PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.2

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 2 Fundamental Operations on Numbers Ex 2.2

Question 1.
Fill the digit in place of *
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.2 1
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.2 2
Solution:
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.2 3
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.2 4

PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.2

Question 2.
Evaluate the following :
(a) 1238 – 1025 + 5018
(b) 9386 – 2535 – 1002
(c) 6307 – 4052 + 2115
(d) 8107 + 2437 – 6089
(e) 18337 + 30947 – 34413
(f) 91206 – 70413 + 30824
(g) 10003 – 5911 – 3284
(h) 92319 – 65424 – 12105
Solution:
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.2 5
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.2 6

PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.1

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 2 Fundamental Operations on Numbers Ex 2.1

Question 1.
Solve the following :
(a) 6574 + 5502
(b) 5350 + 4102
(c) 56754 + 25740
(d) 25000 + 11887
(e) 8988 – 2450
(f) 8990 – 1034
(g) 80029 – 21200
(h) 56789 – 1234
Solution:
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.1 1

Question 2.
Solve the following :
(a) 8760 + 2584
(b) 9649 + 5161
(c) 38009 + 55691
(d) 25347 + 74040
(e) 8761 + 5584 + 4320
(f) 4687 + 1000 + 1130
(g) 28740 + 54938 + 12338
(h) 72624 + 3106 + 10234
(i) 8849 – 4118
(j) 51307 – 42158
(k) 80003 – 19219
(l) 70000 – 12345
Solution:
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.1 2
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.1 3

PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.1

Question 3.
Subtract and verify the following:
(a) 98920 – 12334
(b) 40013 – 18167
(c) 78901 – 52214
(d) 40467 – 10239
(e) 79571 -48678
Solution:
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.1 4
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.1 5
PSEB 5th Class Maths Solutions Chapter 2 Fundamental Operations on Numbers Ex 2.1 6

PSEB 5th Class Maths MCQ Chapter 10 Data Handling

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 10 Data Handling MCQ Questions and Answers.

PSEB 5th Class Maths Chapter 10 Data Handling MCQ Questions

Multiple Choice Questions

Tick (✓) the correct answer :

1. The table shows the data of temperature of a city for a week :
PSEB 5th Class Maths Solutions MCQ Chapter 10 Data Handling 1

Question 1.
Which day is the hottest?
(a) Tuesday
(b) Thursday
(c) Sunday
(d) Monday.
Answer:
(c) Sunday

Question 2.
Which day is the coldest?
(a) Wednesday
(b) Tuesday
(c) Saturday
(d) Friday.
Answer:
(b) Tueday

PSEB 5th Class Maths Solutions MCQ Chapter 10 Data Handling

Question 3.
What is the difference between the highest and the lowest temperature?
(a) 6°C
(b) 8°C
(c) 5°C
(d) 7°C.
Answer:
(d) 7°C

Question 4.
Which two days are equally hot?
(a) Thursday, Saturday
(b) Sunday, Monday
(c) Tuesday, Wednesday
(d) Thursday, Friday.
Answer:
(a) Thursday, Saturday

2. The runs scored by a cricketer in four consecutive years are as follows :

PSEB 5th Class Maths Solutions MCQ Chapter 10 Data Handling 2
Question 1.
How many runs were scored by the player in 2016?
(a) 300
(b) 400
(c) 350
(d) 200.
Answer:
(b) 400

PSEB 5th Class Maths Solutions MCQ Chapter 10 Data Handling

Question 2.
In which year, the player scored the least runs?
(a) 2017
(b) 2016
(c) 2015
(d) 2014.
Answer:
(c) 2015

Question 3.
What is the difference of highest and lowest runs scored by a player?
(a) 150
(b) 50
(c) 200
(d) 100.
Answer:
(a) 150

Question 4.
How many total runs he scored in four consecutive years?
(a) 1100
(b) 1000
(c) 1300
(d) 1200.
Answer:
(c) 1300

PSEB 5th Class Maths Solutions MCQ Chapter 10 Data Handling

Question 3.
See the diagram. How many points were obtained for game 3.
PSEB 5th Class Maths Solutions MCQ Chapter 10 Data Handling 3
(a) 35
(b) 40
(c) 30
(d) 25.
Ans:
(b)

4. The given pie chart provide the information of colour liked by students of class five. Observe the pie chart carefully and answer the questions.

