PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1

Punjab State Board PSEB 8th Class Maths Book Solutions Chapter 4 Practical Geometry Ex 4.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.1

1. Construct the following quadrilaterals:

Question (i).
Quadrilateral ABCD.
AB = 4.5 cm,
BC = 5.5 cm,
CD = 4 cm,
AD = 6 cm,
AC = 7 cm.
Solution :
PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 1
Steps of construction:

  • Draw a line segment AB = 4.5 cm.
  • With A as centre and radius = 7 cm, draw an arc.
  • With B as centre and radius = 5.5 cm, draw another arc to intersect previous arc at C.
  • With A as centre and radius 6 cm draw an arc.
  • With centre at C and radius 4 cm, draw another arc to intersect previous arc at D.
  • Draw \(\overline{\mathrm{BC}}, \overline{\mathrm{CD}}, \overline{\mathrm{AD}}\) and \(\overline{\mathrm{AC}}\).

Thus, ABCD is the required quadrilateral.

PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1

Question (ii).
Quadrilateral JUMP
JU = 3.5 cm,
UM = 4 cm,
MP = 5 cm,
PJ = 4.5 cm,
PU = 6.5 cm.
Solution:
PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 2
Steps of construction :

  • Draw a line segment JU = 3.5 cm.
  • With J as centre and radius = 4.5 cm, draw an arc.
  • With U as centre and radius = 6.5 cm, draw another arc to intersect previous arc at P
  • With U as centre and radius = 4 cm draw an arc.
  • With P as centre and radius 5 cm, draw an arc which intersects previous arc at M.
  • Draw \(\overline{\mathrm{JP}}, \overline{\mathrm{UM}}, \overline{\mathrm{MP}}\) and \(\overline{\mathrm{UP}}\).

Thus, JUMP is the required quadrilateral.

PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1

Question (iii).
Parallelogram MORE ?
OR = 6 cm,
RE = 4.5 cm,
EO = 7.5 cm.
Solution:
PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 3
[Note: □ MORE is a parallelogram. So length of opposite sides are equal. ]
∴ RE = MO = 4.5 cm; OR = ME = 6 cm
Steps of construction:

  • Draw a line segment MO = 4.5 cm.
  • With M as centre and radius = 6 cm, draw an arc.
  • With O as centre and radius = 7.5 cm, draw another arc to intersect the previous arc at E.
  • With O as centre and radius = 6 cm, draw an arc.
  • With E as centre and radius = 4.5 cm, draw another arc to intersect the previous arc at R.
  • Draw \(\overline{\mathrm{ME}}, \overline{\mathrm{OR}}, \overline{\mathrm{RE}}\) and \(\overline{\mathrm{OE}}\).

Thus, MORE is the required parallelogram.

PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1

Question (iv).
Rhombus BEST
BE = 4.5 cm,
ET = 6 cm.
Solution:
PSEB 8th Class Maths Solutions Chapter 4 Practical Geometry Ex 4.1 4
[Note : BEST is a rhombus. So length of all four sides are equal.]
BE = 4.5 cm
∴ ES = ST = TB = 4.5 cm
ET = 6 cm (Given)
Steps of construction:

  • Draw a line segment BE = 4.5 cm.
  • With B as centre and radius = 4.5 cm, draw an arc.
  • With E as centre and radius = 6 cm, draw another arc to intersect the previous arc at T.
  • With E as centre and radius = 4.5 cm, draw an arc.
  • With T as centre and radius = 4.5 cm, draw another arc to intersect previous arc at S.
  • Draw \(\overline{\mathrm{BT}}, \overline{\mathrm{ES}}, \overline{\mathrm{ST}}\) and \(\overline{\mathrm{ET}}\).

Thus, BEST is the required quadrilateral.

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