acid are heated with sodium hydroxide and calcium oxide in 3 : 1 ratio.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 15
It is a useful method to prepare methane. It is known as decarboxylation because one molecule of CO2 is removed.

(iv) Polymerization.
Answer:
Polymerization: When a large number of small molecules join together at a specific temperature and pressure to form a big molecule, this process is termed as polymerization. These small molecules are known as ‘monomer’ whereas big combined molecule is known as ‘polymer.’
For example. Molecules of ethene join together at 2000 atm pressure and 200°C to form polythene.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 16

Question 9.
Describe a method for the preparation of soap.
Answer:
Soaps are sodium or potassium salts of higher fatty acids. When the naturally occurring esters called fats or oils are heated with NaOH solution, they undergo hydrolysis to form sodium salt of higher fatty acid (called soap) and glycerol.

Manufacture of Soap. Soap can be made easily in the laboratory. Heat fat or oil with sodium hydroxide solution. After a few minutes, and constant stirring, the oil and water layers get mixed.

Add 5-10 g of common salt to it, stir the mixture and allow’ it to cool. On cooling, pale yellow a solid forms as a cake called soap.

The same principle is used for making soap in soap industry. Some other substances like perfumes, disinfectants and medicines are added to soap to give it desired characteristics.

Example :
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 17

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 10.
What do you understand by isomers? Explain it with an example.
Or
Write down the isomers of butane.
Answer:
Isomers. The compounds with same molecular formula but different structural formula are called isomers and the phenomenon is called isomerism. There is no change in the structure of methane, ethane, propane if the atoms of carbon and hydrogen are rearranged but in case of alkane molecule if number of carbon is more than three then more than one arrangement is possible.

In this one long carbon chain is formed and the others are branched. In case of butane the chain is linked with atleast three carbon atoms with other carbon atoms. This type of alkanes are termed as iso-alkane. In a chain having no branch, carbon atom cannot be linked with two carbon atoms. Alkanes of this type are called normal alkane (n-alkane).

Two Isomers of Butane:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 18

Isomers of Pentane
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 19

Short Answer Type Questions

Question 1.
Explain why carbon forms mostly covalent compounds?
Answer:
Carbon has four electrons in its outermost shell. In order to get stable electronic configuration, it has to lose or gain four electrons, but it is difficult to lose or gain four electrons from energy considerations. Hence, Carbon complete its octet by sharing its valence electrons with other atoms forming covatent bonds resulting in the formation of covalent compounds.

Question 2.
In order to form large amount of carbonic compounds which major elements are used other than hydrogen and oxygen?
Answer:
The number of carbonic compounds is very large which was not possible only with the help of hydrogen and oxygen. Along with these two elements some other elements like nitrogen, sulphur, oxygen, halogens (Cl, Br, I, F) etc. also combine and because of it the caybonic compounds have crossed the number of many million. These combine together on the basis of functional groups and make new compounds.

Question 3.
‘Carbon is a unique element’, why?
Answer:
Carbon is the only known element out of all other known elements, that has got capability to make long chains. Each long chain of carbon atoms provides such a simple base with which other atoms can join by various methods resulting in the composition of various compounds.

Carbon atoms can make long chains or rings in three ways because of having catenation property.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 20

Question 4.
Explain the structure of diamond and write why is it so hard?
Answer:
In diamond each carbon atom remains at the centre of regular tetrahedral and it remains bound with covalent bond to four carbon atoms which are situated at four corners of tetrahedral. Thus, all electrons of carbon are bound atoms and none is found in free state. So it forms a strong three-dimensional tetrahedral structure and because of it diamond is the hardest substance with very high density.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 21

Question 5.
What are the uses of diamond?
Answer:
Uses of Diamond

  • Diamond being the hardest substance is used for cutting other substances.
  • Diamond because of its shine and lustre is used for making ornaments.
  • It is used for drilling hard rocks.
  • Sharp-edged diamonds are used by eye surgeon in catract surgery.
  • Being extra ordinarly sensitive for heat radiations and having property to remove immediately harmful radiations. These are used in making absolute thermometers.

Question 6.
Why do diamonds glitter?
Answer:
Diamond is a transparent substance whose refractive index is very high. The rays of light passing through it get diverted much. According to its cut base edges light rays undergo total internal reflection. When these edges are polished, diamond glitters very beautifully.

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 7.
How are diamonds made naturally and artifically?
Answer:
Naturally, diamonds are made by carbon present at the depth of about 150 km, where pressure is 70,000 atm and the temperature is about 1500°C. These diamonds come up near the surface with special kimberlite rocks. Artifically, diamonds are made by heating graphite under high pressure in the presence of special catalysts.

Question 8.
Write the structure of graphite. Why is it so soft?
Answer:
Each carbon atom is bonded with three neighbouring carbon atoms with covalent bonds in graphite. They are always in the same plane giving hexagonal array. As compared to diamond, the distance between carbon atoms is more. The distance between upper and lower layers does not permit carbon atoms to make covalent bonds and because of this fourth electrons remains free. These layers can easily slide one upon the other and graphite attains the property of a lubricant. It is very soft and slippery.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 22

Question 9.
Why are diamonds used in jewellery? Give reasons.
Answer:
Refractive index of diamond is 2.45 which is the highest of all known substances, because of this, it shines brightly. Its critical angle is 24°, which is very less. This is why, the light rays passing through it deviates much. A small deviation in it causes beautiful spectrum of colours. When the bases of diamond are polished, it produces an astonishing brightness. That is why diamonds are used in making jewellery.

Question 10.
Why is graphite a good conductor of electricity?
Answer:
Each carbon atom of graphite is surrounded by three carbon atoms joined with covalent bond which makes hexagonal layers over each other. In these layers distance between the carbon atoms is more, that is why the possibility of fourth covalent bond between the carbon atoms of opposite layers is reduced. The fourth covalent electron is set free. The graphite has easy flow of electrons and it acts as a good conductor of electricity.

Question 11.
What are the uses of graphite?
Answer:
Uses of Graphite

  • It is good conductor of electricity so- it is used in making dry cells and electric arcs as electrods.
  • It is used in making pencils, black colour and black paint.
  • It has lubricant property so it is used in machines to keep them lubricating at high temperature.
  • It is used in making crucibles to boil some metals because of its high melting point.

Question 12.
Why are allotropes of carbon in form a molecule known as fullerenes?
Answer:
The allotropes of carbon in which 60 carbon atoms join to form a molecule are termed as fullerene. US architect Buckminster Fuller designed three dimensional domes which were supported by pentagonal and hexagonal structures.

Since fullerene molecules looked like these domes, that is why they are known as fullerene.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 23

Question 13.
Draw the electron dot structures of methane, ethane, ethene, butane.
Or
(i) Write molecular formula of butane.
(ii) Draw the structure of Propanal.
Answer:
Methane
Formula -CH4
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 24

Ethane
Formula -C2H6
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 25

Ethene
Formula -C2H4
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 26

Or
(i) Butane
Formula – C4H10
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 27

(ii) Propanal
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 28

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 14.
Write two tests of alcohol.
Answer:

  1. Ester test: When alcohol is heated with acetic acid, in the presence of sulphuric acid, sweet smelling ester is produced.
  2. Sodium test: Alcohol reacts with sodium metal and always produces hydrogen gas.

Question 15.
(a) What do you understand by homologous series? Explain with an example.
Answer:
Homologous series. A series of compounds in which the same functional group substitutes for hydrogen in a carbon chain is called a homologous series. Each successive member differ by (- CH2) group. All the members of a homologous series can be obtained by similar process.

General Formula : CnH2n+2
For example : Homologous series of alkane is as follows
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 29

(b) Write the first three homologous compounds of methane.
Answer:
Homologous Compounds of Methane
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 30

Question 16.
Define homologous series. What are its main properties?
Answer:
Homologous series. A series of compounds in which the same functional group substitutes for hydrogen in a carbon chain is called homologous series. In this series the adjacent members differ by (-CH2) group. Each member of a homologous series is called homolog.

Properties of Homologous Series :

  • All the members of a homologous series can be represented by a common formula.
  • Two successive members differ by one carbon atom and 2 hydrogen atoms.
  • All the members of a homologous series possess similar chemical properties.
  • There is a small difference between all the members of a homologous series.
  • There is always a difference of 14 a.m.u. in atomic mass of two adjacent homologous.

Question 17.
What are alkanes? Write the properties of its main members. What do we conclude from its properties?
Answer:
Alkanes. The hydrocarbons with structural/general formula CnH2n+2 are called alkanes. The members of this group form an homologous series. Hydrocarbons like methane, ethane, propane and butane form many carbonic compounds which are collectively known as alkane. In these compounds, the number of carbon and hydrogen atoms differ by (- CH2) for the next member of family.

Properties of Alkanes
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 31

Conclusions:

  • Physical properties of alkane are based on their mass.
  • First four members of alkane are in gasous state and alkanes having more than six carbon atoms are in liquid state.
  • Alkanes having high molecular mass are found in solid state.
  • Melting and boiling point of alkanes increase with increase in molecular mass.

Question 18.
What happens when hydrogen gas is passed through vegetable oils in the presence of nickel?
Answer:
Vegetables oils have double bond and polymerisation is possible. When nickel is used as catalyst, vegetable oil converts to vegetable ghee when hydrogen is passed through it because of hydrogenation. Vegetable ghee is solid like butter at room temperature.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 32

Question 19.
Write the chemical properties of ethanoic acid.
Answer:
Ethanoic acid reacts with some metals, metal carbonates, hydroxides and bicarbonates.
1. Action with sodium:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 33

2. Action with sodium hydroxide and potassium hydroxide:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 34

3. Action with carbonate and hydrogen carbonate :
It reacts with carbonates and hydrogen carbonate to form water, salt and carbon dioxide.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 35

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 20.
Which type of oils should be used for cooking? Why?
Answer:
Animal fats have saturated fatty acids, which are harmful for health, whereas oils have long unsaturated carbon chains which are not harmful. Hence unsaturated fatty acids oils are used for cooking.

Question 21.
Write the ill-effects of using alcohol.
Answer:

  • It is an addictive substance.
  • It affects the sensitivity of nervous system.
  • When a drunken person drives the vehicle he/she is not able to take the right decisions which leads to accident.

Question 22.
Why is consumption of methanol (CH3OH) very fatal?
Answer:
Even a very small amount of methanol can prove fatal. In liver, it oxides to form methanale, which vigorously react with cells of liver, by which protoplasm gets emanating and swells in the same manner as boiled egg. Consumption of methanol also lead to blindness.

Question 23.
Write the IUPAC names of ethyl alcohol and acetic acid. Write the name of products formed when ethyl alcohol and acetic acid react in the presence of concentrated sulphuric acid. Write its chemical reaction.
Answer:

Compounds IUPAC Names
1. Ethyl alcohol ethanol
2. Acetic acid ethanoic acid

Chemical reaction :
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 36

Question 24.
How will you prepare :
(a) ethyl alcohol from ethene
(b) acetic acid from ethyl alcohol?
Give reactions.
Answer:
(a) Ethene is heated with water in the presence of phosphoric acid to prepare ethyl alcohol
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 37
(b) Acetic acid is prepared by oxidation of ethyl alcohol
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 38

Question 25.
Write in brief the various industrial alcohols.
Answer:

  • Absolute alcohol: It is 100% pure ethanol. It is produced by fractional distillation of ethanol which is prepared by fermentation of carbohydrates.
  • Denatured alcohol: It is 95% ethanol and is used in industries. It is made poisonous by adding methanol, copper sulphate and pyridine, so as to make it unfit for drinking.
  • Power alcohol: It is mixture of Benzene and Ether in 20% Ethanol and 50% gasolene. It is used to save petroleum.
  • Alcoholic beverages: Alcohol is used as addictive drink. It is sold under various names like, rum, whisky, brandy, Jinn, etc.

Question 26.
Why is cleansing effect of soap not effective in hard water?
Answer:
Soaps are not effective in hard water for washing purposes because hard water has salts of calaium and magnesium. When soaps are dissolved in hard water, calcium and magnesium ions l’eact with water to form calcium and magnesium salts of fatty acids.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 39
That is why a large amount of soap gets wasted. Calcium and magnesium salts being insoluble in water make precipitates and they get attached with the clothes and cause hinderance to the cleaning action and the clothes are not cleaned properly.

Question 27.
Distinguish between soaps and detergents.
Answer:

Soaps Synthetic detergents
1. Soaps are sodium or potassium salts of higher fatty acids e.g. Sodium Stearate. 1. Synthetic detergents are Sodium alkyl Sulphates or Sodium alkyl benzene sulphates.
2. Soaps are prepared from vegetable oils or animal fats. 2. Synthetic detergents are prepared from the hydrocarbons obtained from petroleum.
3. Soaps have relatively weak cleansing action. 3. They have strong cleansing action.
4. Soaps form curdy white precipitates with calcium and magnesium salts present in hard water and hence, are not used in hard water. 4. Calcium and magnesium salts of detergents are soluble in water. Therefore no curdy white precipitates are obtained in hard water and hence synthetic detergents can be used even in hard water.
5. Soaps cannot be used in acidic medium as they are decomposed into carboxylic acids in acidic medium. 5. They can be used in acidic medium as they are the salts of strong acid and are not decomposed in acidic medium.
6. Soaps do not cause water pollution. 6. Synthetic detergents cause water pollution.
7. Soaps are biodegradable. 7. Some of the synthetic detergents are non biodegradable.

Question 28.
Write the formation of ethanol by fermentation process.
Answer:
Fermentation occurs in the presence of Bio-chemical catalysts at normal temperature by which sugar molecules convert into alcohol and carbon dioxide. These catalysts are known as enzymes, which means ‘yeast’ or ‘in the fermentation’.

Alcohol is formed by fermentation of sugar or starch. In a beaker, grape juice or glucose mixture is heated at 20° – 30°C in the presence of yeast. Sugar or starch molecules break into smaller molecules which produce carbon dioxide due to process of fermentation. This carbon dioxide is expelled out but air is not given inlet. A dilute mixture of ethanol is formed in water during fermentation. Ethanol is purified by distillation.

Chemical reaction :
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 40

Question 29.
Write the name of the reaction in which ethanoic acid and ethanol react together to form one product. Write the common name of the product.
Answer:
When ethanoic acid reacts with ethanol in the presence of concentrated sulphuric acid, ester is produced and this process is known as esterification.
CH3COOH + C2H5OH → CH3COOC2H5 + H2O

Question 30.
Observe the figure given below :
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 41
(i) Write the reaction taking place
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 42

(ii) What is this reaction called?
Answer:
Esterification

Question 31.
What is indicated in the figure given below and give use of it.
Answer:
The figure indicates formation of micelle. Micelles are used to remove oily dirt from clothes.
1 – Hydrophilic end
2 – Oil droplet.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 43

Question 32.
Show the bonds of Hydrogen, Oxygen and Nitrogen atoms respectively.
Answer:
1. Hydrogen: Two atoms of hydrogen by sharing of their electrons make hydrogen molecule (H2).
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 44

2. Oxygen: A double bond is made between two atoms of oxygen. Each atom of oxygen shares two electrons with other atom to form .an octet.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 45

3. Nitrogen: Each atom of nitrogen shares three electrons to form an octet.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 46

Question 33.
(i) Write molecular formula of Propane.
Answer:
C3H8

(ii) Write IUPAC name of
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 47
Answer:
Bromoethane.

Question 34.
What is detergent? Write the formation of synthetic detergents. Write its advantage.
Answer:
Materials used for cleaning purposes are known as detergents. Since long, soaps have been used as detergents but now-a-days synthetic detergents are more popular. The detergent molecule has two ends, one which is made of sulphate (-SO4) or sulphonate (SO3Na) group and it is hydrophilic by nature whereas other which is made of hydrocarbon is hydrophobic.

Synthetic detergent produces ample amount of lather even in hard water. These do not form insoluble salts of calcium or magnesium.

Question 35.
Which substances are used to produce synthetic detergents?
Answer:
Following substances are needed for production of synthetic detergents :

  • Long chained hydrocarbons obtained from petroleum and coal.
  • Concentrated sulphuric acid.
  • Sodium hydroxide.

Procedure: Hydrocarbons are treated with cone, sulphuric acid to get hydrocarbonic sulphuric acid. It is further reacted with NaOH which forms synthetic detergents. About 15 to 30% of the total weight of washing powder is detergent. Rest of the others are various chemicals which provide other qualities.

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 36.
What are the components of washing powder?
Answer:

  • Synthetic detergents (15 to 30%).
  • Sodium sulphate and sodium nitrate.
  • Sodium tri-poly phosphate or sodium carbonate.
  • Sodium perborate.

Very Short Answer Type Questions

Question 1.
Which element is present necessarily in the following items?
Food, clothes, medicines and hooks.
Answer:
Carbon.

Question 2.
On which element do all living processes depend?
Answer:
Carbon.

Question 3.
What percentage of carbon is present in minerals found under the crust of earth?
Answer:
0.02 %.

Question 4.
What percentage of CO2 is present in atmosphere?
Answer:
0.003%.

Question 5.
How many electrons are present in the outer shell of carbon?
Answer:
4.