PSEB 5th Class Maths Solutions MCQ Chapter 10 Data Handling 4
Question 1.
How many students (in fractions) of class five like green colour?
Solution:
Number of students who like green colour = \(\frac{1}{4}\) × 40 = 10

Question 2.
Which colour is liked by the students the most?
Solution:
The colour which is liked the most = Red

PSEB 5th Class Maths Solutions MCQ Chapter 10 Data Handling

Question 3.
If there are 40 students in the class, then how many of them like green colour?
Solution:
The number of students who like green colour = 40 × \(\frac{1}{4}\) = 10

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.2

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 10 Data Handling Ex 10.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 10 Data Handling Ex 10.2

1. The following pictograph represents the number of boys of sections A, B, C, D of 5th class during sessions 2014-15 and 2015-16.

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.2 1

Question 1.
In which session number of boys are more in Section A.
Solution:
2015-16

Question 2.
The number of students of Section D are ……………… in 2014-15 and 2015-16 (equal/more/less)
Solution:
equal

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.2

Question 3.
Find the total number of boys in 2014-15.
Solution:
16 × 5 = 80

Question 4.
Find the difference in number of boys of section C during both sessions.
Solution:
30 – 25 = 5

Question 5.
How many more/less boys are there in 2015-16 than in 2014-15.
Solution:
2015 – 16, 15 more boys.

2. The following two Bar Graphs represent the maximum temperature of four cities on two different days. Four cities are Delhi, Shimla, Bangluru and Jaisalmer.

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.2 2
Answer the following from above Bar Graphs :
Question 1.
Which city is the hottest on June 1 ?
Solution:
Jaisalmer

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.2

Question 2.
Which city is the coldest on December 1 ?
Solution:
Shimla

Question 3.
What is the difference in Delhi’s temperature on June 1 and December 1 ?
Solution:
33°C – 23° C = 10°C

Question 4.
What is die difference in Shimla’s temperature on June 1 and December 1 ?
Solution:
22°C – 10° C

Question 5.
Which city has lowest change in temperature on June 1 and December 1 ?
Solution:
Bangluru

3. Study the following Bar Graph carefully.

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.2 3
Find :
Question 1.
What information is provided by the above Bar Graphs ?
Solution:
The Bar Graphs give us the information about the games played by the students of class 3rd and 4th and the number of students who play that game.

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.2

Question 2.
Which game is played equally by students of 3rd and 4th class ?
Solution:
Football

Question 3.
What is the total number of students of 3rd and 4th class who play Kho- Kho?
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.2 4
Solution:
15 + 35 = 50

Question 4.
What is the total number of students Of 3rd and 4th class who play Basketball ?
Solution:
25 + 20 = 45

Question 5.
Which is the favourite game of 3rd class students ?
Solution:
Football

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.2

Question 6.
Which is the favourite game of 4th class students ?
Solution:
Kho-Kho.

PSEB 5th Class Maths Solutions Chapter 1 Numbers Intext Questions

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 1 Numbers InText Questions and Answers.

PSEB 5th Class Maths Solutions Chapter 1 Numbers InText Questions

Try These : (Textbook Page No.2)

Question 1.
Write the following number figures in words :
(a) 968
(b) 6908
(c) 1328
(d) 9002
(e) 9999.
Solution:
(a) 968 : Nine hundred sixty eight
(b) 6908 : Six thousand nine hundred eight
(c) 1328 : One thousand three hundred twenty eight
(d) 9002 : Nine thousand two
(e) 9999 : Nine thousand nine hundred ninty nine.

Question 2.
Write the following numbers in figures:
(a) Six hundred seventy eight
(b) One thousand seven hundred
(c) Four thousand six
(d) Eight thousand eight hundred eighty six
(e) Nine thousand ninety.
Solution:
(a) 678
(b) 1700
(c) 4006
(d) 8886
(e) 9090.

