# PSEB 4th Class Maths Solutions Chapter 1 Numbers Ex 1.2

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 1 Numbers Ex 1.2 Textbook Exercise Questions and Answers.

## PSEB Solutions for Class 4 Maths Chapter 1 Numbers Ex 1.2

1. Write five consecutive successive numbers of the numbers given below :

(a) 2128
Solution:
2129, 2130, 2131, 2132, 2133

(b) 996
Solution:
997, 998, 999, 1000, 1001

(c) 2832
Solution:
2833, 2834, 2835, 2836, 2837

(d) 5989
Solution:
5990, 5991, 5992, 5993, 5994

(e) 7998
Solution:
7999, 8000, 8001, 8002, 8003

(f) 4007
Solution:
4008, 4009, 4010, 4011, 4012.

2. Write five consecutive numbers coming before the numbers given below :

(a) 1004
Solution:
1003, 1002, 1001, 1000, 999

(b) 624
Solution:
623, 622, 621, 620, 619

(c) 9183
Solution:
9182, 9181, 9180, 9179, 9178

(d) 7026
Solution:
7025, 7024, 7023, 7022, 7021

(e) 8303
Solution:
8302, 8301, 8300, 8299, 8298

(f) 6485
Solution:
6484, 6483, 6482, 6481, 6480

3. Fill in the blanks :
(a) ………….., 2200, …………..
Solution:
2199, 2200, 2201

(b) ………….., 7853, …………..
Solution:
7852, 7853, 7854

(c) ………….., 1319, ………….
Solution:
1318, 1319, 1320

(d) 2589, ………….., 2591
Solution:
2589, 2590 2591

(e) ………….., 2401, …………..
Solution:
2400 2401, 2402

(f) 7999, ………….., 8001.
Solution:
7999, 8000 8001.

4. Understand and do :

(a) 723, 733, 743, ………….., ………….., ………….., …………..
Solution:
753, 763, 773, 783

(b) 1510, 1520, 1530, ………….., ………….., ………….., …………..
Solution:
1540, 1550, 1560, 1570

(c) 2545, 2560, 2575, ………….., ………….., ………….., …………..
Solution:
2590, 2605, 2620, 2635

(d) 4690, 4670, 4650, ………….., ………….., ………….., …………..
Solution:
4630, 4610, 4590, 4570

(e) 8150, 8200, 8250, ………….., ………….., ………….., …………..
Solution:
8300, 8350, 8400, 8450

(f) 6325, 6425, 6525, ………….., ………….., ………….., …………..
Solution:
6625, 6725, 6825, 6925

(g) 3008, 3018, 3028, ………….., ………….., ………….., …………..
Solution:
3038, 3048, 3058, 3068

(h) 9000, 8000, 7000, ………….., ………….., ………….., …………..
Solution:
6000, 5000, 4000, 3000

5. Write the successor of the given numbers :

(a) 999
Solution:
999 + 1 = 1000

(b) 7000
Solution:
7000 + 1 = 7001

(c) 2018
Solution:
2018 + 1 = 2019

(d) 2899
Solution:
2899 + 1 = 2900

(e) 4678
Solution:
4678 + 1 = 4679

(f) 4000
Solution:
4000 + 1 = 4001

(g) 7909
Solution:
7909 + 1 = 7910

(h) 5629
Solution:
5629 + 1 = 5630

Write the predecessor of the given numbers :

(a) 9878
Solution:
Predecessor of 9878 = 9878 – 1 = 9877

(b) 5555
Solution:
Predecessor of 5555 = 5555 – 1 = 5554

(c) 4856
Solution:
Predecessor of 4856 = 4856 – 1 = 4855

(d) 7890
Solution:
Predecessor of 7890 = 7890 – 1 = 7889

(e) 3999
Solution:
Predecessor of 3999 = 3999 – 1 = 3998

(f) 2018
Solution:
Predecessor of 2018 = 2018 – 1 = 2017

(g) 5000
Solution:
Predecessor of 5000 = 5000 – 1 = 4999

(h) 6910
Solution:
Predecessor of 6910 = 6910 – 1 = 6909