Question 6.
Why does carbon need four electrons to gain or lose?
Answer:
To attain noble gas configuration.

Question 7.
How does carbon gain four electrons?
Answer:
By making C4 anion.

Question 8.
How does carbon lose four electrons?
Answer:
By making C4+ cation.

Question 9.
Which type of bond is shared by a pair of two hydrogen atoms?
Answer:
Single bond.

Question 10.
How is single bond between two atoms expressed?
Answer:
By single straight line.

Question 11.
What is the atomic number of nitrogen?
Answer:
7.

Question 12.
How many electrons are given by each atom of Nitrogen to complete the octet?
Answer:
3.

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 13.
Which gas is used as a fuel the most?
Answer:
Methane gas.

Question 14.
Methane is the main constituent gas of which two fuel gases?
Answer:
Biogas, C.N.G.

Question 15.
Write the full form of C.N.G.
Answer:
Compressed Natural Gas.

Question 16.
How is the structure of diamond?
Answer:
Strong three-dimensional structure.

Question 17.
How is the structure of graphite?
Answer:
Hexagonal.

Question 18.
Which of these two is a good conductor of electricity diamond or graphite?
Answer:
Graphite.

Question 19.
Which is the hardest substance?
Answer:
Diamond.

Question 20.
How does it feel by touching graphite?
Answer:
Soft and slippery.

Question 21.
Which element has the ability to form large number of compounds?
Answer:
Carbon.

Question 22.
Give names of two elements which are placed in the group of carbon and have same valency.
Answer:
Valency of carbon is 4. This group has silicon and germanium.

Question 23.
What is the simplest form of hydrocarbon?
Answer:
Methane (CH4).

Question 24.
In which types of bonds can carbon atoms join?
Answer:
Single, double, triple bond and ring-shaped.

Question 25.
Write the names of five elements which can make bond with carbon to form new compounds.
Answer:
Oxygen, Hydrogen, Nitrogen, Sulphur, Chlorine.

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 26.
Write the formula of Ethane.
Answer:
C2H6.

Question 27.
Write the structural formula of Ethane.
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 48

Question 28.
Give the next higher homo-logues of:
(i) C3H6
Answer:
C4H8

(ii) C6H8.
Answer:
C7H10.

Question 29.
Give the structure of ethanol.
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 49

Question 30.
Name the functional group in propanone.
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 50

Question 31.
Give the structure of simplest ketone.
Answer:
Simplest keton is acetone. It has the structure :
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 51

Question 32.
Give the name and structure of four carbon atoms in aldehyde.
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 52

Question 33.
Name the products obtained when ethanol undergoes complete combustion.
Answer:
Carbon dioxide (CO2) and Water (H2O).

Question 34.
Give the structural formula of ethanol.
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 53

Question 35.
Give the name and structure of functional group present in acetic acid (CH3COOH).
Answer:
Carboxyl group
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 54

Question 36.
Which of the following compounds belong to same homo-Iogous series?
C2H6O2, C2H6O2, C2H6, CH4O
Answer:
C2H6 O, (C2H5OH) And CH4O or (CH2OH).

Question 37.
Give the structural formula of an ester.
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 55

Question 38.
Give the names and structural formulas of acid and alcohol from which ethyl acetate is obtained.
Answer:
Acetic acid
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 56
and ethyl alcohol, CH3CH2OH

Question 39.
Give the electron-dot stucture of methane.
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 57

Question 40.
Define covalent bond.
Answer:
It is formed by mutual sharing of electron pair between two atoms.

Question 41.
Explain what covalent compounds do not conduct electric current?
Answer:
This is because there are neither free ions nor free electrons.

Question 42.
Name the bond formed between metal atom and non-metal atoms.
Answer:
Ionic or electro valent bond.

Question 43.
What are allotropes?
Answer:
When an element exists in two or more form having different physical pruperties but, some chemical properties, there forms are called allotropes.

Question 44.
Define catenation.
Answer:
It is the property due to which a large number of atoms of the same element get linked together through covalent bonds forming long straight chains, branched chains and rings of different sizes.

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 45.
Give two oxidising agents.
Answer:

  1. Acidified potassium permanganate.
  2. Acidified potassium dichromate.

Question 46.
Give the electron dot structure of ethane.
Answer:
Dot structure of ethane :
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 58

Question 47.
Give the structural formula of propane.
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 59

Question 48.
Give the electron dot structure of ethene.
Answer:
Dot structure of ethene.
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 60

Question 49.
Define functional group.
Answer:
It is an atom or group of atoms which when present in a molecule gives special properties to it. e.g. C2H5OH has the functional group, -OH (hydroxyl group).

Question 50.
If two organic compounds have some functional group, predict they have similar physical or chemical properties.
Answer:
Similar chemical properties.

Question 51.
Give the general formulae of alkanes, alkenes and alkynes.
Answer:
Alkanes: Cn H2n+2
Alkaenes: CnH2n
Alkynes: CnH2n-2, where n = No. if carbon atoms).

Question 52.
Give the structural formula of isomers of C4H10 (butane).
Answer:
Butane has two structural isomers :
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 61

Question 53.
Give the first four members of homologous series of alcohols.
Answer:
CH3OH, C2H5OH. C3H7OH, C4H5OH.

Question 54.
Define a Catalyst.
Answer:
It is a substance which can increase the rate of a reaction but remains unchanged in mass and composition at the end of reaction.

Question 55.
What happens when a piece of sodium metal is added to ethanol? Give chemical equation also.
Answer:
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 62

Question 56.
What happens when ethanol is heated with conc. H2SO4 at 443K?
Answer:
Ethanol undergoes acidic dehydration to give ethene
PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds 63

Question 57.
What is denatured spirit or alcohol?
Answer:
It is prepared by adding poisonous substance like methanol, acetone, pyridine or copper sulphate to ethanol. It is unfit for drinking purposes.

Question 58.
Give three uses of ethanoic acid.
Answer:

  1. In the manufacture of vineger
  2. In the manufacture white lead
  3. As a reagent in laboratory.

Question 59.
What is the atomic number of hydrogen?
Answer:
One.

Question 60.
Give the electronic configuration of carbon atom.
Answer:
(2, 4).

Question 61.
Give name of four carbon compounds.
Answer:
Methane, Chloroform, Ethanol and ethanoic acid.

Question 62.
Give two allotropic forms of carbon.
Answer:
Diamond and graphite.

Question 63.
Give the name of simplest ketone.
Answer:
Propanone (CH3 COCH3).

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 64.
Give the name of first member of homologous series of alkynes.
Answer:
Ethyne (C2H2).

Question 65.
Give the name and formula of acid present in vinegar.
Answer:
Ethanoic acid (CH3 COOH).

Multiple Choice Questions:

Question 1.
Ethanoic acid has the formula:
(A) C2H5OH
(B) CH3COCH3
(C) CH3COOH
(D) C2H5COOH.
Answer:
(C) CH3COOH

Question 2.
Carboxylic acids contain functional group:
(A) -CHO
(B) -CH2OH
(C) -COOH
(D) -OH.
Answer:
(C) -COOH

Question 3.
The general formula of the alkyne is:
(A) CnH2n-2
(B) CnH2n+2
(C) CnH2n
(D) CnH2n+2.
Answer:
(A) CnH2n-2

Question 4.
Propanone has the functional group :
(A) -OH
(B) -CHO
(C) C=O
(D) -COOH.
Answer:
(C) C=O

Question 5.
Vinegar contains acetic acid:
(A) 5-8%
(B) 15-20%
(C) 21-29%
(D) 30-40%.
Answer:
(A) 5-8%

Question 6.
The reaction of acetic acid with ethyl alcohol is called :
(A) Polymerisation
(B) Saponification
(C) Hydrogenation
(D) Esterification.
Answer:
(D) Esterification.

Fill in the Blanks :

Question 1.
The functional group present in ethyl alcohol is ___________
Answer:
The functional group present in ethyl alcohol is alcoholic group (-OH)

Question 2.
CH3—CH2—OH represents ___________
Answer:
Ethyl alcohol.

Question 3.
Two atoms of the same element combine to form a molecule. The bond between them is known as ___________ bond.
Answer:
Covalent.

PSEB 10th Class Science Important Questions Chapter 4 Carbon and its Compounds

Question 4.
In the formation of oxygen molecule, the oxygen atoms share ___________ electrons each.
Answer:
Two.

Question 5.
The number of single covalent bonds in the molecule of ammonia is ___________
Answer:
Three.

PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds

Punjab State Board PSEB 10th Class Science Book Solutions Chapter 4 Carbon and its Compounds Textbook Exercise Questions and Answers.

PSEB Solutions for Class 10 Science Chapter 4 Carbon and its Compounds

PSEB 10th Class Science Guide Carbon and its Compounds Textbook Questions and Answers

Question 1.
Ethane, with the molecular formula C2H6 has :
(a) 6 covalent bonds
(b) 7 covalent bonds
(c) 8 covalent bonds
(d) 9 covalent bonds.
Answer:
(b) 7 covalent bonds

Question 2.
Butanone is a four-carbon compound with the functional group :
(a) carboxylic acid
(b) aldehyde
(c) ketone
(d) alcohol.
Answer:
(c) ketone

Question 3.
While cooking, if the bottom of the vessel is getting blackened on the outside, it means that :
(а) the food is not cooked completely
(b) the fuel is not burning completely
(c) the fuel is wet
(d) the fuel is burning completely.
Answer:
(b) the fuel is not burning completely

Question 4.
Explain the nature of the covalent bond using the bond formation in CH3Cl.
Answer:
The formation of CH3Cl can be represented as :
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 1
Carbon forms single covalent bonds with three H- atoms and one Cl – atom by sharing one electron pair with each C-H bonds are non-polar. But C – Cl bond is polar because C and H leave almost same electronegativity whereas Cl has more electronegativity than carbon.

PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds

Question 5.
Draw the electron dot structures for :
(a) ethanoic acid
Answer:
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 2

(b) H2S
Answer:
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 3

(c) propanone
Answer:
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 4

(d) F2.
Answer:
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 5

Question 6.
What is an homologous series? Explain with an example.
Answer:
A series of compounds having similar structural formulae, same functional group and hence similar chemical properties is called a homologous series. In the homologous series any two adjacent members differ by CH2 unit in their molecular formulae.

For example homologous series of aldehydes (or alkanals) can be represented as :

H – CHO Methanal
CH3 – CHO Ethanal
CH3 – CH2 – CHO Propanal
CH3 – CH2 – CH2 – CHO Butanal
CH3 – CH2 – CH2 – CH2 – CHO Pentanal and so on.

Question 7.
How can ethanol and ethanoic acid be differentiated on the basis of their physical and chemical properties?
Answer:
Differences between ethanol and ethanoic acid

Ethanol Ethanoic acid
1. It is a colourless liquid having a pleasant smell. 1. It is colourless liquid having vineger like smell.
2. It has no action with a litmus solution. 2. It turns blue litmus solution red.
3. It has no action with sodium hydrogen carbonate solution. 3. It decomposes sodium hydrogen carbonate solution giving brisk effervescence of carbon dioxide gas.

Question 8.
Why does micelle formation take place when soap is added to water? Will a micelle be formed in other solvents such as ethanol also?
Answer:
Soap molecule has two ends, one is hydrophilic, and it dissolves in water, while the other end is hydrophobic, and it dissolves in hydrocarbons. When soap is at the surface of water , the hydrophobic ‘tail’ of soap will not be soluble in water and the soap will align along the surface of water with the ionic end in water and the hydrocarbon ‘tail’ pointing out of water.
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 6
Inside water, these molecules have a unique orientation which keeps the hydrocarbon portion out of the water. This is achieved due to the formation clusters of molecules in which the hydrophobic tails are in the interior of the cluster and the ionic ends are on the surface of the cluster. This formation is called a micelle.

Such micelles can be formed in other polar solvents like ethanol.

Question 9.
Why are carbon and its compounds used as fuels for most applications?
Answer:
Carbon and its compounds are used as fuels for most applications because they bum producing a large amount of heat and light.

PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds

Question 10.
Explain the formation of scum when hard water is treated with soap.
Answer:
When soap is added to hard water, the soluble calcium and magnesium salts present in it react with soap to give insoluble calcium salt of soap which produces scum.
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 7

Question 11.
What change will you observe if you test soap with litmus paper (red and blue)?
Answer:
Soap solution will turn red litmus paper blue because soap is alkaline in nature.

Question 12.
What is hydrogenation? What is its industrial application?
Answer:
The addition of hydrogen to unsaturated hydrocarbons in the presence of catalysts like palladium, platinum, nickel etc. to give saturated hydrocarbons is called hydrogenation.
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 8
This reaction is used for hydrogenation of liquid vegetable oils using a nickel catalyst to get artificial or vanaspati ghee.

Question 13.
Which of the following hydrocarbons undergo addition reaction : C2H6, C3H8, C3H6, C2H2 and CH4.
Answer:
Out of C2H6, C3H8, C3H6, C2H2 and CH4; C3H6 and C2H2 undergo addition reactions because they contain multiple bonds.

Question 14.
Give a test that can be used to differentiate chemically between butter and cooking oil.
Answer:
Distinction between Butter and Cooking oil:

Butter Cooking Oil
1. It is solid at room temperature. 1. It is liquid at room temperature.
2. Mix equal volumes of HgCl2 solution in 50% alcohol and 5% iodine solution in alcohol. To this add lg of butter. Violet colour does not fade away. 2. Mix equal volumes of HgCl2 solution in 50% alcohol and 5% solution of iodine in alcohol. To this add 1 ml of cooking oil. Violet colour fades away.
3. Take 2 g of butter in a test tube. To this add 1ml of cone. HCl and a few drops of 2% furfural solution in alcohol. Shake and allow to stand for 5 – 10 minutes. No rose red coloration appears. 3. Take 2 g of cooking oil in a test tube. To this add 1 ml of cone. HCl and a few drops of 2% .furfural solution in alcohol. Shake it and allow to stand for 5 – 10 minutes. Rose red coloration is obtained.

Question 15.
Explain the mechanism of the cleansing action of soaps.
Answer:
Mechanism of cleansing action of Soap:
Soaps are sodium or potassium salts of higher fatty acids e.g. sodium palmitate, C15H31COONa+, sodium stearate, C17H35COONa+ etc. A molecule of soap consists of two parts :

  1. a long chain hydrocarbon part (C15H31, C17H35 …. etc.) which is soluble in oil and
  2. ionic part on polar group, – COONa+ which is soluble in water. Thus a molecule of soap can be represented as :

PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 9
The long hydrocarbon chain is insoluble in water but soluble in oil and greases whereas the ionic or polar part is soluble in water. Soap has a capacity to clean a dirty piece of cloth whereas ordinary water cannot. The dirty clothes contain greasy and oily substance (dirt). Soap molecules dissociate in water to give carboxylate ion (RCOO) and cation (Na+). When soap added to dirty clothes dipped in water, the hydrocarbon part of carboxylate group dissolving in greasy or oily dirt particles where the polar (COO) group remain attached to water. In this way each oil droplet acquires negative charge.
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 10
The cleansing action of Soap

These negative charged oil droplets called micelles cannot coalesce and hence form a stable emulsion water. These small droplets along with dirt can be easily washed away with water. Thus the soap helps in removing greasy dirt by producing a stable oil in wrater type emulsion. Also the soap reduces surface tension of water. Hence cloth is wetted more effectively and is cleaned.

Science Guide for Class 10 PSEB Carbon and its Compounds InText Questions and Answers

Question 1.
What would be the electron-dot structure of carbon dioxide which has the formula CO2?
Answer:
In carbon dioxide, carbon atoms are bonded with two oxygen atoms. The atomic number of carbon is 6, and it has four electrons in the outer shell.

To make an octet it requires four electrons. Oxygen requires only two electrons in the outer shell. Therefore electron-dot structure will be :
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 11
Every oxygen atom is joined to carbon atom by double bond.

Question 2.
What would be the electron-dot structure of a molecule of sulphur which is made up of eight atoms of sulphur? (HINT. The eight atoms of sulphur are joined together in the form of ring.)
Answer:
The atomic number of sulphur is 16
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 12
Sulphur has 6 electrons in the outermost shell and to complete an octet it requires 2 electrons.
∴ Sulphur atom will share 2 electrons. It’s chemical formula is S8.
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 13

PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds

Question 3.
How many structural isomers can you draw for pentane?
Answer:
Three ; n-Pentane, iso-pentane, neo-pentane.
Structural isomers can be drawn for pentane.
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 14

Question 4.
What are the two properties of carbon which lead to the huge number of carbon compounds we see around us?
Answer:

  1. Catenation: The carbon atoms have an astonishing property to combine and form bond with other carbon atoms to form long chain compounds. This property is known as catenation. In this, either long chain of carbon are in ring form or the carbon atoms join in single, double or triple bond.
  2. Tetravalency: Carbon has four electrons in the outermost shell. That is why its valency is four and it has got capacity to make bonds with other elements. Oxygen, Hydrogen, Nitrogen, Sulphur, Chlorine and many other elements can make new compounds with the help of carbon.