PSEB 5th Class Maths Solutions Chapter 1 Numbers Intext Questions

Try These : (Textbook Page No.3)

Question 3.
Compare the following numbers using >, < or = signs :

(a) 238 PSEB 5th Class Maths Solutions Chapter 1 Numbers Intext Questions 1 832
(b) 7851 PSEB 5th Class Maths Solutions Chapter 1 Numbers Intext Questions 1 8715
(c) 2018 PSEB 5th Class Maths Solutions Chapter 1 Numbers Intext Questions 1 2018
(d) 9999 PSEB 5th Class Maths Solutions Chapter 1 Numbers Intext Questions 1 9900
(e) 4651 PSEB 5th Class Maths Solutions Chapter 1 Numbers Intext Questions 1 5467
(f) 5867 PSEB 5th Class Maths Solutions Chapter 1 Numbers Intext Questions 1 6325
Solution:
(a) <
(b) <
(c) =
(d) >
(e) <
(f) <.

Question 4.
Write the following numbers in ascending order (smallest to greatest) :
(a) 245, 751, 654, 456, 199
(b) 1234, 7806, 4123, 5006, 2413
(c) 3344, 4455, U22, 2233, 5566
(d) 6780, 6078, 6870, 8760, 7806
(e) 3299, 5699, 9932, 9999, 6099.
Solution:
(a) 199, 245, 456, 654, 751
(b) 1234,2413,4123,5006,7806
(c) 1122, 2233, 3344, 4455, 5566
(d) 6078, 6780, 6870, 7806, 8760
(e) 3299, 5699, 6099, 9932, 9999.

Question 5.
Write the following in descending order (greatest to smallest) :
(a) 542,751,614,406,129
(b) 2234,7906,5123,8006,6413
(c) 3345, 3456, 1132, 1233, 5066
(d) 6781,6178,6570,6460,6806
(e) 1299, 1669, 1932, 1909, 1099.
Solution:
(a) 751, 614, 542, 406, 129
(b) 8006, 7906, 6413, 5123, 2234
(c) 5066, 3456, 3345, 1233, 1132
(d) 6806,6781,6570,6460,6178
(e) 1932, 1909, 1669, 1299, 1099.

PSEB 5th Class Maths Solutions Chapter 1 Numbers Intext Questions

Try These : (Textbook Page No.4, 5)

Question 6.
Write the place value of underlined digit :
(a) 789
(b) 2782
(c) 7819
(d) 5489
(e) 7009.
Solution:
(a) 80
(b) 700
(c) 9
(d) 5000
(e) 0.

Question 7.
Write in expanded form :
(a) 492
(b) 1280
(c) 3009
(d) 876.5
(e) 9020.
Solution:
(a) 492 = 400 + 90 + 2
(b) 1280 = 1000 + 200 + 80 + 0
(c) 3009= 3000 + 9
(d) 8765 = 8000 + 700 + 60 + 5
(e) 9020 = 9000 + 20.

Question 8.
Form the greatest and smallest numbers by using the following numbers :
(a) 2, 0, 9
(b) 1, 2, 3, 4
(c) 5, 6, 1, 2
(d) 2, 4, 0, 9
(e) 1, 7, 8, 6.
Solution:
(a) The greatest number = 920
The smallest number = 209
(b) The greatest number = 4321
The smallest number = 1234
(c) The greatest number = 6521
The smallest number = 1256
(d) The greatest number = 9420
The smallest number = 2049
(e) The greatest number = 8761
The smallest number = 1678

Question 9.
Follow the pattern and fill in the blanks :
(a) 110, 210, 310, 410, ____, ___, ___, ____
(b) 2018,2019,2020,2021, ___, ___, ___, ____
(c) 1220,1190,1160,1130, ___, ___, ___, ____
(d) 1110,1220,1330,1440, ___, ___, ___, ____
(e) 5800,5850,5900,5950, ___, __, ___, ____
Solution:
(a) 110, 210, 310, 410, 510, 610, 710, 810.
(b) 2018, 2019, 2020, 2021, 2022, 2023, 2024, 2025
(c) 1220, 1190, 1160, 1130, 1100, 1070, 1040, 1010
(d) 1110, 1220, 1330, 1440, 1550, 1660, 1770, 1880
(e) 5800, 5850, 5900, 5950, 6000, 6050, 6100, 6150

Question 10.
Round off to the nearest tens and hundreds of the following :
(a) 96
(b) 209
(c) 652
(d) 787
(e) 975.
Solution:
Nearest ten :
(a) 100
(b) 210
(c) 650
(d) 790
(e) 980.
Nearest hundred :
(a) 100
(b) 200
(c) 700
(d) 800
(e) 1000.

