PSEB 7th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3

Punjab State Board PSEB 7th Class Maths Book Solutions Chapter 11 Perimeter and Area Ex 11.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3

1. Find the circumference of circle whose
(i) Radius (r) = 21 cm
(ii) Radius (r) = 3.5 cm
(iii) Diameter = 84 cm
Solution:
(i) Given radius (r) = 21 cm
circumference of circle = 2πr
= 2 × \(\frac {22}{7}\) ×21
= 132 cm

(ii) Given radius (r) = 3.5 cm
Circumference = 2πl
= 2 × \(\frac {22}{7}\) × 3.5
= 22 cm

(iii) Given Diameter (d) = 84 cm
radius (r) = \(\frac{d}{2}=\frac{84}{2}\)
= 42 cm
Circumference = 2πr
= 2 × \(\frac {22}{7}\) × 42
= 264 cm

2. If the circumference of a circular sheet is 176 m, find its radius.
Solution:
Given circumference of circular sheet = 176 m
Let radius = r
So 2πr = 176
r = \(\frac{176}{2 \pi}\)
\(\frac{176}{2 \times \frac{22}{7}}\)
= 28 m

PSEB 7th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3

3. A circular disc of diameter 8.4 cm is divided into two parts what is the perimeter of each semicircular part ?
Solution:
Given diameter of a circular disc = 8.4 cm
radius (r) = \(\frac{8.4}{2}\) = 4.2 cm
Perimeter of semicircular part = πr + 2r
= \(\frac {22}{7}\) × 4.2 + 2 × 4.2
= 22 × 0.6 + 8.4
= 21.6 cm

4. Find the area of the circle having
(i) Radius r = 49 cm
(ii) Radius r = 2.8 cm
(iii) Diameter = 4.2 cm
Solution:
(i) Given radius (r) = 49 cm
Area of circle = πr2
= \(\frac {22}{7}\) × 49 × 49
= 7546 cm2

(ii) Given radius (r) = 2.8 cm
Area of circle = πr2
= \(\frac {22}{7}\) × 2.8 × 2.8
= 24.64 cm2

(iii) Given diameter (d) = 4.2 cm
radius (r) = \(\frac{d}{2}=\frac{4.2}{2}\)
Area of circle = πr2
= \(\frac {22}{7}\) × 2.1 × 2.1
= 13.86 cm2

5. A gardener wants to fence a circular garden of radius 15 m. Find the length of wire, if he makes three rounds offense. Also, find the cost of wire if it costs ₹ 5 per meter (Take π = 3.14).
Solution:
Given radius of circular garden (r) = 15 m
Circumference of the circular garden = 2πr
= 2 × 3.14 × 15
= 94.2 m
So, length of the wire to make three rounds offense
= 3 × 94.2
= 282.6 cm
Cost of wire= ₹ 5 × 282.6
= ₹ 1413

PSEB 7th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3

6. Which of the following has larger area and by how much ?
(a) Rectangle with length 15 cm and breadth 5.4 cm
(b) Circle of diameter 5.6 cm.
Solution:
(a) Given length of rectangle = 15 cm
breadth = 5.4 cm
Area of rectangle = length × breadth
= 15 × 5.4
= 81 cm2

(b) Given diameter of circle (d) = 5.6 cm
radius (r) = \(\frac{d}{2}=\frac{5.6}{2}\)
= 2.8 cm
Area of the circle = πr2
= \(\frac {22}{7}\) × (2.8)2
= 24.64 cm2
Hence, Rectangle has more area = 81 – 24.64
= 56.36 cm2

7. From a rectangular sheet of length 15 cm and breadth 12 cm a circle of radius 3.5 cm is removed. Find the area of remaining sheet.
Solution:
Given length of rectangular sheet = 15 cm
Breadth of rectangle sheet = 12 cm
Area of rectangular sheet = length × breadth
= 15 × 12
= 180 cm2
Given radius of circle (r) = 3.5 cm
Area of circle = πr2
= \(\frac {22}{7}\) × (3.5)2
= 38.5 cm2
Since circle is removed from rectangular sheet.
So, area of remaining sheet = Area of rectangular Sheet – Area of circle
= 180 – 38.5
= 141.5 cm2

