PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.4

Punjab State Board PSEB 8th Class Maths Book Solutions Chapter 4 Practical Geometry Ex 4.4 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.4

1. Construct the following quadrilaterals:

Question (i).
Quadrilateral DEAR
DE = 4 cm
EA = 5 cm
AR = 4.5 cm
∠E = 60°
∠A = 90°
Solution:
PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.4 1
Steps of construction:

  • Draw a line segment DE = 4 cm.
  • At E, draw \(\overrightarrow{\mathrm{EM}}\) such that ∠DEM = 60°.
  • With E as centre and radius = 5 cm, draw an arc intersecting \(\overrightarrow{\mathrm{EM}}\) at A.
  • At A, draw \(\overrightarrow{\mathrm{AN}}\) such that ∠EAN = 90°.
  • With A as centre and radius = 4.5 cm, draw an arc intersecting \(\overrightarrow{\mathrm{AN}}\) at R.
  • Draw \(\overline{\mathrm{DR}}\).

Thus, DEAR is the required quadrilateral.

PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.4

Question (ii).
Quadrilateral TRUE
TR = 3.5 cm
RU = 3 cm
UE = 4 cm
∠R = 75°
∠U = 120°
Solution:
PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.4 2
Steps of construction :

  • Draw a line segment TR = 3.5 cm.
  • At R, draw a \(\overrightarrow{\mathrm{RM}}\) such that ∠TRM = 75°.
  • With R as centre and radius = 3 cm, draw an arc intersecting \(\overrightarrow{\mathrm{RM}}\) at U.
  • At U, draw \(\overrightarrow{\mathrm{UN}}\) such that ∠RUN = 120°.
  • With U as centre and radius = 4 cm, draw an arc intersecting \(\overrightarrow{\mathrm{UN}}\) at E.
  • Draw \(\overline{\mathrm{ET}}\).

Thus, TRUE is the required quadrilateral.

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