PSEB 5th Class Maths Solutions Chapter 1 Numbers Intext Questions

Question 11.
Fill in the blanks :
1 digit smallest number =
2 digits smallest number =
3 digits smallest number =
4 digits smallest number =
5 digits smallest number =
6 digits smallest number =

1 digit greatest number =
2 digits greatest number =
3 digits greatest number =
4 digits greatest number =
5 digits greatest number =
Solution:
1, 10, 100, 1000, 10000, 100000, 9, 99, 999, 9999, 99999.
Note
Successor of a number : To find the successor of a number we add 1 to it.
Predecessor of a number : To find the predecessor of a number we subtract 1 from it.

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 10 Data Handling Ex 10.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 10 Data Handling Ex 10.1

Question 1.
The students of a school visited a zoo for picnic. Students collected the data of number of different animals. The number of animals are as follows : Monkey – 32, Lion – 10, Deer – 25, Rabbit – 27 and Fox – 39. Represent the data in tabular form.
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 1
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 2
Solution:
We can represent the above information in the tabular form as follows :
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 18

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1

Question 2.
There is a circus in a village. The following pictograph represents the number of children visitors from Monday to Friday. Read the following pictograph carefully and answer the questions.
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 3

  1. How many children visited circus on Tuesday ?
  2. Which day had most children visited and how many ?
  3. Which day had least children visited and how many ?
  4. How many total number of children visited the circus on Monday and Wednesday ?
  5. What is the difference of number of children visited on Thursday and Friday ?

Solution:

  1. Number of children who visited circus on Tuesday = 3 x 25 = 75.
  2. The day on which the most number of the children had visited is Thursday and the number of children is 8 × 25 = 200.
  3. The day on which least number of children had visited = Monday and the number of children = 2 × 25 = 50.
  4. Total number of children who visited the circus on Monday and Wednesday = 50 + 125=175.
  5. The difference of number of children who visited on Thursday and Friday = 200 – 150 = 50.

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1

Question 3.
The following table shows the plantation of trees on Diwali day in 5 different villages on the eve of celebration of Green Diwali :
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 4
(i) Draw pictograph of the above data.
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 5
Solution:
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 6

(ii) Draw another pictograph of above information by any other scale.
Solution:
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 7
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 8

Question 4.
The following Bar Graph represents the quantity of milk used in a week in a sweet shop during the festival season.
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 9

  1. On which day maximum milk is used ?
  2. On which day minimum milk is used ?
  3. On which two days, the quantity of milk used is the same and how much ?
  4. How much total quantity of milk is used on Thursday and Friday ?
  5. How much less milk is used on Tuesday than Sunday ?
  6. What is the difference of maximum and minimum quantity of milk used ?

Solution:

  1. Sunday
  2. Wednesday
  3. Monday and Saturday, 150 l
  4. 550 l
  5. 350 l – 200 l = 150 l
  6. 350 l – 100 l = 250 l.