Question 5.
What will be the formula and electron dot structure of cyclopentane?
Answer:
Molecular formula of cyclopentane = C5 H2 × 5 = C5H10
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 15

Question 6.
Draw the structures for following compounds :
Are structural isomers possible for bromopentane?
(i) Ethanoic acid
Answer:
Ethanoic acid (CH3COOH)
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 16

(ii) Bromopentane
Answer:
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 17
Due to exchange of position of carbon with bromine, many isomers of bromopentane are possible.
For example :
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 18

(iii) Butanone
Answer:
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 19

(iv) Hexanal.
Answer:
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 20

Question 7.
How would you name the following compounds?
(i) CH3 – CH2 – Br
Answer:
Bromoethane

PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 21
Answer:
Methanal

PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 22
Answer:
Hex-1-yne.

PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds

Question 8.
Why is the conversion of ethanol to ethanoic acid an oxidation reaction?
Answer:
This is because in this reaction oxygen gets added to ethanol.
PSEB 10th Class Science Solutions Chapter 4 Carbon and its Compounds 23

Question 9.
A mixture of oxygen and ethyne is burnt for welding. Can you tell why a mixture of ethyne and air is not used?
Answer:
A mixture of ethyne and air is not burnt for welding. This is because air also contains nitrogen along with oxygen. Nitrogen will also burn in oxygen producing oxides of nitrogen such as nitre oxide (NO) and nitrogen dioxide (NO2) which cause pollution.

Question 10.
How would you distinguish experimentally between an alcohol and a carboxylic acid?
Answer:
The following two tests are used :

  • Litmus test: Treat the given compound with blue litmus solutions. If the blue litmus solution turns red, it is a carboxylic acid and if does not turn red, it is an alcohol.
  • Sodium bicarbonate test: Add some sodium bicarbonate solution to the given compound. If their is a brisk evolution of a colourless and odourless gas (CO2) which turns freshly prepared lime water milk, it is carboxylic acid and if their is no effervescence, it is an alcohol.

Question 11.
What are oxidising agents?
Answer:

  • The substances which can oxidise other substances by giving oxygen are called oxidising agents.
  • Examples: Alkaline potassium permanganate solution, acidified potassium dichromate solution, etc.

Question 12.
Would you be able to check if water is hard using a detergent?
Answer:
No, we can’t check whether the water is hand or soft using a detergent.

Question 13.
People use a variety of methods to wash clothes. Usually after adding the soap, they ‘beat’ the clothes on a stone, or beat it with a paddle, scrub with a brush, or the mixture is agitated necessary to get clean clothes?
Answer:
This is because when soap molecules dissolve in the dirt, the dirt is somewhat loosened from the clothes, and in order to remove it from clothes, the clothes have to be beaten on a stone or beaten with a paddle or scrubbed with a brush or mixture has to be agitated in washing machines.

PSEB 9th Class Science Solutions Chapter 5 The Fundamental Unit of Life

Punjab State Board PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life Important Questions and Answers.

PSEB Solutions for Class 9 Science Chapter 5 The Fundamental Unit of Life

PSEB 9th Class Science Guide The Fundamental Unit of Life Textbook Questions and Answers

Question 1.
Make a comparison to write down ways in which plant cells are different from animal cell.
Answer:

Features Plant Cell Animal Cell
1. Cell wall Cell wall is formed of cellulose. Cell wall is absent.
2. Centrosome Absent. Present.
3. Vacuoles Large-sized and many present, small-sized. Generally absent but if only a few.
4. Plastids Present. Absent.
5. Reserve food In the form of starch and paramylon. In the form of glycogen
6. Nucleus Central. Acentric away from centre.

PSEB 9th Class Science Solutions Chapter 5 The Fundamental Unit of Life 1

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 2.
How is prokaryotic cell different from a eukaryotic cell?
Answer:
Differences between prokaryotic cell and eukaryotic cell

Prokaryotic cell Eukaryotic cell
1. Found in Bacteria, blue-green algae and , Mycoplasma.

2. Primitive nucleus called nucleoid present. Chromosome is single, circular and double-stranded DNA but no proteins (so naked), No nuclear membrane.

3. Cell wall when present, it is formed of peptidoglycan.

4. Membrane-bound Cell-organelles like mitochondria, plastids, E.R., golgi bodies etc. is absent.

5. Ribosomes are of 70 S type.

6. Small-sized (1 – 10 um).

7. Cell division by fission or budding.

  1.  Found in Protista, Fungi, Plantae and Animalia.

2. A true nucleus present. Chromosomes are two to man, linear and formed of DNA and histones. Nuclear membrane present.

3. Cell wall when present in plant cells it is formed of cellulose.

4. Membrane-bound Cell-organelles like mitochondria, plastids, E.R., golgi bodies etc. is present.

5. Ribosomes are of 80 S type.

6. Large-sized (5 – 100 /un).

7. Cell division bv mitosis and meiosis.

Question 3.
What would happen if a plasma membrane ruptures or breaks down?
Answer:
Plasma membrane maintains the shape and protects the organelles. If it gets ruptured the internal organisation will be lost and it will not be able to perform its function. Then cell wall die and contents of cell will get disintegrated.

Question 4.
What would happen to the life of a cell if there was no Golgi apparatus?
Answer:
1. The Golgi apparatus performs the function of storage, modification and packaging of materials synthesised in the cell. These materials will not be able to perform their function in its original form.
2. The formation of lysosomes will be affected.

Question 5.
Which organelle is known as the powerhouse of the cell? Why?
Answer:
Mitochondria are known as ‘power house’ of the cell. They are sites for synthesis, storage and transport of ATP (Adenosine triphosphate) commonly called energy currency.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 6.
Where do the lipids and proteins constituting the cell membrane get synthesised?
Answer:

  • Proteins are synthesised bv ribosomes.
  • SER is site for synthesis of lipid.
  • These proteins and lipids are modified by golgi apparatus to form plasma membrane.

Question 7.
How does an Amoeba obtain its food?
Answer:
Plasma membrane is flexible and it enables the cell to engulf in food and other materials from the external environment. Such a process is termed endocytosis.

Question 8.
What is osmosis?
Answer:
Osmosis. It is a special case of diffusion of water through a selectively permeable membrane. It is a passage of water from a region of higher concentration through a semi- permeable membrane to a region of low water concentration.

Question 9.
Carry out the following osmosis experiment:
Take four peeled potato halves and hollow each one out to make potato cups. One of these potato cups should be made from a boiled potato. Put each potato cup in a trough containing water. Now,
(a) keep cup A empty
(b) put one teaspoon sugar in cup B
(c) put one teaspoon salt in cup C
(d) put one teaspoon sugar in the boiled potato cup D.
Keep this setup for two hours. Then observe the four potato cups and answer the following.
1. Explain why water gathers in the hollowed portion of B and C.
2. Why is potato A necessary for this experiment?
3. Explain why water does not gather in the hollowed out portions of A and D?
Answer:
1. The water gathers in hollowed portion of potato cups B and C due to osmosis.
2. Cup A acts as control experiment and indicates that cavity of potato will not induce any type of movement.
3. Cup A does not contain hypertonic solution hence water does not rise. In cup D, cells of potato cup being boiled cells are dead and no osmosis occurs.

Science Guide for Class 9 PSEB The Fundamental Unit of Life InText Questions and Answers

Question 1.
Who discovered cell and how?
Answer:
Robert Hooke (1665) discovered cell for the first time. He examined a thin slice of cork under the microscope. He observed that cork resembled the structure of a honey comb consisting of many hexagonal compartments and called these boxes ‘cells’.

Question 2.
Why is cell called the structural and functional unit of life?
Answer:

  1. Cells are arranged in proper and systematic order to form a body of living organism. Thus cells serve as basic building structural units for more complex organisms.
  2. Cell is also functional unit of life because all the metabolic activities of life take place at cell level.
  3. Respiration, digestion, excretion and reproduction occur at cell level.
  4. Cells contain genetic material which regulate cell functions and pass on all information to the next generation.

Question 3.
How do substances like C02 and water move in and out of the cell? Discuss.
Answer:
The substances like C02 and water move in and out of cell by the process of diffusion. There is spontaneous movement of substances from higher concentration to lower concentration. The movement of water across selectively permeable membrane is called osmosis.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 4.
Why is the plasma membrane called selectively permeable membrane?
Answer
Plasma membrane permits the entry and exit of selected materials in and out of the cell. It also prevents movement of some materials required within the cell. The membrane is called selectively permeable membrane.

Question 5.
Fill in the gaps in the following table illustrating differences between prokaryotic and eukaryotic cells.

Prokaryotic Cell Eukaryotic Cell
1. Size: generally small (1 – 10 µm) = 10-6m

2. Nuclear region ……………. and known as ………………..

3. Chromosome single.

4. Membrane-bound cell organelles absent.

1. Size: generally large 5 – 100 µm

2. Nuclear region well defined and surrounded by a nuclear membrane.

3. More than one.

4. ………………………………………………..

Answer:
2. Nuclear region undefined due to absence of nuclear membrane and known as Nucleoid.
4. Membrane-bound cell organelles such as mitochondria, Golgi bodies, chloroplast, etc. are present.

Question 6.
Can you name two organelles we have studied that contain their own genetic material?
Answer:

  • Chloroplasts
  • Mitochondria.

Question 7.
If the organization of the cell is destroyed due to some physical or chemical influence, what will happen?
Answer:
Each cell has certain special cell organelles. Each performs a special function. If an organization is destroyed cell will stop performing basic functions and result in its death.

PSEB 9th Class Science Important Questions Chapter 5 The Fundamental Unit of Life

Question 8.
Why are lysosomes called ‘suicidal bags’?
Answer:
Lysosomes are membrane-bound sacs filled with enzymes and this enzyme may digest their own contents if burst. They carry out autolysis (auto = self; lysis = break down) hence called “suicidal bags.”

Question 9.
Where are proteins synthesized inside the cell?
Answer:
Proteins are synthesized on the ribosomes which are attached to the surface of RER or lie freely in the cytoplasm. Ribosomes are also called “protein factories” of cells.

PSEB 10th Class Science Solutions Chapter 6 Life Processes

Punjab State Board PSEB 10th Class Science Book Solutions Chapter 6 Life Processes Textbook Exercise Questions and Answers.

PSEB Solutions for Class 10 Science Chapter 6 Life Processes

PSEB 10th Class Science Guide Life Processes Textbook Questions and Answers

Question 1.
The kidneys in human beings are a part of the system for :
(a) nutrition
(b) respiration
(c) excretion
(d) transportation.
Answer:
(c) excretion.

Question 2.
The xylem in plants are responsible for :
(a) transport of water
(b) transport of food
(c) transport of amino acids
(d) transport of oxygen.
Answer:
(a) transport of water.

Question 3.
The autotrophic mode of nutrition requires :
(a) CO2 and water
(b) Chlorophyll
(c) Sunlight
(d) All of the above.
Answer:
(d) All of above.

Question 4.
The breakdown of pyruvate to give CO2, water and energy takes place in :
(a) cytoplasm
(b) mitochondria
(c) chloroplast
(d) nucleus
Answer:
(b) mitochondria.

Question 5.
How are fats digested in our bodies? Where does the process take place?
Answer:
Digestion of fats takes place in the intestine. The fats are emulsified by the bile salts present in bile. The emulsified fats are acted upon by pancreatic lipase (strepsin) which hydrolyses fats into fatty acids and glycerol. The intestinal lipase also hydrolyses the emulsified fats into fatty acids and glycerol.
PSEB 10th Class Science Solutions Chapter 6 Life Processes 1

Question 6.
What is the role of saliva in the digestion of food?
Answer:
Role of saliva

  • Saliva lubricates the food and facilitates mastication.
  • Saliva binds the food molecules together.
  • Saliva contains ptyalin (salivary amylase) enzyme which acts on starch, glycogen and other carbohydrates to form maltose.

PSEB 10th Class Science Solutions Chapter 6 Life Processes

Question 7.
What are the necessary conditions for autotrophic nutrition and what are its byproducts?
Answer:
Photosynthesis is essential in case of autotrophic nutrition
PSEB 10th Class Science Solutions Chapter 6 Life Processes 2

Conditions required for photosynthesis

  • CO2 is necessary for photosynthesis.
  • Water is required.
  • Sunlight is necessary for photosynthesis.
  • Chlorophyll is essential for photosynthesis.
  • By-products. Molecular oxygen is liberated as a byproduct.

Question 8.
What are the differences between aerobic respiration and anaerobic respiration? Name some organisms that use anaerobic mode of respiration.
Answer:
(a) Differences between aerobic and anaerobic respiration

Aerobic respiration Anaerobic respiration
1. It takes place in the presence of oxygen. 1. It takes place in the absence of oxygen.
2. It is completed in cytoplasm and mitochondria of cells. 2. It is completed in the cytoplasm only.
3. It involves the complete oxidation of glucose into CO2 and H2O and a large amount of energy is released. 3. It involves the incomplete oxidation of glucose into CO2 and alcohol or lactic acid and less amount of energy is released.
4. The process is harmless. 4. It is toxic to plants.

(b) Anaerobic respiration takes place in bacteria and yeast.

Question 9.
How are alveoli designed to maximise the exchange of gases?
Answer:

Question 10.
What would be the consequences of a deficiency of haemoglobin in our bodies?
Answer:
Haemoglobin is a respiratory pigment present in RBC of blood. It has high affinity for oxygen. One molecule of haemoglobin carries 4 molecules of oxygen. If simple diffusion were to move oxygen in our body, it is estimated that it would take 3 years for a molecule of oxygen to reach tip of toes from lungs.

Question 11.
Describe double circulation in human beings. Why is it necessary?
Answer:
Double circulation. In human beings heart is four-chambered, having right and left auricles and right and left ventricles. The right auricle receives the deoxygenated blood from the body and sends it into the right ventricle that pumps it to the lungs via a pulmonary arch for oxygenation. The left auricle receives oxygenated blood from the lungs and sends it into the left ventricle, which pumps it to the body through a single aortic arch.

Significance:

  • Thus, the deoxygenated and oxygenated blood remain fully separate, and there is complete double circulation.
  • It increases efficiency.

PSEB 10th Class Science Solutions Chapter 6 Life Processes 3
Double circulation of blood in birds and mammals.

Question 12.
What are the differences between the transport of materials in xylem and phloem?
Answer:
Differences between transport in xylem and phloem

Transport in xylem Transport in phloem
1. Water and minerals are transported through xylem. 1. Sucrose, amino acids and other substances are transported through phloem.
2. Xylem helps in upward movement, i.e. from roots to stem, branches and leaves. 2. Phloem is responsible for downward and lateral movement from leaves to other parts.

Question 13.
Compare the functioning of alveoli in the lungs and nephrons in the kidneys with respect to their structure and functioning.
Answer:

  • Alveoli of lungs remove CO2 as a waste during exchange of gases and nephrons filter wastes from blood.
  • Alveoli are supplied with extensive network of blood capillaries for gaseous exchange. Bowman’s capsule surrounds a cluster of capillaries for filtration.
  • Both increases surface area either for gaseous exchange or filtration.
  • Urea and uric acid wastes are removed in the nephron.
  • Both purify blood lungs alveoli by removing waste gases and nephrons by filtering the waste products in the form of urine.

Science Guide for Class 10 PSEB Life Processes InText Questions and Answers

Question 1.
Why is diffusion insufficient to meet the energy requirements of multicellular organisms like humans?
Answer:
In multicellular organisms, all the cells of body may not be in direct contact with the surrounding source of oxygen i.e. environment, thus simple diffusion will not meet the oxygen requirements of all the cells. These organisms require specialised organs to meet the oxygen requirement.

PSEB 10th Class Science Solutions Chapter 6 Life Processes

Question 2.
What criteria do we use to decide whether something is alive?
Answer:
Features of living organisms

  • Movements
  • Growth
  • Metabolism
  • Cellular body
  • Nutrition
  • Respiration
  • Transportation
  • Excretion
  • Respond to stimuli
  • Reproduction.

Question 3.
What are outside raw materials used by living organism?
Answer:
Outside raw materials used by living organism

  • Energy obtained from food.
  • Oxygen: Required for breaking down of carbon based molecules to liberate energy in the body.
  • Water: It is required for proper digestion of food and other functions in the body. It is raw material for photosynthesis in plants. All reactions occur in solution form in the body.
  • CO2 Raw material for photosynthesis in plants. All reactions occur in solution form in the body.

Question 4.
What processes would you consider essential for maintaining life?
Answer:

  • Nutrition
  • Respiration
  • Transportation
  • Excretion.

Question 5.
What are the differences between autotrophic and heterotrophic nutrition?
Answer:
Differences between Autotrophic and Heterotrophic nutrition

Autotrophic Nutrition Heterotrophic Nutrition
1. It occurs in green plants and blue green algae. 1. It occurs in animals and insectivorous plants.
2. CO2 and water are raw materials which combine to form organic compound. 2. They depend on plants and herbivore for their food.
3. They need chlorophyll and sunlight 3. There is no need of chlorophyll and sunlight,

Question 6.
Where do the plants get each of raw materials required for photosynthesis? (PB. Board 2011)
Answer:
Raw materials of photosynthesis

  • CO2
  • Water.
  • Nitrogen
  1. CO2 is obtained from air. It enters the leaf through stomatal openings.
  2. Water is obtained from soil. It enters the leaf through the mid-rib and vein from the root which absorbs it from the soil.
  3. Nitrogen: It is obtained from soil.

