Punjab State Board PSEB 6th Class Maths Book Solutions Chapter 5 Fractions Ex 5.3 Textbook Exercise Questions and Answers.

## PSEB Solutions for Class 6 Maths Chapter 5 Fractions Ex 5.3

1. Write the fraction for the shaded part and check whether these fractions are equivalent or not?

Question (i)

Solution:

2. Find four equivalent fractions of the followings:

Question (i)

(i) \(\frac {1}{4}\)

(ii) \(\frac {3}{5}\)

(iii) \(\frac {7}{9}\)

(iv) \(\frac {5}{11}\)

(v) \(\frac {2}{3}\)

Solution:

3. Write the lowest equivalent fraction (simplest form) of :

Question (i)

(i) \(\frac {10}{25}\)

(ii) \(\frac {27}{54}\)

(iii) \(\frac {48}{72}\)

(iv) \(\frac {150}{60}\)

(v) \(\frac {162}{90}\)

Solution:

4. Are the following fractions equivalent or not?

Question (i)

\(\frac{5}{12}, \frac{25}{60}\)

Solution:

We have

By cross product,

5 × 60 = 300 and 12 × 25 = 300

Since two cross products are same

So, the given fractions are equivalent.

Question (ii)

\(\frac{6}{7}, \frac{36}{42}\)

Solution:

We have

By cross product,

6 × 42 = 252 and 7 × 36 = 252

Since two cross products are same

So, the given fractions are equivalent.

Question (iii)

\(\frac{7}{9}, \frac{56}{72}\)

Solution:

We have

By cross product,

7 × 72 = 504 and 9 × 56 = 504

Since two cross products are same

So, the given fractions are equivalent.

5. Replace [ ] 1 in each of the following by the correct number.

Question (i)

\(\frac{2}{7}\) = 12 / [ ]

Solution:

Observe the numerators we have 12 ÷ 2 = 6

So, we multiply both numerator and denominator of \(\frac {2}{7}\) by 6

We get \(\frac{2}{7}=\frac{2 \times 6}{7 \times 6}=\frac{12}{42}\)

Hence, the correct number in [ ] 1 is 42

Question (ii)

\(\frac{5}{8}\) = 35 / [ ]

Solution:

Observe the numerators we have 35 ÷ 5 = 7

So, we multiply both numerator and denominator of \(\frac {5}{8}\) by 7

We get \(\frac{5}{8}=\frac{5 \times 7}{8 \times 7}=\frac{35}{56}\)

Hence, the correct number in [ ] is 56.

Question (iii)

\(\frac{24}{36}\) = 6 / [ ]

Solution:

Observe the numerators we have 24 ÷ 6 = 4

So, we divide both numerator and denominator of \(\frac {24}{36}\) by 4

We get \(\frac{24}{36}=\frac{24 \div 4}{36 \div 4}=\frac{6}{9}\)

Hence, the correct number in [ ] is 9

Question (iv)

\(\frac{30}{48}\) = 8 / [ ]

Solution:

Observe the denominators we have 48 ÷ 8 = 6

So, we divide both numerator and denominator of \(\frac {30}{48}\) by 6

We get \(\frac{30}{48}=\frac{30 \div 6}{48 \div 6}=\frac{5}{8}\)

Hence, the correct number in ⊇ is 5

Question (v)

\(\frac{7}{4}\) = 42 / [ ]

Solution:

Observe the numerators we have 42 ÷ 7 = 6

So, we multiply both numerator and denominator of \(\frac {7}{4}\) by 6

We get \(\frac{7}{4}=\frac{7 \times 6}{7 \times 6}=\frac{42}{24}\)

Hence, the correct number in [ ] is 24

6. Find the equivalent fraction of \(\frac {3}{5}\), having

Question (i)

numerator 18

Solution:

(i) Equivalent fraction of \(\frac {3}{5}\), having numerator 18 is

\(\frac{3}{5}\) = 18 / [ ]

Observe the numerators, we have 18 ÷ 3=6

So, we multiply both numerator and denominator of \(\frac {3}{5}\) by 6

∴ \(\frac{3}{5}=\frac{3 \times 6}{5 \times 6}=\frac{18}{30}\)

Thus, required equivalent fraction of \(\frac{3}{5}=\frac{18}{30}\)

Question (ii)

denominator 20

Solution:

Equivalent fraction of \(\frac {3}{5}\), having denominator 20 is \(\frac{3}{5}\) = [ ] / 20

Observe the denominators, we have 20 ÷ 5 = 4

So, we multiply both numerator and denominator of \(\frac {3}{5}\) by 4

Thus, required equivalent fraction of \(\frac{3}{5}=\frac{12}{20}\)

∴ \(\frac{3}{5}=\frac{3 \times 4}{5 \times 4}=\frac{12}{20}\)

Thus, required equivalent fraction of

\(\frac{3}{5}=\frac{12}{20}\)

Question (iii)

numerator 24.

Solution:

Equivalent fraction of \(\frac {3}{5}\) , having numerator 24 is

\(\frac{3}{5}\) = 24 / [ ]

Observe the numerators, we have 24 ÷ 3 = 8

So, we multiply both numerator and denominator of \(\frac {3}{5}\) by 8

∴ \(\frac{3}{5}=\frac{3 \times 8}{5 \times 8}=\frac{24}{40}\)

Thus, required equivalent fraction of

\(\frac{3}{5}=\frac{24}{40}\)

7. Find the equivalent fraction of \(\frac {24}{40}\), having

Question (i)

(i) numerator 6

(ii) numerator 48

(iii) denominator 20

Solution:

(i) Equivalent fraction of \(\frac {24}{40}\), numerator 6 is

\(\frac{24}{40}\) = 6 / [ ]

Observe the numerators, we have 24 ÷ 6 = 4

So, we divide both numerator and denominator of \(\frac {24}{40}\) by 4

∴ \(\frac{24}{40}=\frac{24 \div 4}{40 \div 4}=\frac{6}{10}\)

Thus, required equivalent fraction of

\(\frac{24}{40}=\frac{6}{10}\)

Question (ii)

numerator 48

Solution:

Equivalent fraction of \(\frac {24}{40}\), having numerator 48 is

\(\frac{24}{40}\) = 48 / [ ]

Observe the numerators, we have 48 ÷ 24 = 2

So, we multiply both numerator and denominator of \(\frac {24}{40}\) by 2

∴ \(\frac{24}{40}=\frac{24 \times 2}{40 \times 2}=\frac{48}{80}\)

Thus, required equivalent fraction of

\(\frac{24}{40}=\frac{48}{80}\)

Question (iii)

denominator 20

Solution:

Equivalent fraction of \(\frac {24}{40}\), having denominator 20 is

\(\frac{24}{40}\) = [ ] / 20

Observe the denominators, we have 40 ÷ 20 = 2

So, we divide both numerator and denominator of \(\frac {24}{40}\) by 2

\(\frac{24}{40}=\frac{24 \div 2}{40 \div 2}=\frac{12}{20}\)

∴ Thus, required equivalent fraction of

\(\frac{24}{40}=\frac{12}{20}\)