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1

Question 5.
The data of mobile phones sold of different companies of a shop in October is as follows :
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 10
Draw the bar graph for the above data.
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 11
Scale : 8 sets = 1 unit
Solution:
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 12

Question 6.
The number of students from 1st to 5th class of a school is as follows:
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 13
Draw the bar graph for the above data.
Scale : 10 students = 1 unit
Solution:
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 14

Question 7.
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 16
The above Pie Chart is divided into 8 equal parts. It represents the different number of coins in Ajay’s Piggy Bank, then answer the following : If the number of total coins is 80.
(i) How many coins of ₹ 5 are there ? (In fraction)
(ii) How many coins of ₹ 2 are there ?
(iii) Tell the number of coins of ₹ 5 ?
(iv) What is the amount of coins of ₹ 10 ?
(v) How much total amount is there in Ajay’s Piggy bank ?
Solution:
(i) \(\frac{3}{8}\)
(ii) \(\frac{2}{8}\) × 80 = 20
(iii) \(\frac{3}{8}\) × 80 = 30

(iv) Number of ₹ 10 coins = \(\frac{1}{8}\) × 80 = 10
Total value of ₹ 10 coins
= ₹ 10 × 10 = ₹ 100

(v) Number of ₹ 1 coins = \(\frac{2}{8}\) × 80 = 20
Number of ₹ 2 coins = 20
Number of ₹ 5 coins = 30
Number of ₹ 10 coins = 10
Total value of ₹ 1 coins = ₹ 1 × 20 = ₹ 20
Total value of ₹ 2 coins = ₹ 2 × 20 = ₹ 40
Total value of ₹ 5 coins = ₹ 5 × 30 = ₹ 150
Total value of ₹ 10 coins = ₹ 10 × 10 = ₹ 100
The total amount of money in Ajay ’ s piggy bank
= ₹ 20 + ₹ 40 + ₹ 50 + ₹ 100
= ₹ 310.

PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1

Question 8.
Given pie chart is divided into 12 equal parts. It represents the favourite festivals of 120 students of a school. Read it carefully and answer the following :
PSEB 5th Class Maths Solutions Chapter 10 Data Handling Ex 10.1 17

  1. How many students (in fraction) like Diwali festival ?
  2. How many students like Holi festival out of 120 students ?
  3. Which festival is liked by minimum number of students ?
  4. What is the difference of number of students who like Diwali and Basant ?

Solution:

  1. \(\frac{5}{12}\)
  2. \(\frac{4}{12}\) × 120 = 40
  3. Dussehra
  4. (\(\frac{6}{12}\) × 120) – (\(\frac{2}{12}\) × 120)
    = 60 – 20 = 30

PSEB 5th Class Maths MCQ Chapter 1 Numbers

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 1 Numbers MCQ Questions and Answers.

PSEB 5th Class Maths Chapter 1 Numbers MCQ Questions

Tick (✓) the right answer :

Question 1.
Write the successor of the greatest 5-digit number.
(a) 99999
(b) 10000
(c) 100000
(d) 9999.
Answer:
(c) 100000

Question 2.
How many 2-digits numbers are there ?
(a) 99
(b) 90
(c) 100
(d) 89
Answer:
(b) 90

PSEB 5th Class Maths Solutions MCQ Chapter 1 Numbers

Question 3.
How many 5-digits numbers are there ?
(a) 99999
(b) 9000
(c) 10000
(d) 90000.
Answer:
(d) 90000.

Question 4.
Smallest 5-digits number using digits 4, 6, 8, 9, 0 is :
(a) 46890
(b) 04689
(c) 98640
(d) 40689.
Answer:
(d) 40689.

Question 5.
Fifty nine thousand fifty nine = ______
(a) 59590
(b) 5959
(c) 59059
(d) 59509.
Answer:
(c) 59059

Question 6.
Choose the place value of 6 in 26573.
(a) 60000
(b) 6000
(c) 6
(d) 60.
Answer:
(b) 6000

Question 7.
Standard form of 20000 + 5000 + 30 + 4 is :
(a) 25304
(b) 25034
(c) 20534
(d) 25043.
Answer:
(b) 25034

Question 8.
Greatest 5-digits number by using digits 7, 8, 6, 7, 9 :
(a) 67879
(b) 98767
(c) 98776
(d) 98677.
Answer:
(c) 98776

Question 9.
Out of the following numbers, which number has the place value of 8 as 8000 ?
(a) 35832
(b) 43248
(c) 54682
(d) 48054.
Answer:
(d) 48054.