Question 7.
What is the role of acid in our stomach?
Answer:
HCl is obtained from gastric glands present in the wall of the stomach.

Functions of HCl:

  • It provides acidic medium. It is required for the action of enzymes. It changes the pH of food from almost neutral to acidic medium (from pH 7 to 2)
  • Activates the inactive proenzyme propepsin into active pepsin.
  • Kills the bacteria present in food.
  • It softens calcium.
  • It regulates the opening and closing of the pyloric aperture.

Question 8.
What is the function of digestive enzymes?
Answer:
Role of digestive enzymes: These enzymes convert the complex non-diffusible form of food into simple diffusible form.

  • Ptyalin converts starch into maltose.
  • Pepsin breaks down proteins into peptides and amino acids.
  • Rennin curdles milk protiens so that they can stay for longer period to be acted upon by pepsin.
  • Lipase acts on fats and forms fatty acid and glycerol.
  • Maltase acts on maltose and forms glucose.

Question 9.
How is small intestine designed to absorb digested food?
Answer:
Small intestine is a long tubular structure. The inner wall of small intestine is thrown into folds called villi. The absorptive cells have numerous finger-like processes called microvilli. They increase the surface area for absorption of food. These villi have blood vessels named lacteals from absorption of food.

Question 10.
What advantage over an aquatic organism does a terrestrial organism have with regard to obtaining oxygen for respiration?
Answer:
The amount of oxygen dissolved in water is very low as compared to the amount of oxygen in air. Thus these organisms have to make less efforts to obtain oxygen.

PSEB 10th Class Science Solutions Chapter 6 Life Processes

Question 11.
What are the different ways in which glucose is oxidised to provide energy in various organisms?
Answer:
Different pathways to provide energy from glucose
PSEB 10th Class Science Solutions Chapter 6 Life Processes 4

Question 12.
How is oxygen and CO2 transported in human beings?
Answer:
1. Transport of oxygen: It is transported from respiratory organs to body cells,
1. Haemoglobin helps in the transport of oxygen. In the alveoli of the lungs, the haemoglobin (Hb) present in red blood corpuscles combines with oxygen to form oxyhaemoglobin. When the blood reaches the tissue, oxygen is released from the oxyhaemoglobin for the consumption by the tissues.
Hb + O2 → HbO2
PSEB 10th Class Science Solutions Chapter 6 Life Processes 5

2. Some of O2 is transported in the solution form by plasma of blood.

2. Transport of CO2

  • CO2 diffuses into blood plasma to form physical solution.
  • CO2 forms unstable carbonic acid with water and is transported as such.
  • CO2 is also transported from tissue to lungs as bicarbonates.

Question 13.
How are lungs designed in human beings to maximise the area for exchange of gases?
Answer:
Within the lungs, the primary bronchi divides into smaller and smaller tubes which finally terminate into balloon-like structures called alveoli. These alveoli increase the surface area for exchange of gases. There are 750 million alveoli in the lungs of man. If the alveolar surface is spread out it would cover about 80 m2. Thus it makes efficient exchange of gases.

Each alveolus or air sac has a diameter of 75 to 300 microns and has a very thin wall. The walls of the alveoli are elastic and are supplied with capillaries. Through these thin walls gases are exchanged between the capillaries and the air sacs.

Question 14.
What are the components of the transport system in human beings? What are the functions of these components?
Answer:
There are two main transport systems in human beings :

  1. Blood vascular system.
  2. Lymphatic system.

Components of blood vascular system

  • Blood: It is a reddish viscous fluid connective tissue. In an adult human being, it is 5-6 litres in amount. Blood consists of two parts – plasma and formed elements. (RBCs, WBCs and blood platelets). Blood transports digested food, oxygen, carbon dioxide, nitrogenous wastes and hormones in the body.
  • Heart: It is a hollow, muscular pumping organ. The heart sends the blood to lungs. Heart pumps the blood in the body.
  • Blood vessels: The blood vessels which carry oxygenated blood are called arteries. They divide to form capillaries of finer dimensions. Exchange of materials takes place across the capillaries. It is possible because the walls of capillaries are extremely thin. The blood from the tissues is returned by veins.

Components of Lymphatic system

  1. Lymph: It acts as middle man between blood and tissue. It destroys harmful bacteria
  2. Lymph vessels
  3. Lymph capillaries
  4. Lymph nodes

Question 15.
Why is it necessary to separate oxygenated and deoxygenated blood in mammals and birds?
Answer:

  • In the heart of these organisms the left side has oxygenated blood and right side deoxygenated blood.
  • The separation of blood allows a highly efficient supply of oxygen to the body.
  • It is essential for such animals which have high energy needs.
  • They also constantly use energy for maintaining body heat.

Question 16.
What are the components of transport system in highly organised plants?
Answer:
Components of transport system in plants

  • Xylem tissue. Vessels and tracheids of roots, stems and leaves are concerned with transport of water and minerals in plants.
  • Phloem consists of sieve tubes and companion cells. It transports food, amino acid, phytohormones and other substances from leaves to various parts of plants.

Question 17.
How are water and minerals transported in plants?
Answer:
Transport of water and minerals
1. In xylem tissue, vessels and tracheids of the roots, stems and leaves are interconnected to form a continuous system of water conducting channels reaching all parts of the plants.

2. Plants absorb water and minerals through their entire surface i.e., roots, stem and leaves. However, mainly the water is absorbed by roots from soil.

3. The area of young roots where most of the absorption takes place is the root hair zone.

4. This zone is the area of greatest permeability.
PSEB 10th Class Science Solutions Chapter 6 Life Processes 6

5. Passage of water in root or pathway of water in root

  • The entry of water into the root hair dilutes the cell sap. Thus water molecules in root hair increase as compared to adjacent cortical cells.
  • Water reaches the passage cells of endodermis. These passage cells lie opposite the xylem.
  • They allow water to entre the pericycle.
  • So, water enters the xylem from pericycle for upward movement of sap.

6. The Ascent of Sap:
The upward movement of water from the root towards the top of the plant in the xylem vessels is called ascent of sap. The upward transport of water and minerals in plants which are in some cases as tall as 400 ft. poses a serious problem.

7. Transpiration also helps in the absorption and upward movement of water and minerals dissolved in it from roots to the leaves.

Question 18.
How is food transported in plants?
Answer:
Transport of food in plants:
The food prepared in the green leaves of plants is transported through phloem in the form of sucrose solution to storage organs of roots, seeds and fruits. This process is called translocation. This process requires energy. It is provided by ATP molecules. This increases the osmotic pressure in the tissue causing water to move into it. This pressure moves the material in the phloem to tissues which have less pressure.

PSEB 10th Class Science Solutions Chapter 6 Life Processes

Question 19.
Describe the structure and functioning of nephron.
Or
How does urine formation occur in human?
Answer:
Structure of a Nephron:
A nephron is made up of:

  • a globular double-walled Bowman’s capsule around a clump of capillaries or glomerulus, and
  • a tubule surrounded by blood capillaries.

The tubule consists of
(a) a proximal convoluted portion
(b) the loop of Henle, with descending and ascending limbs, and
(c) a distal convoluted part.

The nephron empties into a collecting duct. The two million nephrons of a human being, end to end would extend for nearly 80 km. All the collecting ducts discharge into a central cavity of the kidney (pelvis) that connects to the ureter.

Functioning of Nephron
Urine is formed by 3 processes: glomerular filtration, tubular reabsorption and tubular secretion in the nephrons of the kidney.
1. Ultrafiltration (Glomerular filtration):
Blood is filtered under pressure in the glomeruli present in the cup-like structure of Bowman’s capsule. Glomerular (nephric) filtrate is formed.
PSEB 10th Class Science Solutions Chapter 6 Life Processes 7
Nephron and its function

2. Tubular reabsorption:
In the PCT, entire glucose, amino acids, vitamins and hormones, most of the inorganic ions are reabsorbed by active transport, most of water by osmosis, and some urea by back diffusion from nephric filtrate.
Loop of Henle mainly concentrates urine to conserve water. Here, some inorganic ions are actively taken up and some water leaves by osmosis.

3. Tubular secretion:
In the DCT, collecting tubule and collecting duct, many ions, water (depending upon availability) are secreted in to DCT and collecting duct.
Urine formed passes into bladder from kidney through ureters.

Question 20.
What are the methods used by plants to get rid of excretory products?
Answer:
Excretory products of plants include CO2, salts, resins, tanins latex etc. Excretion in Plants

  • Excess of water passes out during transpiration.
  • Plants get rid of dead tissue as a measure to eliminate waste.
  • Waste products may be stored in cellular vacuoles.
  • Waste products may be stored in leaves which fall off.
  • Resins and gums are stored in old xylem.
  • Plants also excrete wastes into soil.
  • Aquatic plants lose their waste products by diffusion into the water.

Question 21.
How is the amount of urine produced regulated?
Answer:

  • Amount of urine formed depends upon the availability of water in the body.
  • ADH (Antidiuretic Hormone) regulate the amount of water.
  • Osmoregulation helps in regulation of salts and water.
  • Urine is stored in urinary bladder.

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Punjab State Board PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals Important Questions and Answers.

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Long Answer Typt Questions

Question 1.
Show various steps involved in extraction of metal from an ore by a sketch.
Answer:
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 1
Steps involved in the extraction of metals from ores.

Question 2.
Give methods of enrichment of ores.
Answer:
Methods of enrichment of ores. Ores or minerals are mined from earth these are usually contaminated with large amount of impurities which are called gangue. It is necessary to remove these impurities before extraction of metals. By removing gangue the ore is enriched and concentration of metal is increased. Therefore ore in enriched prior to other processes. Methods of removing gangue from ore depends on the difference of physical and chemical properties of both of them.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 2
Enrichment of ore using magnetic method.

Physical methods of enrichment :

  • Hydraulic Washing: In this method finely powdered ore is washed with jet of water. In this strong flow of water light gangue particles are washed away where as heavy ore particles settle down, Tin and lead ores are enriched by this method.
  • Froth Floatation Method: In this method, mixture of powdered ore and water or some appropriate oil is taken in a tank. Ore particles are coated with oil and gangue particles are wet with water. A blast of compressed air is blown through the pipe of a rotating agitation to produce froth, due to this, mineral particles wetted with oil change into foam and float on the surface of water. Froth containing ore particles is easily transferred to another container sulphides of copper, lead and zinc are enriched by this method.

Chemical Methods: The chemical method used for the concentration of the ore is based on the difference in some chemical property of the metal and the impurities. An example of this method is the concentration of bauxite ore of aluminium.

Concentration of aluminium ore by Bayer’s process: In this method, Bauxite is reduced by treating it with hot sodium hydroxide. It gives sodium meta aluminate (NaAlO2) which is soluble in water. The solution in filtered to remove the gangue present in the ore because it does not dissolve in sodium hydroxide. NaAlO2 is allowed to react with hydrochloric acid to obtain Aluminium hydroxide. On strong heating aluminium hydroxide pure aluminium oxide is obtained.

Following reactions take place
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 3

Question 3.
Explain General methods used in the extraction of metals.
Answer:
Steps involved in the extraction of metals :

  • Enrichment (concentration) of ore.
  • Converting concentrated ore into oxide.
  • Reduction of metal oxide to obtain metal.
  • Refining of impure metal.

1. Concentration :
(A) Hydraulic washing: This method is used for concentration of oxide ores Gangue particles are lighter as compared to ore particles. In this method powdered ore is washed with flowing water. Light gangue particles are washed away with water and heavy ore particles are left.

(B) Froth floatation method: In this method powdered ore is taken in a tank containing water pine oil is also added to it. Sulphide ore is wet with oil and gangue is wet with water.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 4
The water is agitated by blowing compressed air violently, a froth is formed on the surface of water. This froth carries the lighter ore particles along with it to the surface. Gangue particles are heavy and settle to the bottom.

(C) Magnetic separation.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 5
Enrichment of ore using magnetic method.

1. Magnetic method: This method is acceptable for magnetic impurities like iron, cobalt, Nickel etc. Minerals which are of magnetic nature got attracted towards magnetic field. Chromite and pyrolusite ores are enriched by this method. In this method ground ore is placed on a conveyer belt. This belt goes around two rollers one of which is magnetic. When ore comes near the magnetic roller then two heaps of magnetic and non magnetic materials are obtained. Iron ore magnetite is enriched by this method.

(D) Chemical separation: This process is based on the difference between chemical – properties of ores and gangue eg. Bauxite Al2O3.2H2O is impure form of aluminium oxide. It contains Iron (III) oxide (Fe2O3) and sand (SiO2) as main impurities. Due to iron (III) oxide its colour is red brown. Bayer’s process is used to obtain pure aluminium from / bauxite. In this methods powdered ore is mixed with heated sodium hydroxide.
Al2O3 (S) + 2NaOH (aq) → 2NaAlO2 (aq) + H2O (l)
NaAlO2 (aq) + 2H2O (l) → Al(OH)2 (s) + NaOH (aq)
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 6

2. Converting concentrated ore into metal oxide
Roasting: In this process ore is heated in the presence of air to obtain metal oxide. Which can easily be reduced to obtain the metal.

Zinc blende contains zinc sulphide when concentrated zinc blende ore (zinc sulphide) is roasted in air then it gets oxidized to give zinc oxide.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 7
Calcination: In this process ore is heated in the absence of air to remove moisture and volatile impurities.
When carbonate ore is heated it dissociates to give metal oxide.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 8

3. Extracting metals from metal oxide.
To obtain metal from metal oxide it is heated with some reducing agent. To obtain metals zinc, iron, tin etc. their oxides ore heated with carbon which acts as reducing agent.
ZnO(s) + C(s) → Zn(s) + CO(g)

Oxides of metals with medium activity can be reduced by using highly reactive metals like sodium, calcium and aluminium etc.
3MnO2(s) + 4Al(s) → 3Mn(l) + 2Al2O3(s) + heat

4. Electrolytic refining.
In this method impure metal is taken as anode and a thin strip of pure metal is taken in the form of cathode metal salt solution is taken as electrolyte. When electric current is passed through the electrolyte, pure metal from anode dissolves into solution and impurities settle down as anode mud.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 9
Electrolytic refining

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 4.
(a). How do metals and non-metals react?
Answer:
Metals and non-metals react on the basis of electronic configuration in the valence shell.

Sodium has only one electron in its outer most shell. If it lose its electrons of the M shell then L will become its outermost shell which have complete octet. Nucleus of this atom will have 11 protons but number of electrons is 10, therefore it is positively charged and gives Na+ sodium positive ions. On the other side, there are 7 electrons in the outer most shell of chlorine and it requires one electron to complete its octet. If there is reaction between chlorine and sodium then lost electron of sodium atom is gained by chlorine atom and chlorine atom becomes negatively charged by one unit. Because there are 17 protons in the nucleus of the chlorine atom and there are 18 electrons in K, L and M shells. Therefore, chloride negative ions Cl- is obtained.

Due to opposite charges sodium and chloride ions attract each other and they form strong bonds involving electrostatic forces and form sodium chloride.

Another ionic compound, magnesium chloride is shown in fig.
Formation of NaCl and MgCl2 by Electron transfer :
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 10
Formation of sodium chloride.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 11
Formation of sodium chloride.

Compounds formed by metals and Non-Metals by the transfer of electrons between them are called ionic or electrovalent compounds.

(b) Write four main exceptions from normal properties of metals and Non-Metals.
Answer:

  • All the metals are solid at room temperature except mercury. Melting point of metal is usually high but of Gallium and Cesium is low.
  • Iodine is a non-metal but still shiny.
  • Carbon is a non-metal which can have many forms. Diamond is allotrope of carbon. It is the hardest substance found in nature. Its melting and boiling point are very high. Another allotrope of carbon is graphite which is conductor of electricity.
  • Alkali metal (lithium, sodium, Potassium) are so soft that these can be cut by knife. They have low density and low melting point.

Question 5.
How will you differentiate between metals and non-metals?
Answer:
Differences between metals and non-metals on the basis of physical properties :

Metals Non-metals
1.         All metals are solid at room temperature. But mercury is liquid at room temperature. 1. Non-metals exist in all the three states at room temperature. Phosphorous and sulphur are solid, H2, O2, N2 in gaseous state, and bromine in liquid state.
2. Metals are ductile, malleable and tenacious. 2. These are soft.
3. Metals have lustre i.e. metal shine. 3. They do not have lustre but diamond, graphite and iodine are exceptions.
4. Metals are good conductors of heat and electricity but bismuth is exception.  4.All non metals are non conductors except graphite and carbon gas.
5. Metals have high melting and boiling points.  5. Non metals have low melting and boiling points.
6. Metals are hard but sodium and potassium can be cut by knife. 6. These are not very hard but diamond is the hardest substance.
7. Metals have very high relative densities but Na, K are exceptions. 7. Non metals have very low relative densities.
8. Metals are opaque. 8. Gaseous non metals are transparent.

