# PSEB 7th Class Maths Solutions Chapter 2 Fractions and Decimals Ex 2.4

Punjab State Board PSEB 7th Class Maths Book Solutions Chapter 2 Fractions and Decimals Ex 2.4 Textbook Exercise Questions and Answers.

## PSEB Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.4

1. Find the reciprocal of each of the following fraction.
(i) $$\frac {2}{7}$$
(ii) $$\frac {3}{2}$$
(iii) $$\frac {5}{7}$$
(iv) $$\frac {1}{9}$$
(v) $$\frac {2}{3}$$
(vi) $$\frac {7}{8}$$
(i) $$\frac {7}{2}$$
(ii) $$\frac {2}{3}$$
(iii) $$\frac {7}{5}$$
(iv) 9
(v) $$\frac {3}{2}$$
(vi) $$\frac {8}{7}$$

2. Solve the following (Division of a fraction by a non zero whole number)

Question (i).
$$\frac {19}{6}$$ ÷ 10
$$\frac {19}{6}$$ ÷ 10
= $$\frac{19}{6} \times \frac{1}{10}$$
= $$\frac {19}{60}$$

Question (ii).
$$\frac {4}{9}$$ ÷ 5
$$\frac {4}{9}$$ ÷ 5
= $$\frac{4}{9} \times \frac{1}{5}$$
= $$\frac {4}{45}$$

Question (iii).
$$\frac {8}{9}$$ ÷ 8
$$\frac {8}{9}$$ ÷ 8
= $$\frac{8}{9} \times \frac{1}{8}$$
= $$\frac {1}{9}$$ Question (iv).
3$$\frac {1}{2}$$ ÷ 4
3$$\frac {1}{2}$$ ÷ 4
= $$\frac{7}{2} \times \frac{1}{4}$$
= $$\frac {7}{8}$$

Question (v).
16$$\frac {1}{2}$$ ÷ 5
16$$\frac {1}{2}$$ ÷ 5
= $$\frac{33}{2} \times \frac{1}{5}$$
= $$\frac {33}{10}$$
= 3$$\frac {3}{10}$$

Question (vi).
4$$\frac {1}{3}$$ ÷ 3
4$$\frac {1}{3}$$ ÷ 3
= $$\frac{13}{3} \times \frac{1}{3}$$
= $$\frac {33}{9}$$
= 1$$\frac {4}{9}$$

3. Solve the following (Division of a whole number by a fraction)

Question (i).
8 ÷ $$\frac {7}{3}$$
8 ÷ $$\frac {7}{3}$$
= 8 × $$\frac {3}{7}$$
= $$\frac {24}{7}$$
= 3$$\frac {3}{7}$$ Question (ii).
5 ÷ $$\frac {7}{5}$$
5 ÷ $$\frac {7}{5}$$
= 5 × $$\frac {5}{7}$$
= $$\frac {25}{7}$$
= 3$$\frac {4}{7}$$

Question (iii).
4 ÷ $$\frac {8}{3}$$
4 ÷ $$\frac {8}{3}$$
= 4 × $$\frac {3}{8}$$
= $$\frac {3}{2}$$
= 1$$\frac {1}{2}$$

Question (iv).
3 ÷ 2$$\frac {3}{5}$$
3 ÷ 2$$\frac {3}{5}$$
= 3 ÷ $$\frac {13}{5}$$
= 3 × $$\frac {5}{13}$$
= $$\frac {15}{13}$$
= 1$$\frac {2}{13}$$

Question (v).
5 ÷ 3$$\frac {4}{7}$$
5 ÷ 3$$\frac {4}{7}$$
= 5 ÷ 3$$\frac {25}{7}$$
= 5 × $$\frac {7}{25}$$
= $$\frac {7}{25}$$
= 1$$\frac {2}{5}$$ 4. Solve the following (Division of a fraction by another fraction)

Question (i).
$$\frac{2}{3} \div \frac{10}{9}$$
$$\frac{2}{3} \div \frac{10}{9}$$
= $$\frac{2}{3} \times \frac{9}{10}$$
= $$\frac {3}{5}$$

Question (ii).
$$\frac{4}{9} \div \frac{2}{3}$$
$$\frac{4}{9} \div \frac{2}{3}$$
= $$\frac{4}{9} \times \frac{3}{2}$$
= $$\frac {2}{3}$$

Question (iii).
$$2 \frac{1}{2} \div \frac{3}{5}$$
$$2 \frac{1}{2} \div \frac{3}{5}$$
= $$\frac{5}{2} \times \frac{5}{3}$$
= $$\frac {25}{6}$$
= 4$$\frac {1}{6}$$

Question (iv).
$$\frac{3}{7} \div 1 \frac{1}{5}$$
$$\frac{3}{7} \div 1 \frac{1}{5}$$
= $$\frac{3}{7} \div \frac{6}{5}$$
= $$\frac{3}{7} \times \frac{5}{6}$$
= $$\frac {5}{14}$$

Question (v).
$$5 \frac{1}{2} \div 2 \frac{1}{5}$$
$$5 \frac{1}{2} \div 2 \frac{1}{5}$$
= $$\frac{11}{2} \div \frac{11}{5}$$
= $$\frac{11}{2} \times \frac{5}{11}$$
= $$\frac {5}{2}$$
= 2$$\frac {1}{2}$$

Question (vi).
$$3 \frac{1}{5} \div 1 \frac{2}{3}$$
$$3 \frac{1}{5} \div 1 \frac{2}{3}$$
$$\frac{16}{5} \div \frac{5}{3}$$
= $$\frac{16}{5} \times \frac{3}{5}$$
= $$\frac {48}{25}$$
= 1$$\frac {23}{25}$$ 5. 11 small ropes are cut from 7$$\frac {1}{3}$$ m long rope. Find the length of each of the small rope.
Solution:
Length of rope = 7$$\frac {1}{3}$$ m = $$\frac {22}{3}$$ m,
∴ Length of 11 small ropes = $$\frac {22}{3}$$m
Length of each small rope = $$\frac {22}{3}$$m ÷ 11
= $$\frac{22}{3} \times \frac{1}{11} \mathrm{~m}$$
= $$\frac {2}{3}$$m

6. Multiple choice questions :

Question (i).
Reciprocal of $$\frac {3}{4}$$ is :
(a) $$\frac {3}{4}$$
(b) $$\frac {4}{3}$$
(c) 1
(d) none of these
(b) $$\frac {4}{3}$$

Question (ii).
$$\frac{5}{7} \div \frac{7}{5}=?$$
(a) 1
(b) $$\frac {49}{25}$$
(c) $$\frac {25}{49}$$
(d) -1
(c) $$\frac {25}{49}$$

Question (iii).
$$\frac{5}{7} \div \frac{5}{7}=?$$
(a) 1
(b) $$\frac {49}{25}$$
(c) $$\frac {25}{49}$$
(d) -1
(a) 1 7.
Question (i).
The reciprocal of a proper fraction is an improper fraction (True/False)