PSEB 5th Class Maths Solutions MCQ Chapter 1 Numbers

Question 10.
Write 48 is Roman Numerals.
(a) LVIII
(b) LXVIII
(c) XLVHI
(d) XVIIIL.
Answer:
(c) XLVHI

Question 11.
Write 85 in Roman Numerals.
(a) LXXV
(b) XXCV
(c) XVC
(d) LXXXV.
Answer:
(d) LXXXV.

Question 12.
Which is predecessor of 10000 ?
(a) 9999
(b) 999
(c) 99999
(d) 1000.
Answer:
(a) 9999

Question 13.
Roman numeral of 94 is :
(a) CVI
(b) XCVI
(c) XCIV
(d) XICV.
Answer:
(c) XCIV

Question 14.
Choose the correct numeral using I, X, L, V.
(a) XILV
(b) XLVI
(c) XVIL
(d) VXIL.
Answer:
(b) XLVI

Question 15.
Greatest 5-digits number by using digits 1, 0, 3 is :
(a) 11103
(b) 10333
(c) 33310
(d) 10003.
Answer:
(c) 33310

Question 16.
Smallest 4-digits number using digits 9, 8, 0 :
(a) 9800
(b) 9008
(c) 8090
(d) 8009.
Answer:
(d) 8009.

Question 17.
Round off 758 to the nearest tens is :
(a) 750
(b) 760
(c) 800
(d) 700
Answer:
(b) 760

Question 18.
Round off 8978 to the nearest tens is :
(a) 8980
(b) 9000
(c) 8970
(d) 8900.
Answer:
(a) 8980

Question 19.
Round off 69684 to the nearest thousands is :
(a) 69000
(b) 69700
(c) 79000
(d) 70000.
Answer:
(d) 70000.

Question 20.
If a number has to be rounded off to the nearest ten thousands then which place of the digit will be taken ?
(a) Tens
(b) Hundreds
(c) Thousands
(d) Ten Thousands.
Answer:
(c) Thousands

Question 21.
Place value of 0 in 50358 is :
(a) 10000
(b) 100
(c) 1000
(d) 0.
Answer:
(d) 0.

Question 22.
Which symbols are not repeated in Roman system ?
(a) L, X
(b) L, V
(c) X, I
(d) L, I.
Answer:
(b) L, V

PSEB 5th Class Maths Solutions MCQ Chapter 1 Numbers

Question 23.
How many digits are there in one lakh ?
(a) 5
(b) 6
(c) 4
(d) 7.
Answer:
(b) 6

Question 24.
How many thousands are there in one lakh ?
(a) 10
(b) 100
(c) 1000
(d) 10000.
Answer:
(b) 100

Question 25.
How many maximum number of beads can be inserted in abacus ?
(a) 1
(b) 10
(c) 0
(d) 9.
Answer:
(d) 9.

Question 26.
In the given figure which object has maximum cost price ?
PSEB 5th Class Maths Solutions MCQ Chapter 1 Numbers 1
Answer:
PSEB 5th Class Maths Solutions MCQ Chapter 1 Numbers 2

Question 27.
Write the number by looking at abascus.
PSEB 5th Class Maths Solutions MCQ Chapter 1 Numbers 3
(a) 8179
(b) 38179
(c) 3879
(d) 97183.
Answer:
(b) 38179

Question 28.
Write the successor and predicessor of 2019.
Answer:
Successor of 2019 = 2019 + 1 = 2020
Predicessor of 2019=2019 – 1 = 2018
PSEB 5th Class Maths Solutions MCQ Chapter 1 Numbers 4
Answer:

PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.4

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 1 Numbers Ex 1.4 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 1 Numbers Ex 1.4