Difference between metals and non-metals on the basis of chemical properties

Metals Non-metals
1. Metals form alkaline oxides some of them form bases. 1. Non-metals form acidic or neutral oxides.
2. Metals react with acids to displace hydrogen and form salts. 2. Non-metals do not displaces hydrogen from acids.
3. Metals are electropositive in nature. 3. Non-metals are electronegative in nature.
4. Metals combine with chlorine to form chlorides which are electrovalent compounds. 4. Non-metals combine with chlorine to form chlorides which are covalent compounds.
5. Some metals combine with hydrogen to form hydrides which are electrovalent. 5. Non-metals combine with hydrogen to form hydrides which are covalent.
6. Metals are reducing agents. 6. Non-metals are oxidizing agents.
7. Metals form positive ions in aqueous solution. 7. Non-metals form negative ions in aqueous solution.

Question 6.
Discuss about the extraction of metals
Answer:
Some metals are found in free state in nature. Some metals are found in the form of compounds. Metals at the bottom of reactivity series show very low reactivity. These are found in free state. Gold, silver, platinum and copper are found in free state.

Copper and silver are also found in the form of sulphide and oxide ores. Metals (K, Na, Ca, Mg and Al) which are at the top of reactivity series show very high reactivity that they are never found in free state. Metals at the middle of the reactivity series (Zn, Fe, Pb etc.) are moderately reactive. These are found in the form of oxide, sulphide or carbonate. Some metal ores are found in the form of oxides.

Metals are classified into three types:
(a) least reactive metals
(b) Moderately reactive metals
(c) highly reactive metals.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 12
Reactivity series and metallurgy

Question 7.
What is rust? What are the requirements necessary for its completion? Give ways to prevent rusting of iron?
Answer:
Surface of iron aquires a coating of a brown flaky substance called rust. It is a compound of Iron (III) Oxide and iron (III) hydroxide. It weakens the iron surface. Due to this, a great loss occurs to the iron articles.

The presence of moisture and air is necessary for rusting of iron. This can be proved with an experiment. If we take new shining irons nails in three test tubes as shown, then we find that nails which are in contact with water and air, got rusted. If we completely immerse the nails in water and cover the water surface with oil so that there is no air available for the nails, then nails will not get rusted.

Similarly if we use CaCl, in the test tube absorbs all the moisture so that no moisture is available in this case also, nails will not get rusted.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 13

Ways to Prevent Rusting :

  1. Using oil or grease on the surface: If iron surface is covered with oil or grease it does not remain in contact with air and thus rusting is prevented. Machine parts are saved by this method.
  2. Using enamel: By painting iron surface, rusting can be prevented. Buses, cars, scooter, motor cycle, windows, trains etc. are saved by this method.
  3. Covering with plastic: Iron surface is covered with plastic. Iron furniture is saved by this method.
  4. Galvanization: A process of coating thin layer of zinc on iron is called galvanization. This method is used to prevent buckets, tubs, drums, iron sheets etc. from rusting.
  5. By electroplating: Iron can be electroplated by metals like Nickle, Chromium, aluminium etc. Rims, handles, bumpers etc. of vehicles are prevented from rusting by this method.
  6. By tin: Iron is coated with tin. Ghee canisters, boxes used for packing food are tinned.
  7. Converting to steel: Iron can be preverted from rusting by converting it into steel.

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 8.
Explain General properties of ionic compounds.
Answer:
General properties of ionic compounds are given below:

  • Physical nature: Due to strong force of attraction between positive ions and negative ions, ionic compounds are solid. They are brittle and break on pressing.
  • Melting and boiling point: They have high melting and boiling points. Because a large amount of energy is required to break the strong inter ionic attraction.
  • Solubility: Ionic compounds are normally soluble in water but are insoluble in Kerosene, Petrol etc.
  • Electric Conductivity: In solid form ionic compounds do not conduct electricity because of strong and firm structure. Movement of ions is not possible. But ionic compounds can conduct electricity in molten state, because electrostatic force of attraction becomes very weak due to heat energy. Therefore ions can move freely and electric current can pass through it. Mobility of charged particles is necessary for conduction of electricity in a solution. Ions are present in aqueous solution of ionic compounds. When electric current is passed through the solution then ions start moving towards the opposite electrodes.

Question 9.
What is an alloy? Magnetic iron oxide explain the objective of their formation?
Answer:
Alloy: An alloy is a homogeneous mixture of a metal with another metal or non-metal, e.g. solder is an alloy of lead and tin (Pb and Sn). Stainless steel, solder, brass, bronze, bell metal etc.

Uses of alloys :

  • For increasing hardness: Iron is mixed with carbon to form stainless steel which is harder than iron. Copper is mixed with gold and lead is mixed with silver to make them hard. Duralium is an alloy made from aluminium and is very hard.
  • Increasing strength: Steel, Duralium are hard as well as strong.
  • Preventing Corrosion: By making stainless steel an alloy of iron, which do not get rusted.
  • To produce sound: Bell metal is an alloy of copper and tin used to produce loud sound.
  • To lower melting point: An alloy of Bismuth, tin and lead has low melting point.
  • Moulding: Bronze and type metal.
  • For change in colour: Aluminium bronze is an alloy of copper and aluminium is of golden colour.
  • Domestic uses: Alloys are used in homes, factories, offices etc. e.g. utensils, almirahs, fans, refrigerators elements etc. are made up of alloys.

Question 10.
Explain the activity series of metals.
Answer:
All metals have different rates of activity. Some metals like sodium, potassium and calcium etc. are highly reactive. These metals combine with oxygen to form oxide and react with hydrogen to form hydrides. Some metals are compratively less reactive e.g. iron, zinc etc. Some metals are least reactive e.g. gold, silver. Reactivity of metals depends on their ability to lose electrons, Metals are arranged in a list in decreasing rate of their activity.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 14
Metals which are above hydrogen are more reactive and those below hydrogen are lower in reactivity and are found in free state. In this series potassium is the most reactive metal in this series.

Short Answer Type Questions

Question 1.
Name two metals which are good conductors of heat and electricity. Name metals which are highly and least conducting with reference to heat.
Answer:
Copper and aluminium are good conductors of electricity and heat. Silver is very good conductor of heat whereas lead is not a good conductor of heat.

Question 2.
Define ductility with example.
Answer:
Property of drawing thin wires from a metal is called ductility. Gold is the highest ductile metal. We can draw 2 km long wire from 18 carat gold.

Question 3.
What is electrical conductivity? Name the metals which have the highest conductivity, less than this and the lowest conductivity.
Answer:
It is the ease with which electric current can flow through a metal. Those metals which offer very low resistance to the flow of current they have high conductivity. Silver, copper are very good conductors of current then comes gold, aluminium and tungsten. Lead and iron have least conductivity i.e., they offer very high resistance to the flow of current.

Question 4.
Which property of metals give them characteristic chemical properties?
Answer:
Metals form positive ions by loosing electrons. This property of formation of ions by the metals give them characteristics chemical properties, e.g., Mg form Mg ion by loosing two electrons :
Mg → Mg2+ + 2e

Question 5.
Ionic compounds are found in which state? Comment on the melting and boiling point of ionic compounds.
Answer:
Compounds which are formed by the transfer of electrons from metals to Non¬Metals are called ionic or electrovalent compounds e.g., NaCl, LiCl, CaCl2, CaO, MgCl2. Ionic compounds have very high melting and boiling points because a large amount of energy is required to break the strong inter-ionic attractions.

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 6.
What is difference between minerals and ores?
Answer:

Sr. No. Minerals Ores
1. Those natural occuring substances, which contain metals in the form of compounds. 1. These are the minerals from which metals can be extracted easily and cheaply.
2. In many of the minerals percent age amount of metals is large and in some it is less. 2. In all the ores, percentage amount of metals is enough.
3. In some minerals there are so many impurities which create difficulty in the extraction of metals. 3. Ores do not have such problematic impurities.
4. All the minerals can not be used for extracting metals. All the minerals are not ores. 4.         All the ores can be used to extract metals.

Question 7.
How are the metals extracted, which are at the top of reactivity series?
Answer:
Metals which are towards the top of reactivity series are sodium, calcium, magnesium, aluminium. There are very reactive. These metals can not be obtained by heating them with carbon. These have more affinity towards oxygen, therefore these are extracted by electrolytic reduction. Sodium, magnesium and calcium are obtained by the electrolysis of their molten chlorides. Metals got deposited at cathode and chorine is liberated at anode.
At cathode : Na+ + e → Na
At anode : 2Cl → Cl2 + 2e

Aluminium is obtained by the electrolytic reduction of aluminium oxide.
At cathode ; Al3+ + 3e → Al
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 15

Question 8.
How the metals, which are in the middle of the activity series extracted?
Answer:
Metals which are in the middle of the activity series are iron, zinc, lead, copper etc. These are found in the form of sulphides or carbonates. It is easy to obtain metals from their oxides compared to sulphides or carbonates. Therefore before extraction metal sulphide or carbonates are converted into their oxide. Sulphide ores are converted into metal oxides by heating in the presence of air. This is known as roasting. Carbonate ores are heated in limited supply of air to convert them into oxides. This is known as calcination. Following reactions take place during roasting and calcination of zinc.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 16
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 17
Then by using carbon as reducing agent, metal is extracted from metal oxide, e.g. when Zinc oxide is heated with carbon it gets reduced to give zinc.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 18
In addition to using carbon for reduction, displacement reaction can be used to extract metals. More reactive metals like sodium, calcium, aluminium etc. can be used as reducing agents because these can displace atoms which are below them in the reactivity series. For example, when mangnese dioxide is heated with aluminium powder then following reaction takes place.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 19

Question 9.
How will you extract metals which are low in the activity series?
Answer:Metals low in the activity series are less reactive and can be obtained from metal oxides simply by heating. Cinnabar (Hgs) an ore of mercury (Hg) when heated change to mercuric oxide (HgO), on heating it further it is reduced to mercury.

Question 10.
Explain the reactions of metals with water.
Answer:
On reacting with water, metals form metal oxide and produce hydrogen. These dissolve in water to form metal hydroxide. But all metals do not react with water.

Metals like sodium and Potassium react with cold water, vigorously. The reaction of sodium and Potassium is very vigorous and exothermic that hydrogen produced starts burning simultaneously.
2K (s) + 2H2O (l) → 2KOH (aq) + H2(g) + heat
2Na (s) + 2H2O (l) → 2NaOH (aq) + H2(g) + heat

Reaction of calcium with water is slow. Heat produced in this reaction is not enough to burn the hydrogen produced in the reaction.
Ca (s) + 2H2O(l) → Ca (OH)2 + H2(g)

Metals like iron, aluminium, zinc etc. do not react with cold water and not even with hot water. But they react with steam to form metal oxide and produce, hydrogen.
2Al(s) + 3H2O(g) → Al2O3(S) + 3H2(g)
3Fe(s) + 4H2O(g) → Fe3O4(s) + 4H2(g)
Metals like lead, copper, silver and gold etc. do not react with water.

Question 11.
How do metals react with :
1. Oxygen
2. Dilute acids
3. Chlorine
4. Hydrogen.
Answer:
I. Reaction of metals with oxygen: Metals combine with oxygen to form metal oxides. Metal atoms lose their loosely bound electrons to form positive ions where as oxygen atoms gain electrons to form negative oxide ions. These metal oxide are basic in nature. Since all metals have different level of reactivity therefore they combine with oxygen at different temperatures.
1. Na and K Combine with oxygen at normal temperature to form oxides which dissolve in water to form hydroxide.
4 Na (s) + O2(g) → 2Na2S(s)
Na2O(s) + H2O → 2NaOH (or)

2. If magnesium is burned in air it forms magnesium oxide.
Mg → Mg2+ + 2e-
O + 2e → O2-
Mg2+ + O2- → MgO

3. Copper and iron combine with oxygen at high temperature in dry air.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 21

II. Reaction of metals with dilute acids. Metals reacts with dilute acids to produce hydrogen gas. Rate of reactivity is different.
1. Na, K, Zn, Mg, Fe etc. are reactive in decreasing order.
2Na + HCl → 2NaCl + H2
Mg + 2HCl → MgCl2 + H2
Zn + H2SO4 → ZnSO4 + H2

2. Dilute nitric acid reacts with metals like Cu, Ag, Pb, Hg to form NO (nitrogen oxide).
Cu + 8HNO3 → 3Cu (NO3)2 + 2NO + 4H2O
3Ag + 4HNO3 → 3AgNO3 + NO + 2H2O

3. Dilute nitric acid reacts with Mg and Mn to produce hydrogen gas.
Mg + 2HNO3 → Mg (NO3)2 + H2

4. Gold and platinum do not react with dilute acids.

III. Reaction of metals with chlorine. Metals combines with chlorine to form electrovalent chlorides.
Ca + Cl2 → CaCl2

IV. Reaction of metals with hydrogen. Reactive metals like Na, K, Ca etc. react with hydrogen to form hydrid.
2Na + H2 → 2NaH
Ca + H2 → CaH2

V. Reaction of metals with water:
1. Water at normal temperature react with Na, K and Ca to liberate hydrogen gas.
2Na + 2H2O → 2NaOH + H2
Ca + 2H2O → Ca (OH)2 + H2

2. Mg, Zn and Fe react with boiling water to form oxide.
Mg + H2O → MgO + H2
3Fe + 4H2O → Fe3O4 + 4H2

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 12.
What is roasting? When do you use it?
Answer:
Roasting. After enrichment of ore, it is heated in the presence of dir, this process is called roasting sulphides or carbonates of some metals are converted into oxides, because extraction of metal is easy from oxides. Carbonates and sulphides of zinc and lead are converted into oxides by roasting.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 22

Question 13.
If a copper plate remains immersed in silver nitrate solution for some time then what happens? Write the ionic equation for the reaction.
Answer:
Copper is more reactive than silver. Copper will displace silver from the solution and silver gets deposited on copper. Colour of the solution becomes blue.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 23

Question 14.
Copper sulphate solution is stored in an iron container. After some days holes were seen in the container. Write the reaction. Explain the reaction on the basis of activity series.
Answer:
Iron is more reactive than copper and is placed before copper in the activity series. Therefore iron can displace copper from copper sulphate solution, due to this reaction holes were seen in the container.
CuSO4 + Fe → FeSO4 + Cu
Cu2+ (aq) + Fe(s) → Fe2+ (aq) + Cu(s)
Thus iron displaced copper.

Question 15.
Why copper becomes green if left open in air. Why?
Answer:
Copper reacts with moist carbon dioxide which is present in air. This makes its surface dull and a green layer is seen on the surface of copper. This green substance is copper carbonate.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 24

Question 16.
What is 24 carat gold?
Answer:
Pure gold is called 24 carat gold. It is very soft. It can be used to make ornaments. Small amount of silver or copper is mixed with it to make it harder. In our country usually 22 carat gold is used to make ornaments. This means 22 pure gold is mixed with 2 parts of copper or silver.

Question 17.
Which process is used for the enrichment of sulphide ore. Explain in brief two steps involved in the extraction of metal from enriched sulphide ore.
Answer:
Sulphide ore is finely grounded to get powder. This is then enriched by using ‘Froth floation process’.

Steps involved in the extraction of metal from enriched sulphide ore :
1. Roasting: Enriched ore is heated in the presence of air to get oxides. This process is called roasting.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 25

2. Reduction. Oxide of the enriched ore is heated with reducing agent to extract the metal.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 26

Question 18.
Give differences :
(i) Hydraulic washing and liquation.
Answer:

Hydraulic Washing Liquation
1. This process is used for concentration of an ore. 1. The process is used for refining of metals.
2. Ore is washed with washing. 2. This is used for refining metal having low melting points.

(ii) Electrolytic reduction and reduction by carbon.
Answer:

Electrolytic reduction Reduction by carbon
1. Here cathode acts as reducing agent. It converts metal ions into metals by providing electrons.
  1. Carbon is used as reducing agent.
2. This method is used to reduce the salts of highly reactive metals. 2. This method is used to reduce the oxides of metals which are in the middle of activity series.

Question 19.
An alloy of yellow’ colour is made up of two metals A and B. When this alloy was dipped in dilute sulphuric acid, a layer dissolved in acid and formed colourless solution. B did not dissolve in it and the surface of alloy attained red brown colour. What is A and B?
Answer:
Yellow coloured alloy is brass which is mixture of zinc and copper. In this A is zinc and B is copper.
Zn + H2SO4 → ZnSO4 + H2

Question 20.
Sulphur dioxide (SO2) gas is produced when a certain ore is heated. Write the method involved in the extraction of metal from this ore.
Answer:
SO2 gas is produced when copper pyrites an ore of copper is heated.

Following steps are involved in the extraction of metal from this ore :
1. Ore is ground to get powder. It is mixed with water and pine oil. Compressed air is blown to separate impurities. This way ore gets enriched, this method is called froth floatation method.

2. Now the enriched ore is roasted. A part of CuS converts to CuO
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 27
Copper is in liquid state and is purified by electric refining.

3. Electrical refining. In this process impure copper rod is taken as anode and pure copper plate is taken as cathode. Electric current is passed through copper sulphate solution in the presence of acid
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 28

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 21.
What is Thermite process? Write its uses.
Answer:
Some displacement reactions are highly exothermic. The quantity of heat produced is so high that metals obtained are in molten state. When Iron (III) oxide (Fe2O3) reacts with aluminium then a large amount of heat is produced.
Fe2O3(s) + 2Al(s) → 2Fe(l) + Al2O3(s) + heat

This is known as thermite process. This process is used to weld the rails and to join the cracks in machines.

