Punjab State Board PSEB 7th Class Maths Book Solutions Chapter 1 Integers Ex 1.4 Textbook Exercise Questions and Answers.

## PSEB Solutions for Class 7 Maths Chapter 1 Integers Ex 1.4

1. Evaluate each of the following :

(i) 76 ÷ 19

(ii) (-156) ÷ (-12)

(iii) (-125) ÷ (-1)

(iv) (125) ÷ (-25)

(v) 0 ÷ (-5)

(vi) (-15) ÷ (15)

Answer:

2. Write all even integers between -18 and 0.

Answer:

All even integers between – 18 and 0 are :

-16, -14, -12, -10, -8, -6, -4, -2.

3. Write all odd integers between -9 and 9.

Answer:

All odd integers between -9 and 9 are :

-7, -5, -3, -1, 1, 3, 5, 7.

4. By what number should (-240) be divided to obtain 16.

Answer:

Let the required number be x

∴ -240 ÷ x = 16

Hence, the required number is -15

5. Find the value of :

Question (i).

125 ÷ [5 ÷ (-1)]

Answer:

125 ÷ [5 ÷ (-1)] = 125 ÷ (-5)

= -25 Ans.

Question (ii).

[169 ÷ 13] ÷ [26 ÷ 2]

Answer:

[169 ÷ 13] ÷ [26 ÷ 2]

= [13] ÷ [13] = 1 Ans.

Question (iii).

[(-105) ÷ 3] ÷ 7

Answer:

[(-105) ÷ 3] ÷ 7

= [-35] ÷ 7

= -5.

6. Simplify : 12 – [8 + 27 ÷ (2 × 8 – 7)]

Answer:

12 – [8 + 27 + (2 × 8 – 7)]

= 12 – [8 + 27 ÷ (16 – 7)]

= 12 – [8 + 27 ÷ (9)]

= 12 – [8 + 3] = 12- 11

= 1

7. Simplify : 10 – [8 – {11 + 30 ÷ (4 + 2)}]

Answer:

10 – [8 – {11 + 30 (4 + 2)}]

= 10 – [8 – {11 + 30 ÷ 6}]

= 10 – [8 – (11 + 5)]

= 10 – [8 – 16]

= 10 – [-8]

= 10 + 8 = 18

8. Multiple Choice Questions :

Question (i).

(-8) ÷ 2 =

(a) -16

(b) -4

(c) 4

(d) -8.

Answer:

(b) -4

Question (ii).

(-7) ÷ (-7) =

(a) -1

(b) 49

(c) -49

(d) None of these.

Answer:

(d) None of these.

Question (iii).

0 ÷ 2 =

(a) 1

(b) 2

(c) -2

(d) 0.

Answer:

(d) 0.

9. The quotient of two integers is always an integer. (True/False)

Answer:

False.

10. If a and b are two unequal non-zero integers then a ÷ b = b ÷ a. (True/False)

Answer:

False.