8. From a circular sheet of radius 7 cm, a circle of radius 2.1 cm is removed, find the area of remaining sheet.
Solution:
Radius of the circular sheet = 7 cm
Area of the circular sheet = 1 cm
= πr2 = \(\frac {22}{7}\) × 7 × 7 cm2
=154 cm2
Radius of the circle = 2.1 cm
Area of the circle
\(\frac {22}{7}\) × 2.1 × 1.1 = \(\frac{22}{7} \times \frac{21}{10} \times \frac{21}{10}\)
= \(\frac {1386}{100}\)
= 13.86 cm2
Area of the remaining sheet = 154 cm2 – 13.86 cm2
= 140.14 cm2

PSEB 7th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3

9. Smeep took a wire of length 88 cm and bent it into the shape of a circle, find the radius and area of the circle. If the same wire is bent into a square, what will be the side of the square ? Which figure encloses more area ?
Solution:
Given length of wire = 88 cm
The wire is bent into the shape of circle.
Circumference of circle = length of the
2πr = 88
r = \(\frac{88}{2 \pi}=\frac{44}{\pi} \mathrm{cm}\)
= 14 cm
Area of the circle = πr2
= π × (14)2
= \(\frac {22}{7}\) × 14 × 14
= 616 cm2
If the same wire is bent into the square
Let side of the square = a
Perimeter of square = length of the wire
4 × a = 88
a = \(\frac {88}{4}\)
= 22 cm
Area of the square = (side)2
= (22)2
= 484 cm2
Hence circle enclosed more area.

10. A garden is 120 m long and 85 m broad. Inside the garden, there is a circular pit of diameter 14 m. Find the cost of planting the remaining part of the garden at the rate of ₹ 5.50 per square meter.
Solution:
Given length of garden = 120 m
Breadth of garden = 85 m
Area of garden = length × breadth
= 120 × 85
= 10200 m2
Given diameter of circular pit (d) = 14 m
radius (r) = \(\frac{d}{2}=\frac{14}{2}\)
= 7 m
Area of circular pit = πr2
= \(\frac {22}{7}\) × 7 × 7
= 154 m2
Remaining part of garden = Area of garden for planting – Area of circular pit
= 10200 – 154
= 10046 m2
Cost of planting the remaining part of the garden
= ₹ 5.50 × 10046
= ₹ 55243

PSEB 7th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3

11. In the figure PQ = QR and PR = 56 cm. The radius of inscribed circle is 7 cm. Q is centre of semicircle. What is the area of shaded region ?
PSEB 7th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3 1
Solution:
Given PQ = QR
PR = 56 cm
Radius of inscribed circle = 7 cm
So PR = PQ + QR
= PQ + PQ = 2PQ
Hence, PQ = \(\frac{\mathrm{PR}}{2}=\frac{56}{2}\)
= 28 cm
So QR = PQ = 28 cm
Area of shaded region = Area of semicircle of diameter PR – Area of semicircle of diameter PQ – Area of semicircle of diameter QR – Area of inscribe circle
PSEB 7th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3 2

12. The minute hand of a circular clock is 18 cm long. How far does the tip of minute hand move in one hour ?
Solution:
Given minute hand of a circular clock = 18 cm
Distance covered by minute hand in 1 hour = 2πr
= 2 × 3.14 × 18
= 2 × \(\frac {314}{100}\) × 18
= \(\frac {11304}{100}\)
= 113.04 cm.

13. Multiple choice questions :

Question (i).
The circumference of a circle of diameter 10 cm is :
(a) 31.4 cm
(b) 3.14 cm
(c) 314 cm
(d) 35.4 cm
Answer:
(a) 31.4 cm

Question (ii).
The circumference of a circle with radius 14 cm is :
(a) 88 cm
(b) 44 cm
(c) 22 cm
(d) 85 cm
Answer:
(a) 88 cm

PSEB 7th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3

Question (iii).
What is the area of the circle of radius 7 cm ?
(a) 49 cm
(b) 22 cm2
(c) 154 cm2
(d) 308 cm2
Answer:
(c) 154 cm2

Question (iv).
Find the diameter of a circle whose area is 154 cm2 ?
(a) 4 cm
(b) 6 cm
(c) 14 cm
(d) 12 cm
Answer:
(c) 14 cm

Question (v).
A circle has area 100 times the area of another circle. What is the ratio of their circumferences ?
(a) 10 : 1
(b) 1 : 10
(c) 1 : 1
(d) 2 : 1
Answer:
(a) 10 : 1

Question (vi).
Diameter of a circular garden is 9.8 cm. Which of the following is its area ?
(a) 75.46 cm2
(b) 76.46 cm2
(c) 74.4 cm2
(d) 76.4 cm2
Answer:
(a) 75.46 cm2

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