Question 22.
Give five uses of non-metals.
Answer:

  • Hydrogen is used in the preparation of vegetable oil.
  • Carbon is an important non-metal which is main constituent of vitamins, proteins, carbohydrates, enzymes etc. Graphite is used as an electrode in various cells.
  • Nitrogen is used in ammonia, Nitric acid and fertilizers. Its presence in air controls the rate of combustion.
  • Presence of oxygen is the base of our life. Combustion is also possible in the presence of oxygen.
  • Sulphur is used in many medicines and is also used to make explosives.

Question 23.
Differentiate Roasting and Calcination.
Answer:

Roasting Calcination
1. Roasting is used for sulphide ores. 1. Calcination is used for carbonate and hydrated ores.
2. Ore is heated in the presence of air.  2. Ore is heated in the absence of air.
3. SO2 gas is produced. 3. CO2 gas is produced.

Question 24.
How is ionic compound sodium chloride, forms from sodium and chlorine?
Answer:
Sodium and chloride ions are oppositely charged and thus attract each other
They are bound together by strong electrostatic force of attraction and exist in the form of sodium chloride (NaCl). Sodium chloride does not exist as a molecule but as a set of ions :
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 29

Question 25.
Ionic compounds are insulators when in solid state whereas when in aqueous solution they become conductors. Why?
Answer:
There exist a strong force of attraction between positive and negative ions of the ionic compounds, due to which these compounds are solid and hard. Due to their firm and rigid structure ions cannot move. But in molten state or in aqueous solution the force between opposite ions become weak and the ions can move freely. Therefore electricity can pass through ionic compounds when in liquid form.

Question 26.
What is aqua regia? Explain.
Answer:
Aqua regia is a mixutre of concentrated hydrochloric acid and concentrated nitric acid in the ratio of 3 : 1. It can dissolve gold where no single acid can do this. Aqua regia (Latin word for Royal water) is highly corrosive and fuming liquid. It can also dissolve platinum.

Question 27.
Give two main ores of aluminium. Also give two alloys of aluminium.
Answer:
Two ores of aluminium are :

  1. Bauxite, Al2O3. 2H2O
  2. Cryolite, Na3 (AlF6).

Two alloys of aluminium are :

  1. Duralium
  2. Magnalium.

Question 28.
Give uses of pure metals.
Answer:

  • Copper and aluminium wires are used in the transmission of power (electricity).
  • Utensils, Machines etc. are made up of iron, aluminium and copper.
  • Gold and silver are used to make ornaments, these are also used in sweets in the form of silver foil.
  • Metals like cadmium, titanium, zinconium etc. are used in nuclear energy and space science projects.
  • Aluminium foil is used to wrap eatables.
  • Titanium and its alloys are used in airplane, airplane structure and engine, chemical reactor.
  • Metals are used in broken bones and body parts.

Question 29.
Which gas is produced, when reactive metals come in contact with dilute hydrochloric acid? Write the chemical reaction between iron and dil. H2SO4.
Answer:
When reactive metals come in contact with dil. hydrochloric acid then (H2) hydrogen gas is produced.
Hydrogen gas is produced when iron reacts with dil. H2SO4.
Fe + H2SO4 → FeSO4 + H2

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 30.
What is the function of cryolite in the electrolytic reduction of alumina?
Answer:
Cryolite has two functions in the extraction of aluminium :

  • To reduce the melting point of alumina.
  • Alumina is bad conductor of electricity on mixing cryolite (Na2AlF3), Al2+ ions are produced from alumina.

Question 31.
How do iron and aluminium react with water?
Answer:
Aluminium and iron do not react with cold or hot water. But react with steam to form metal oxide and hydrogen.
2Al(s) + 3H2O(g) → Al2O3(s) + 3H2(g)
3Fe(s) + 3H2O(g) → Fe3O4(s) + 3H2(g)

Question 32.
What happen when :
(i) Iron oxide is heated with coke?
Answer:
Iron oxide is readuced to iron.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 30

(ii) Magnesium is treated with dilute sulphuric acid?
Answer:
Hydrogen is produced
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 31

(iii) Zinc is added to blue vitriol solution?
Answer:
Blue colour of solution gradually faders away
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 32

Question 33.
What is rust? Explain it with the help of a chemical reaction.
Answer:
If iron is left open in moist air, a brown layer is produced on its surface. This brown coloured layer is of Ferric oxide and ferric hydroxide. This is called rust. This makes iron weak.
4Fe + 3O2 + 3H2O → Fe2O3 + 2Fe(OH)3

Question 34.
Write names of main alloys and their constituents?
Answer:

Alloys Constituents Uses
1. Steel Iron, carbon used in airplanes, buildings vehicles etc.
2. Stainless steel Iron, Carbon, Chromium utensils, machine parts, knife, blade, food and milk industry, nuts, bolts, taps etc.
3. Brass Copper, Zinc utensils, idols, airplanes, medals, steam driven train parts etc.
4. Bronze Copper, tin utensils and other apparatus.
5. Solder Lead, tin For joining/welding electric wires.
6. German Silver Copper, Nickel, zinc Airplane wings, utensils used in kitchen of airplanes and other mate­rials.
7. Bell metal Copper,tin For making bells.
8. Duralium Aluminium, copper magnesium and mangnese in very small amount. In airplane
9. Magnoleum Aluminium, magnesium Light weight tools and cheap utensils.
10. Gun metal Copper, tin, zinc For making gears of vehicles and machines.

Question 35.
Write the names of metals found in Bronze and Duralium, give uses of these alloys.
Answer:
Bronze. It is 90% copper and 10% tin. It is used in idols, medals, coins and vessels used for cooking food.
Duralium. It consists of 95% aluminium, 4% copper, 0.5% magnesium and 0.5% manganese. It is used in aeroplanes, space crafts, kitchen vessels.

Question 36.
What is rust? What is its chemical formula?
Answer:
When iron is left open in air, then a layer of iron oxide is formed on the surface of iron. This brown matter is rust. It corrodes the metal. Its chemical formula is Fe2O3. xH2O.

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 37.
What are metals?
Answer:
The elements which are on the left and in the middle of the periodic table and have metallic lustre are called metals. These are usually ductile, malleable, good conductor of electricity and heat, hard and have high density. They form basic oxides. Examples of metals are gold, iron, silver, copper, platinum etc.

Question 38.
What is ihe reason of catching fire by potassium and sodium on their own?
Answer:
Potassium and sodium reacts with water vigorously and violently. The reaction is very violent and highly exothermic that hydrogen produced in the reaction catches fire on its own.

Question 39.
Observe the figure given below and name the gas produced. Also give the chemical equation.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 33
Answer:
Hydrogen gas is produced
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 34

Question 40.
What is indicated by the following figure?
Or
With the help of a labelled diagram prove that both oxygen/air and water are necessary for rusting of iron.
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 35
Answer:
Both air and moisture are required for rusting of iron.

Question 41.
Why the substance obtained by mixing small amount of carbon in iron is used largely for various purposes?
Answer:
When small amount of carbon is mixed with iron it changes to steel. This is stronger than iron. It can be used in ships, vehicles, dams.

Question 42.
Write a chemical equation for the reaction taking place in the test tube. How does the colour of solution change? What is change in colour of iron nails?
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 36
Answer:
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 37
The colour of the solution changes from blue to light green. The colour of Iron nails changes from grey to brown.

Very Short Answer Type Questions

Question 1.
Give one example of metal which is liquid at room temperature.
Answer:
Mercury.

Question 2.
Name one metal and one non-metal which is liquid at room temperature.
Answer:
Metal-Mercury.
Non-Metal—Bromine

Question 3.
Name one non-metal which has bright lustre.
Answer:
Iodine.

Question 4.
Name one non-metal which does not have bright.
Answer:
Phosphorus.

Question 5.
Which of the following metal are liquid at body temperature (37° C): Gallium, Magnesium, Caesium, Aluminium.
Answer:
Gallium and Caesium.

Question 6.
Name one non-metal which is a good conductor of electricity?
Answer:
Graphite (Carbon).

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 7.
Arrange the following metals in the decreasing order of reactivity,
Fe, Zn, Cu, Na, Ag.
Answer:
Na > Zn > Fe > Cu > Ag.

Question 8.
Out of Sodium, Calcium, Aluminium, Copper and Magnesium name the metal which reacts with
(i) Boiling water
Answer:
Magnesium

(ii) Steam.
Answer:
Copper.

Question 9.
Sodium metal is kept under kerosene oil, why?
Answer:
This is because sodium reacts with moist air as well as water.

Question 10.
A non-metal X, exists in two forms Y and Z. Y is the hardest substance and Z is a poor conductor of electricity. What are X, Y and Z?
Answer:
Y = Diamond Z = Graphite X = Carbon
Y and Z are allotropic forms of carbon.

Question 11.
An element, A form two oxides AO and AOa. AO is neutral and AO2 is acidic : Indicate whether A is metal or non-metal.
Answer:
A is non-metal.

Question 12.
Name the reaction to convert metal into its oxide .
Answer:
Oxidation.

Question 13.
Ionic solids have high melting points, why?
Answer:
In ionic solids, there are strong electrostatic forces of attraction between the oppositely charged ions and a large amount of energy required to overcome these forces.

Question 14.
An element X reacts with oxide to form oxide, X2O which dissolves in water and turns red litmus solution blue. Give the nature of oxide and indicate X is metal or non-metal.
Answer:
X2O is basic. X is metal.

Question 15.
What is the nature of metal oxides?
Answer:
Basic.

Question 16.
Name two noble metals.
Answer:
Gold and platinum.

Question 17.
Name an ore of mercury.
Answer:
Mercury sulphide (Hgs).

Question 18.
Name two metalloids.
Answer:
Arsenic, antimony.

Question 19.
Metals lose lustre when placed in air, why?
Answer:
This is because their surfaces are covered with oxides, carbonates or sulphide layer’s .

Question 20.
Name two metals which can be cut with a knife.
Answer:
Sodium and potassium.

Question 21.
Why do metals aquire different shapes?
Answer:
This is due to malleability and ductility of metals.

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 22.
Name the metal which is poor conductor of heat.
Answer:
Lead.

Question 23.
Name the metal which offers resistance to the flow of electricity.
Answer:
Mercury.

Question 24.
Which of the following metals can be drawn into wires?
Answer:
Cu, Al, Fe, Pb.

Question 25.
Name four non-metals which are solid at room temperature.
Answer:
Carbon, Sulphur, Phosphorous, and iodine.

Question 26.
Name the elements which are present in abundance in earth’s crust.
Answer:
Oxygen and silicon.

Question 27.
What are alkalies? Give one example.
Answer:
Alkali. It is a metal hydroxide soluble in water Example : Sodium hydroxide (NaOH).

Question 28.
Name two amphoteric oxide.
Answer:

  1. Aluminium oxide (Al2O3)
  2. Zinc Oxide (ZnO)

Question 29.
What happens when magnesium is heated to ignition temperature?
Answer:
Magnesium burns with white light producing magnesium oxide.

Question 30.
Name the metal which does not react with dil. HCl.
Answer:
Copper.

Question 31.
Name two metals which react with hydrogen.
Answer:
Sodium and potasium.

Question 32.
Give the reaction when a piece of Calcium reacts with water.
Answer:
Ca + 2H2O → Ca (OH)2 + 4H2.

Question 33.
Give the reactions when red hot iron reacts with steam.
Answer:
Ca + 4H2O → Fe3O4 + H2.

Question 34.
Why is zinc oxide called amphoteric oxide?
Answer:
This is because zinc oxide reacts with both acid as well as base.

Question 35.
The metals Na, K and Ca react with hydrogen to form hydroxide but other metals don’t, why?
Answer:
This is because Na, K and Ca are highly reactive metals.

Question 36.
Give the reactions which occur when zinc plate is added to copper sulphate solution.
Answer:
Zn + CuSO4 → ZnSO4 + Cu.

Question 37.
Out of the metals, Na, Cu, Au, which is
(i) Most reactive and
Answer:
Most reactive metal-Sodium (Na)

(ii) Least reactive?
Answer:
Least reactive metal-Gold (Au).

Question 38.
Arrange the following metals in the decreasing order of reactivity, Zinc, Mercury and Aluminium.
Answer:
Al < Zn < Hg.

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 39.
Name two metals which occur in free state in nature.
Answer:
Gold and Platinum.

Question 40.
Define corrosion of metals.
Answer:
It is the interaction of surface of metal with air and moisture forming a layer of oxide, halide or carbonate layer on its surface.

Question 41.
Name a metal which undergoes corrosion in air.
Answer:
Iron.

Question 42.
Name two metals which are not corroded easily.
Answer:
Gold and silver.

Question 43.
Why does copper utensils turn green on exposure to air?
Answer:
Copper reacts with oxygen, carbon dioxide and moisture to form a green coloured compound (basic copper carlxmate):
PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals 38

Question 44.
Name two metals which are both malleable and ductile.
Answer:

  1. Copper
  2. Aluminium.

Question 45.
Name the most abundant metal in the earth’s crust.
Answer:
Aluminium.

Question 46.
Name the metal that gives a green coating when exposed to moisture.
Answer:
Copper.

Question 47.
Which is the most lightest metal known to us?
Answer:
Lithium.

Question 48.
Name two metals which occur in free state in nature.
Answer:

  1. Gold
  2. Platinum.

Question 49.
Name one of the most common ore of aluminium.
Answer:
Bauxite (Al2O3. 2H2O).

Question 50.
What is an amalgam?
Answer:
An amalgam is an alloy of mercury with some other metals.

Question 51.
Name two metals which :
(a) readily burn in air an
Answer:
Metals which readily burn in air are :

  1. sodium
  2. magnesium.

(b) do not burn.
Answer:
metals which do not burn readily in air are :

  1. Copper
  2. iron.

Question 52.
Name the metal which is best conductor of electricity.
Answer:
Silver.

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 53.
Name one metal which reacts with cold water.
Answer:
Sodium.

Question 54.
Name one metal
(i) more reactive than hydrogen and
Answer:
Sodium

(ii) less reactive than hydrogen.
Answer:
Silver.

Question 55.
Write the chemical name of any one compound ore of sulphur.
Answer:
Zinc sulphide (ZnS).

Question 56.
Name the metal used in galvanisation of iron.
Answer:
Zinc.

Question 57.
The metal which is found in nature in the free state is
Answer:
Gold and Platinum.

Question 58.
What chemical process is used for obtaining a metal from its oxide?
Answer:
Reduction process.

Question 59.
Which metals do not corrode easily?
Answer:
The metals which are not attacked by air and moisture don’t corrode easily.

Multiple Choice Questions :

Question 1.
The non-metal which is liquid at room temperature is:
(A) Chlorine
(B) Bromine
(C) Fluorine
(D) Iodine.
Answer:
(B) Bromine

Question 2.
Most reactive metal is:
(A) Na
(B) Mg
(C) Au
(D) K
Answer:
(D) K

Question 3.
The property due to which metals can be beaten into sheets is :
(A) Malleability
(B) Ductility
(C) Metallic lustre
(D) Hardness.
Answer:
(A) Malleability

Question 4.
The axnphoteric oxide is:
(A) ZnO
(B) BaO
(C) K2O
(D) Na2O.
Answer:
(A) ZnO

PSEB 10th Class Science Important Questions Chapter 3 Metals and Non-metals

Question 5.
Copper gets covered with green layer when exposed to air due to the formation of:
(A) CuSO4
(B) CuCO3. Cu(OH)2
(C) Cu (NO3)2
(D) CuO.
Answer:
(B) CuCO3. Cu(OH)2

Question 6.
During galvanisation, the metal whose layer is deposited is:
(A) Gallium
(B) Aluminium
(C) Zinc
(D) Silver.
Answer:
(C) Zinc

Fill in the blanks:

Question 1.
Brass is an alloy of copper and ____________
Answer:
Zinc.

Question 2.
____________ is the best conductor of electricity.
Answer:
Silver.

Question 3.
All the ores are ____________
Answer:
Minerals.

Question 4.
Copper can be refined by ____________
Answer:
Electrorefining.

PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals

Punjab State Board PSEB 10th Class Science Book Solutions Chapter 3 Metals and Non-metals Textbook Exercise Questions and Answers.

PSEB Solutions for Class 10 Science Chapter 3 Metals and Non-metals

PSEB 10th Class Science Guide Acids, Bases and Salts Textbook Questions and Answers

Question 1.
Which of the following pairs will give displacement reactions :
(а) NaCl solution and copper metal
(b) MgCl2 solution and aluminium metal
(c) FeSO4 solution and silver metal
(d) AgNO3 solution and copper metal?
Answer:
(d) AgNO3 solution and copper metal?

Question 2.
Which of the following methods is suitable for preventing an iron frying pan from rusting :
(a) applying grease
(b) applying paint
(c) applying a coating of zinc
(d) all of the above :
Answer:
(c) applying a coating of zinc

Question 3.
An element reacts with oxygen to give a compound with a high melting point. This compound is also soluble in water. The element is likely to be :
(a) calcium
(b) carbon
(c) silicon
(d) iron.
Answer:
(a) calcium

Question 4.
Food cans are coated with tin and not with zinc because :
(а) zinc is costlier than tin
(b) zinc has a higher melting point than tin
(c) zinc is more reactive than tin
(d) zinc is less reactive than tin.
Answer:
(c) zinc is more reactive than tin

PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals

Question 5.
You are given a hammer, a battery, a bulb, wires and a switch.
(i) How could you use them to distinguish between samples of metals and non-metals?
(ii) Assess the usefulness of these tests in distinguishing between metals and non-metals.
Answer:
(i) Set up the electric circuit as shown below :
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 11
To distinguish between metals and non-metals on the basis of their electrical conductivity.

Insert the sample to be tested between clips A and B
If the bulbs glows, the sample is metal.
If the bulb does not glow, the sample is non-metal.
Thus metals are good conductors of electricity whereas non-metals are poor conductors of electricity.

(ii) If a substance produces a sound when struck beating with a hammer, it is a metal and if no sound is produced, it is a non-metal.
Metals are sonorous whereas non-metals are non-sonorous.

Question 6.
What are amphoteric oxides? Give two examples of amphoteric oxides.
Answer:
Amphoteric oxides. The metal oxide which react both with acids as well as bases to produce salts and water are known as amphoteric oxides.

Examples. Zinc oxide, ZnO Aluminium oxide, Al2O3

Question 7.
Name two metals which will displace hydrogen from dilute acids, and two metals which will not.
Answer:
Zinc and magnesium can displace hydrogen from dilute acids. Copper and silver cannot displace hydrogen from dilute acids.

Question 8.
In the electrolytic refining a metal M, what would you take as the anode, the cathode and the electrolyte?
Answer:
During the electrorefining of metal, the impure metal is made as anode, a thin strip of pure metal M is made as cathode. The electrolyte used a soluble salt of metal M. to be refined.

Question 9.
Pratyush took sulphur powder on a spatula and heated it. He collected the gas evolved by inverting a test tube over it as shown in figure
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 12
Collection of Gas
(a) What will be the action of gas on
(i) dry litmus paper?
Answer:
No action.

(ii) moist litmus paper?
Answer:
It turns moist litmus paper red and then bleaches it.

(b) Write a balanced chemical equation for the reaction taking place.
Answer:
S + O2 → SO2

Question 10.
State two ways to prevent the rusting of iron.
Answer:
The rusting can be prevented by

  1. By painting, oiling, greasing, galvanising, chrome plate or anodising.
  2. By forming alloys.

Question 11.
What type of oxides are formed when non-metals combine with oxygen?
Answer:
As they form two types of oxides :
(a) Neutral oxides such as CO, NO etc.
(b) Acidic oxides such as SO2, CO2 etc.

Question 12.
Give reasons :
(a) Platinum, gold and silver are used to make jewellery.
Answer:
Platinum, gold and silver are used to make jewellery because these are not attacked by air and moisture. They don’t undergo corrosion and retain their lustre for a long time. Also these metals are malleable and ductile.

(b) Sodium, potassium and lithium are stored under oil.
Answer:
Sodium, potassium and lithium are stored under oil because in contact with moist air containing carbon dioxide, these are covered with a carbonate layer.
e.g. 4Na + O2 → 2Na2O
Na2O + H2O → 2NaOH
2NaOH + CO2 → Na2CO3 + H2O

Also they react with water.
e.g. 2Na + 2H2O → 2NaOH + H2.
Hence, these metals are stored under oil.

(c) Aluminium is a highly reactive metal, yet it is used to make utensils for cooking.
Answer:
This is due to the reason that a thin sticking oxide layer of aluminium is formed on its surface which prevents further reaction. Also aluminium is a good conductor of heat and the oxide layer (Al2O3) is stable even at high temperatures.

(d) Carbonate and sulphide ores are usually converted into oxides during the process of extraction.
Answer:
This is because it is easier to obtain a metal from its oxide as compared to its sulphide and carbonate ore.

Question 13.
You must have seen tarnished copper vessels being cleaned with lemon or tamarind juice. Explain why these sour substances are effective in cleaning the vessels.
Answer:
In tarnished copper vessel there is a layer of basic copper carbonate. This basic layer can be cleaned by using sour substances such as lemon or tamarind juice which are acidic in nature and dissolve the basic coat of copper carbonate

PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals

Question 14.
Differentiate betw een metals and non-metals.
Or
Differentiate between metals and non-metals on the basis of their chemical properties.
Answer:
Differences between metals and non-metals :

Metals Non-Metals
1. They form basic oxides. 1. They form acidic or neutral oxides.
2. They displace hydrogen from dilute acids. 2. They don’t displace hydrogen from dilute acids.
3. Usually they don’t combine with hydrogen. Only a few reactive metals combine with hydrogen to form metal hydroxide which are electrovalent compounds. 3. They react with hydrogen to form hydrides which are covalent compounds.
4. They form chlorides which are electrovalent compounds. 4. They react with chlorine to form chlorides which are covalent compounds.

Question 15.
A man went door to door posing as a goldsmith. He promised to bring back the glitter of old and dull gold ornaments. An unsuspecting lady gave a set of gold bangles to him which he dipped in a particular solution. The bangles sparkled like new but their weight was reduced drastically. The lady was upset but after a futile argument the man beat a hasty retreat. Can you play the detective to find out the nature of the solution he had used?
Answer:
The solution used by goldsmith to bring back the glitter of old and dull gold ornaments was aqua regia. It is a freshly prepared mixture of cone. HCl and cone. HNOg in the ratio 3 : 1. It can dissolve gold,

Question 16.
Give the reasons why copper is used to make hot water tanks but steel (an alloy of iron) is not.
Answer:
This is because iron present in steel reacts with steam to form ferrosoferric oxide whereas copper has no action with water. As a result of it, the body of the steel tank becomes weaker and weaker in case of iron and not in case of copper.
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 13

Science Guide for Class 10 PSEB Metals and Non-metals InText Questions and Answers

Question 1.
Give an example of a metal which :
(i) is a liquid at room temperature
Answer:
Mercury

(ii) can be easily cut with a knife
Answer:
Sodium

(iii) it is the best conductor of heat
Answer:
Silver

(iv) is a poor conductor of heat.
Answer:
Lead.

Question 2.
Explain the meaning of malleable and ductile.
Answer:
Malleable: A substance is said to be malleable, if it can be beaten into sheets. e.g. metals are malleable.
Ductile: A substance is said to be ductile, if it can be drawn into wires e.g. the metals are ductile.

Question 3.
Why is sodium kept immersed in kerosene oil?
Answer:
This is because in contact with moist air containing carbon dioxide, it is covered with a carbonate layer.
4Na + O2 → 2Na2O
Na2O + H2O → 2NaOH
2NaOH + CO2 → Na2CO3 + H2O

Also sodium reacts with water.
2Na + 2H2O → 2NaOH + H2
Hence, sodium is kept immersed in kerosene oil.

PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals

Question 4.
Write equation for the reactions of
(i) iron with steam
Answer:
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 1

(ii) calcium and potassium with water.
Answer:
Ca + 2H2O → Ca(OH)2 + H2
2K + 2H2O → 2KOH + H2

Question 5.
Samples of four metals A, B, C and D were taken and added to the following solution one by one. The results obtained have been tabulated as follows :
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 2
Use the table above to answer the following questions about metals, A, B, C and D.
(i) Which is the most reactive metal?
Answer:
B is the most reactive metal.

(ii) What would you observe if B is added to a solution of copper (II) sulphate?
Answer:
B will displace copper from copper sulphate solution.

(iii) Arrange the metals A, B, C and D in the order of decreasing reactivity.
Answer:
The decreasing order of reactivity is B > A > C > D.

Question 6.
Which gas is produced when dilute hydrochloric acid is added to a reactive metal? Write the chemical reaction when iron reacts with dilute H2SO4.
Answer:
Hydrogen gas is produced when dilute hydrochloric acid is added to a reactive metal.
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 3

Question 7.
What would you observe when zinc is added to a solution of iron (II) sulphate? Write the chemical reaction that takes place.
Answer:
When zinc is added to a solution of iron (II) sulphate it will displace iron from it and light green colour of solution gradually fades away.
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 4

Question 8.
(i) Write the electron-dot structures for sodium, oxygen and magnesium.
Answer:
Electron-dot structures for sodium, oxygen and magnesium are
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 5

(ii) Show the formation of Na2O and MgO by the transfer of electrons.
Answer:
Formation of Na2O:
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 6

(iii) What are the ions present in the above compounds?
Answer:
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 7

Question 9.
Why do ionic compounds have high melting points?
Answer:
In ionic compounds there are strong electrostatic forces of attraction between oppositely charged ion and a considerable amount of energy is required to break the strong interionic attraction.

Question 10.
Define the terms :
(a) mineral
Answer:
Mineral. The compounds of elements occurring in earth’s crust which are associated with earthly impurities are called minerals.

(b) ore
Answer:
Ore. An ore is a mineral from which metal can be extracted conveniently and economically.

(c) gangue.
Answer
Gangue. The earthly impurities such as sand, lime stone, rocks etc. associated with minerals and ores are collectively known as gangue or matrix.

Question 11.
Name two metals which are found in nature in the free state.
Answer:
Gold and Platinum.

PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals

Question 12.
What chemical process is used for obtaining a metal from its oxide?
Answer:
Reduction process.

Question 13.
Metallic oxides of zinc, magnesium and copper were heated with the following metals :

Metal Zinc Magnesium Copper
Zinc oxide
Magnesium oxide
Copper oxide

In which cases will you find displacement reactions taking place?
Answer:
Zinc can displace copper from copper oxide
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 8
Magnesium can displace zinc from zinc oxide
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 9
Also Mg can displace copper from CuO
PSEB 10th Class Science Solutions Chapter 3 Metals and Non-metals 10

Question 14.
Which metals do not corrode easily?
Answer:
The metals which are not attacked by air and moisture don’t corrode easily.

Question 15.
What are alloys?
Answer:
Alloys. These are the homogeneous mixtures of two or more metals or metals and non-metals.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Punjab State Board PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom Important Questions and Answers.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Long Answer Type Questions:

Question 1.
What is Rutherford’s ∝-ray scattering experiment? Give its observations. How does Rutherford explain this observation?
Answer:
Rutherford’s ∝-ray scattering experiment: In this experiment, Rutherford obtained a thin stream of fast-moving alpha (∝) particles from radioactive source (P0) and was allowed to strike against a thin foil of heavy metal like gold. Alpha particles are also called helium nuclei (He2+ with + 2 unit charge and 4 a.m.u. mass). As a result of the experiment, he made the following observations:

  1. Most of the ∝-particles passed through the gold foil without any deflection from their original path.
  2. Some of the ∝-particles got deflected by small angles from their original path.
  3. A few ∝-particles (approximately 1 out of 10,000) were deflected to a large extent. In some cases, the a-particles came back in the same direction after striking the gold foil.

Explanation for the observations:

We know that the gold foil is made up of atoms of gold which are placed side by side. Since most of the ∝-particles passed through these atoms undeflected they did not come across any obstruction in their path, this shows that most of the space in the atom is light or hollow.

The electrons with negligible mass were supposed to be present in this portion called extra nuclear portion. The a-particies were deflected from their path and a very few came back in the same direction. This shows that they must have met with some obstruction in their path.
The obstruction must be
1. Heavy because a-particles are high speed particles and can remove light obstruction from their path.
2. Small because only a few a-particles got deflected.
3. Positively charged because some a-particles were repelled by this obstruction.
PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 1
This small, heavy and positively charged portion inside an atom was called nucleus. The protons with mass and positive charge were supposed to be present in the nucleus. Later on, neutrons were also found to be present in the nucleus of the atom.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 2.
Discuss in brief Rutherford’s Model of atom.
Answer:
The main points of Rutherford’s model of atom are listed as follows:
1. An atom has two parts. These are nucleus and extra nuclear portion.
2. The nucleus contains protons while electrons are present in the extra nuclear portion.
3. Most of the mass of the atom is due to the nucleus because electrons have negligible mass.
PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 2
4. The volume occupied by the nucleus is very small as compared to the volume occupied by extra nuclear portion.
5. The electrons in the extra nuclear portion are not stationary. These are revolving around the nucleus. The electrons are called planetary electrons because they can be compared to various planets which revolve around the sun. The nucleus may be compared with the sun.

Question 3.
Discuss the arrangement of the electrons in the different energy levels.
Or
Describe Bohr-Bury scheme for the distribution of electrons in the various orbits or energy levels of an atom.
Answer:
The distribution of electrons in the energy levels is given with the help of Bohr Bury scheme. It is given as follows:
1. The energy levels or energy shells are filled in order of increasing energies. The electrons first enter the K shell (n = 1. which is closest to the nucleus. This is followed by L shell (n = 2), M shell (n = 3) and so on. Here V represents the number of the shell.
2. The maximum number of electrons in any shell is given as 2n2 (n = number of the shell). The distribution in the first four energy shells is given in the table given below:
Distribution of electrons in first four energy shells according to 2n2 rule.

Symbol of shell Number of shell (n) Maximum number of electrons (2n2)
K 1 2 x (1)2 = 2
L 2 2 x (2)2 = 8
M 3 2 x (3)2 = 18
N 4 2 x (4)2 = 32

3. The outermost energy shell cannot have more than 8 electrons. The next inner shell called penultimate shell, cannot have more than 18 electrons.
4. It is not necessary that an energy level or shell is fully filled before the filling in the next energy level starts. In fact, filling of electrons in a new shell starts when any shell contains 8 electrons.
On the basis of the above scheme, let us discus with mass number 24 and atomic number 12.
PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 3

  • Mass no. of atom (A) = 24
  • Atomic no. of atom (Z) = 12
  • No. of protons in nucleus = 12
  • No. of neutrons in nucleus = 12
  • No. of electrons to be distributed = 12
  • The distribution in the various energy shells: K L M: 2, 8, 2

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 4.
Give the electronic distribution in the first twenty elements on the basis of Bohr-Bury scheme.
Answer:
On the basis of Bohr-Bury scheme, the distribution of electrons in first twenty elements (Z = 1 to Z = 20) is given below:
Table: Electronic distribution in atoms of first 20 elements

Element (Symbol) Mass No. (A) Atomic No. (Z) No. of Protons (P) No. of Electrons (e) No. of Neutrons (n) (A-Z) Electronic Distribution
K L M N
1. Hydrogen (H) 1 1 1 1 0 1
2. Helium (He) 4 2 2 2 2 2
3. Lithium (Li) 7 3 3 3 4 9 1
4. Beryllium (Be) 9 4 4 4 5 2 2
5. Boron (B) 11 5 5 5 6 2 3
6. Carbon (C) 12 6 6 6 6 2 4
7. Nitrogen (N) 14 7 7 7 7 2 5
8. Oxygen (O) 16 8 8 8 8 2 6
9. Fluorine (F) 19 9 9 9 10 2 7
10. Neon (Ne) 20 10 10 10 10 2 8
11. Sodium (Na) 23 11 11 11 12 2 8 1
12. Magnesium (Mg) 24 12 12 12 12 9 8 2
13. Aluminium (Al) 27 13 13 13 14 ‘ 2 8 3
14. Silicon (Si) 28 14 14 14 14 2 8 4
15. Phosphorus (P) 31 15 15 15 16 2 8 5
16. Sulphur (S) 32 16 16 16 16 2 8 6
17. Chlorine (Cl) 35 17 17 17 18 2 8 7
18. Argon (Ar) 40 18 18 18 22 2 8 8
19. Potassium (K) 39 19 19 19 20 2 8 8 1
20. Calcium (Ca) 40 20 20 20 20 2 8 8 2

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 4
Special cases of Potassium and Calcium:

  • In case of Potassium (Z = 19), the M shell has only 8 electrons and not 18. Actually, when the M shell gets 8 electrons, the filling of electrons starts in the next shell which is N-shell. When the N-shell gets 2 electrons, the electron are again- filled in the M shell.
  • Thus, electronic distribution in potassium (Z = 19) is
    K L M N
    2 8 8 1 (M shell has 8 electrons and N shell has 1 electron)
  • Similarly, the electronic distribution in calcium (Z = 20) is:
    K L M N: 2 8 8 2 (M shell has 8 electrons and N shell has 2 electrons)

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 5.
Define the terms:

  1. Atomic number
  2. Mass number
  3. Atom
  4. Ion
  5. Element
  6. Orbit
  7. Nucleons

Answer:

  1. Atomic number: It is the number of protons present in the nucleus of an atom of the element.
  2. Mass number: It is the sum of number of protons and neutrons present in the nucleus of an atom of the elements.
  3. Atom: It is the smallest unit of matter which takes part in chemical reactions and it may or may not exist independently.
  4. Ion: It is an atom or group of atoms having charge positive or negative and can exist freely in solution.
  5. Element: It is a pure substance which can neither be built up nor broken into two or more still simpler substance by any physical or chemical method and it consists of only one kind of atoms.
  6. Orbit: It is the fixed circular path traced by an electron revolving around the
  7. Nucleons: The protons and neutrons present in the nucleus of an atom of the element are collectively known as nucleons.u

Short Answer Type Questions:

Question 1.
What do you understand by the structure of atom?
Answer:
According to the Dalton’s atomic theory, the smallest particle of matter is called atom. But later studies have shown that an atom is further made up of sub-atomic particles called electrons, protons and neutrons. Different atoms have different number of such particles and they also differ in the arrangement of these particles. Therefore, the atoms have different properties.

Question 2.
What happens when electric field is applied to the path of cathode rays? What does it show?
Answer:
When electric field is applied to the path of the cathode rays, these are deflected towards the positive plate of the field. This shows that the cathode rays consist of negatively charged particles.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 3.
What is the information conveyed by the following observations :

  1. Atom is electrically neutral,
  2. Mass of the atom is due to the nucleus.

Answer:

  1. If an atom is electrically neutral, this means that it will have equal number of protons and electrons. Both protons and electrons have 1 unit charge but with opposite sign.
  2. This means that nucleus contains in it both protons and neutrons which have mass.

Question 4.
What is the significance of number of protons found in the atoms in each of the different elements?
Answer:
The number of electrons in atom of the element is equal to the number of protons. By knowing no. of protons, we can calculate no. of electrons and hence its properties.

Question 5.
Write the electronic configuration of the elements A, B, C, D, E with atomic numbers 5, 6, 14, 13 and 15. Which have similar chemical properties?
Answer:

Element Atomic No. (Z) Electronic configuration
K L M
A 5 2 3
B 6 2 4
C 14 2 8 4
D 13 ? 8 3
E 15 2 8 5

Elements B and C. have similar chemical properties because both of them have 4 valence elt, trons.
Elements A and D have similar chemical properties because both of them have 3 valence electrons.

Question 6.
Five species P, Q, R, S, T have electrons, protons and neutrons are as follows:

Species Electrons Protons Neutrons
P 4 3 4
Q 8 9 9
R 17 17 20
S 17 17 18
T 18 18 22

Find

  1. a cation
  2. an anion
  3. a noble gas and
  4. a pair of isotopes.

Answer:

  1. Cation – Q
  2. Anion – P
  3. A noble gas = T
  4. Pair of isotopes = R and S (because they have same number of electrons and protons but different number of neutrons).

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 7.
Helium has only 2 electrons in the K-shell. But it is called an inert gas element. Why?
Answer:
Helium (He) atom has only one shell (K-shell) which can have a maximum of 2 electrons only. It cannot have more than 2 electrons. As a result, the combining capacity of He is zero. Therefore, its valency is also zero.

Question 8.
Give labelled diagram to show how are cathode rays produced?
Answer:
PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 5

Question 9.
An atom has mass number A and atomic number Z.
1. How many protons are present in the nucleus?
2. How many electrons are revolving around the nucleus?
3. How many neutrons are present in its nucleus?
Answer:
Mass number = A
Atomic number = Z
1. No. of protons present in the nucleus = Z
2. No. of electrons revolving around the nucleus = Z
3. No. of neutrons present in the nucleus = A – Z.

Question 10.
State three ways by which a proton differs from an electron.
Answer:

Proton Electron
1. It has one unit of positive charge.

2. It has mass 1.6 x 10-24 g.

3. It is present in the nucleus of an atom.

It has one unit of negative charge.

It has mass 9.1 x 10″28 g.

It is present in the extranuclear part of an atom.

Question 11.
What are isotopes? Give two uses of isotopes. Name the isotopes of hydrogen. Give their structures.
Answer:
Isotopes. The atoms of the same element having the same atomic number but different mass numbers are called isotopes.
Use of isotopes:
1. Isotopes of hydrogen, oxygen, carbon are used to study the mechanisms of organic reactions.
2. Some radioactive isotopes are used for the treatment of cancer and other diseases. The isotopes of hydrogen are:
PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 6

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 12.
Explain why elements have fractional atomic masses?
Answer:
The elements have fractional atomic masses due to the existence of isotopes (having different mass numbers) e.g. chlorine has two isotopes \({ }_{17}^{35} \mathrm{Cl}\) and \({ }_{17}^{37} \mathrm{Cl}\) and are present in the ratio 3:1.
∴ Average atomic mass of chlorine = \(\frac{35 \times 3+37 \times 1}{4}=\frac{105+37}{4} \) = 35.5 a.m.u.

Question 13.
What are isobars? Give examples.
Answer:
The atom of different elements having same mass numbers but different atomic numbers are called isobars.
e.g. 1. \({ }_{18}^{40} \mathrm{Ar}\) and \({ }_{19}^{40} \mathrm{Ar}\)
2. \({ }_{36}^{86} \mathrm{Ar}\) and \({ }_{38}^{86} \mathrm{Ar}\)

Question 14.
Sulphur has an atomic number 16 and a mass of 32. State the number of protons and neutrons in the nucleus of sulphur. Give a simple diagram to show the arrangement of electrons in an atom of sulphur.
Answer:
PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 7
Atomic number of S = 16
Mass number of S = 32
∴ No. of protons = 16
No. of neutrons = 32 – 16 = 16
No. of electrons = 16

Question 15.
Write down the electronic configuration of the following:
1. \({ }_{13}^{27} \mathrm{X}\)
2. \({ }_{17}^{35} \mathrm{X}\)
Write down the number of electrons in X and neutrons in Y and the formula of
compound formed by X and Y.
Answer:
1. \({ }_{13}^{27} \mathrm{X}\)
Atomic number of X = 13
Mass number of X =27
No. of protons in X = 13
∴ No. of electrons in X = 13
The electronic configuration of X = 2, 8, 3
Valency of X = 3

2. \({ }_{17}^{35} \mathrm{X}\)
Atomic number of Y = 17
Mass number of Y =35
No. of protons in Y = 17
No. of electrons in Y = 17
No. of neutrons in Y = 35 – 17 = 18
The electronic co0nfiguration of Y = 2, 8, 7
Valency of Y = 1
The formula of the compound formed by X and Y
PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 8

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 16.
Give the important properties or characteristics of isotopes.
Answer:

  1. The isotopes of an element have same atomic number (Z) i.e. the same number of electrons and same number of protons. Hence, they have identical chemical properties.
  2. Isotopes of an element have same number of valence electrons and hence same valency.
  3. Isotopes of an element have different mass numbers (or different number of neutrons) and hence they have different physical properties such as mass, density, melting point, boiling point etc.

Question 17.
An atom of the element is represented as 11x?

  1. What does the numeral 23 indicate?
  2. What does the nemeral 11 indicate?
  3. What is the number of protons in X?

Answer:

  1. 23 indicates mass number of X.
  2. 11 indicates atomic number of X.
  3. No. of protons in X = Atomic number = 11.

Question 18.
The atom of an element is made up of 4 protons, 5 neutrons and 4 electrons. what are its atomic number and mass number?
Answer:
No. of proton = 4
Atomic number of the element, Z = 4
No. of neutrons = 5
∴ No. of protons + No. of neutrons =4 + 5 = 9
∴ Mass number of the element, A = 9.

Question 19.
Calculate the number of neutrons in the following elements:
1. \({ }_{1}^{3} \mathrm{Cl}\)
2. \({ }_{17}^{37} \mathrm{Cl}\)
3. \({ }_{20}^{40} \mathrm{Cl}\)
Answer:
1. \({ }_{1}^{3} \mathrm{Cl}\)
Mass number = 3
Atomic number = 1
No.of neutrons = Mass no – Atomic no.
= 3 – 1 = 2

2. \({ }_{17}^{37} \mathrm{Cl}\)
Mass number = 37
Atomic number = 17
No.of neutrons = 37 – 17 = 20

3. \({ }_{20}^{40} \mathrm{Cl}\)
Mass number = 40
Atomic number = 20
No.of neutrons = 40 – 20 = 20

Question 20.
Give two conditions under which cathode rays are produced.
Answer:
Cathode rays are produced when a gas is subjected to the action of
1. High voltage of the order of 5000-10000 V and
2. Under a low pressure of the order of 10-3 atm of Hg.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 21.
The electronic configuration of P (Z = 15) is 2, 8, 5. Why is the valency of phosphorus 3 and not 5?
Answer:
The electronic configuration of phosphorus (P) shows that it has 5 valence electrons. Its valency is expected to be 5. But it is not possible for the atom to lose 5 electrons present in the valence shell because the energy required to remove these electrons will be very high. Therefore, phosphorus atom has valency equal to 3 because to gain 3 electrons is easier than losing 5 electrons as it requires less energy.

Question 22.
What information is conveyed by the statement that the mass number of magnesium is 24 and the atomic number is 12?
Answer:
The atomic number (12) of magnesium indicates that its atom has 12 protons in the nucleus and an equal number of electrons in the extra nuclear portion. The mass number (24) points out that there are also 12 neutrons (24 – 12 = 12) present in the nucleus alongwith protons.

Question 23.
Is it possible for an atom to have 12 protons and 13 electrons? Explain.
Answer:
No, it is not possible. An atom must always be electrically neutral. This means that it has no net charge present on it. Now, each proton has one unit positive charge and each electron has one unit negative charge. In a neutral atom, the number of electrons and protons must always be the same. Thus, an atom cannot have 12 protons and 13 electrons.

Question 24.
Give the important isotopes of hydrogen, carbon, oxygen and chlorine. Indicate their mass numbers and atomic numbers.
Answer:
PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 9

Numerical Problems (Solved):

Question 1.
Chlorine has two isotopes \({ }_{17}^{35} \mathrm{Cl}\) and \({ }_{17}^{37} \mathrm{Cl}\) in the ratio 3 : 1. Calculate the average atomic mass of chlorine.
Solution:
PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 10

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 2.
Out of 18X and 16Y which atom is chemically more reactive?
Solution:
PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom 11
No. of valence electrons in X =8
No. of valence electrons in Y =6
∴ Y is more reactive.

Question 3.
An element has 12 neutrons and mass number 23. Give the atomic number and symbol of the element.
Solution:

  • Mass number(A) = 23
  • Number of neutrons = 12
  • Number of protons = 23 – 12 = 11
  • Atomic Number(Z)= 11
  • Symbol of the element = \(\frac{23}{11} \mathrm{Na}\)

Question 4.
Calculate number of protons, neutrons and electrons in \(\frac{235}{92} \mathrm{U}\) and \(\frac{238}{92} \mathrm{U}\). How are these atoms related?
Solution:
table
\(\frac{235}{92} \mathrm{U}\) and \(\frac{238}{92} \mathrm{U}\) are isotopes.

Question 5.
Calculate the number of electrons, protons and neutrons is \(\frac{19}{9} \mathrm{U}\). Also calculate its valency.
Solution:

  1. Atomic number = 9
  2. Mass number = 19
  3. No. of protons = 9
  4. No. of neutrons = 19 – 9 = 10
  5. Electronic configuration = 2 7
  6. Valency = 8 – 7 = 1.

Very Short Answer Type Questions

Question 1.
Who discovered canal rays?
Answer:
Goldstein discovered canal rays in 1886.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 2.
Which charge is present on canal ray particles?
Answer:
They carry positive charge.

Question 3.
Which charge is present on protons?
Answer:
Positive charge.

Question 4.
Where are protons present in an atom?
Answer:
Protons are present in the nucleus, deep inside the atom.

Question 5.
What were the characteristics of an atom according to Dalton?
Answer:
According to Dalton an atom was indivisible and indestructible.

Question 6.
Which discovery is against Dalton’s theory?
Answer:
Discovering of electrons and protons in an atom.

Question 7.
Who proposed the first model for the structure of atom?
Answer:
J.J. Thomson.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 8.
Why did Rutherford used gold foil in a-ray scattering experiment?
Answer:
This is because he wanted as thin a layer as possible. It was about 1000 atoms thick.

Question 9.
What are α-particles?
Answer:
They are doubly charged helium ions (He2+).

Question 10.
What is the charge on α-particles?
Answer:
+2 units.

Question 11.
What is the mass of an α-particle?
Answer:
4 u.

Question 12.
How the defects of Rutherford’s model were removed by Neil Bohr?
Answer:
The electrons revolve around the nucleus in an atom in fixed circular paths called orbits or energy levels and don’t lose energy.

Question 13.
What are energy levels or shells?
Answer:
The definite orbits in where electrons revolve around the nucleus are called energy levels. These are designated as K, L, M, N ……………. 1, 2, 3, 4.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 14.
Define mass number of an element.
Answer:
It is the sum of number of neutrons and protons present in the nucleus of the atom of the element.

Question 15.
Who gave the distribution of electrons in the various shells of an atom?
Answer:
Bohr and Bury.

Question 16.
What is the maximum number of electrons present in an electronic shell?
Answer:
2n2 (Where n is the number of shells).

Question 17.
What is the maximum first four shells of an atom?
Answer:
2, 8, 18, 32.

Question 18.
What is the maximum number of electrons in the outermost shell of an atom?
Answer:
8

Question 19.
Which elements are chemically inert?
Answer:
These are the elements which have 8 electrons in their outermost shells.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 20.
Define octet.
Answer:
The maximum number of electrons present in the outermost shell of an atom is called octet.

Question 21.
Define valency of an element.
Answer:
It is the combining capacity of an atom of the element and it is equal to the number of electrons lost or gained or contributed for sharing from its valence shell in order to complete its octet.

Question 22.
Define atomic number.
Answer:
It-is the number of protons present in the nucleus of an atom of the element.

Question 23.
Define nucleon.
Answer:
The neutrons and protons present in the nucleus of an atom of the element are collectively known as nucleons.

Question 24.
Where is most of the mass of the element present?
Answer:
In the nucleus of an atom.

Question 25.
Define atomic mass of an element.
Answer:
It is the sum of the number of neutrons and protons present in the nucleus of its atom.

Question 26.
What are isotopes?
Answer:
Atoms of the same element having same atomic number but different mass numbers are called isotopes.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 27.
Write two isotopes of chlorine.
Answer:
\({ }_{17}^{35} \mathrm{Cl}\) and \({ }_{17}^{37} \mathrm{Cl}\).

Question 28.
Write two isotopes of carbon.
Answer:
\({ }_{6}^{12} \mathrm{Cl}\) and \({ }_{6}^{14} \mathrm{Cl}\).

Question 29.
Isotope of which element is used in the treatment of cancer?
Answer:
Isotope of cobalt (\({ }_{27}^{59} \mathrm{Co}\)).

Question 30.
What is the atomic mass of chlorine?
Answer:
35.5

Question 31.
Isotope of which element is used for the treatment of goitre?
Answer:
An isotope of iodine.

Question 32.
Isotope of which element is used in atomic reactor?
Answer:
Uranium.

Question 33.
What are isobars?
Answer:
Atoms of the different elements having same mass number but different atomic numbers are called isobars.

Question 34.
Give one example of isobars?
Answer:
\(\underset{(\text { Calcium })}{\stackrel{40}{20} \mathrm{Ca}}\) and \(\underset{(\text { Argon })}{\stackrel{40}{18} \mathrm{Ca}}\).

Question 35.
Write three isotopes of hydrogen.
Answer:

  1. Protium (\({ }_{1}^{1} \mathrm{H}\))
  2. Deuterium (\({ }_{2}^{1} \mathrm{H}\))
  3. Tritium (\({ }_{3}^{1} \mathrm{H}\)).

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 36.
What is the total number of electrons in an atom if its K-and L-shells are fully filled?
Answer:
10 (K-2, L-8).

Question 37.
What electrons in an atom influence its chemical properties?
Answer:
Valence electrons (electrons in the outermost shell).

Question 38.
How will you represent chlorine atom having mass number 35 and atomic number 17?
Answer:
\({ }_{17}^{35} \mathrm{Cl}\)

Question 39.
Name the sub-atomic particle on which size of an atom depends?
Answer:
Electron.

Question 40.
Name the atoms having same atomic number but different mass numbers.
Answer:
Isotopes.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 41.
Mg2+ has 10 electrons, what is the number of protons in it?
Answer:
10 + 2 = 12.

Question 42.
Name the element which has no neutrons in the nucleus of its atom.
Answer:
Hydrogen.

Question 43.
Out of electrons, protons and neutrons, which are same in isotopes?
Answer:
Electrons and protons.

Question 44.
There are three isotopes of hydrogen, \({ }_{1}^{1} \mathrm{H},{ }_{1}^{2} \mathrm{H},{ }_{1}^{3} \mathrm{H}\) all are electrically neutral, why?
Answer:
This is because each isotope has one electron and one proton.

Question 45.
An element has atomic number 16. Give its electronic configuration and number of valence electrons.
Answer:
Electronic configuration 2, 8, 6.

Question 46.
The number of electrons in the valence shell of sodium (Na) is ……………… .
Answer:
1.

Question 47.
Fluorine belongs to …………… family.
Answer:
Halogen.

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 48.
In an atom, the number of …………… is the same as the number of ………………. .
Answer:
Electrons, protons

Question 49.
Sodium has …………….. electron …………….. than sodium ion.
Answer:
One, more

Question 50.
Isotopes of an element are …………….. because they have ……….. number of electrons.
Answer:
Chemically similar, same

PSEB 9th Class Science Important Questions Chapter 4 Structure of the Atom

Question 51.
The number of electrons in the valence shell of an atom cannot be ………………..>
Answer:
More than eight.