Question 1.
Round off the following numbers to the nearest tens.
(a) 270
(b) 809
(c) 6465
(d) 9782
(e) 908
(f) 100
(g) 25338
(h) 1756.
Solution:
(a) In the number 270, ones digit is 0, which is less than 5, so, tens digit remains the same.
∴ Required number = 270.
(b) In the number 809, ones digit is 9, which is greater than 5, so, tens digit is increased by 1 and units digit is replaced by 0.
∴ Required number = 810.
(c) In the number 6465, ones digit is 5, which is equal to 5, so, tens digit is increased by 1 and ones digit is replaced by 0.
∴ Required number = 6470.
(d) In the number 9782, ones digit is 2, which is less than 5, so, tens digit remains the same and ones digit is replaced by 0.
∴ Required number = 9780.
(e) In the number 908, ones digit is 8, which is greater than 5, so, tens digit is increased by 1 and units digit is replaced by 0.
∴ Required number = 910.
(f) In the number 100, ones digit is 0, which is less than 5, so, tens digit remains the same.
∴ Required number = 100.
(g) In the number 25338, ones digit is 8, which is greater than 5, so, tens digit is increased by 1 and ones digit is replaced by 0.
∴ Required number = 25340.
(h) In the number 1756, ones digit is 6, which is greater than 5, so, the tens digit is increased by 1 and units digit is replaced by 0.
∴ Required number = 1760.

Question 2.
Round off the following numbers to the nearest hundreds.
(a) 325
(b) 875
(c) 990
(d) 4580
(e) 568
(f) 63535
(g) 85972
(h) 75069.
Solution:
(a) In the number 325, tens digit is 2, which is less than 5, so, hundreds digit remains the same and 25 is replaced by 00.
∴ Required number = 300.
(b) In the number 875, tens digit is 7, which is greater than 5, so, hundreds digit is increased by 1 and 75 is replaced by 00.
∴ Required number = 900.
(c) In the number 990, tens digit is 9, which is greater than 5, so, hundreds digit is increased by 1 and 90 is replaced by 00.
∴ Required number = 1000.
(d) In the number 4580, tens digit is 8, which is greater than 5, so, hundreds digit is increased by 1 and 80 is replaced by 00.
∴ Required number = 4600.
(e) In the number 568, tens digit is 6, which is greater than 5, so, hundreds digit is increased by 1 and 68 is replaced by 00.
∴ Required number = 600.
(f) In the number 63535, tens digit is 3, which is less than 5, so, hundreds digit remains the same and 35 is replaced by 00.
∴ Required number = 63500.
(g) In the number 85972, tens digit is 7, which is greater than 5, so, hundreds digit is increased by 1 and 72 is replaced by 00.
∴ Required number = 86000.
(h) In the number 75069, tens digit is 6, which is greater than 5, so, hundreds digit is increased by 1 and 69 is replaced by 00.
∴ Required number = 75100.

PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.4

Question 3.
Round off the following numbers to the nearest thousands.
(a) 7890
(b) 8901
(c) 45982
(d) 5650
(e) 63520
(f) 50460
(g) 60008
(h) 9999
Solution:
(a) In the number 7890, the hundreds digit is 8, which is greater than 5, so, thousands digit is increased by 1 and 890 is replaced by 000.
∴ The required number = 8000.
(b) In the number 8901, the hundreds digit is 9, which is greater than 5, so, thousands digit is increased by 1 and 901 is replaced by 000.
∴ The required number = 9000.
(c) In the number 45982, the hundreds digit is 9, which is greater than 5, so, thousands digit is increased by 1 and 982 is replaced by 000.
∴ The required number = 46000.
(d) In the number 5650, the .hundreds digit is 6, which is greater than 5, so, thousands digit is increased by 1 and 650 is replaced by 000.
∴ The required number = 6000.
(e) In the number 63520, the hundreds digit is 5, so, thousands digit is increased by 1 and 520 is replaced by 000.
∴ Required number = 64000. .
(f) In the number 50460, the hundreds digit is 4, which is less than 5, so, thousands digit remains the same and 460 is replaced by 000.
∴ Required number = 50000.
(g) In the number 60008, the hundreds digit is 0, which is less than 5, so, thousands digit remains the same and 008 is replaced by 000.
∴ Required number = 60000.
(h) In the number 9999, hundreds digit is 9, which is greater than 5, so, thousands digit is increased by 1 and 999 is replaced by 000.
∴ The required number = 10000.

Question 4.
Round off the following number to the nearest ten thousands.
(a) 27900
(b) 80901
(c) 46580
(d) 12550
(e) 99998
(f) 10001
(g) 23235
(h) 23568.
Solution:
(a) In the number 27900, the thousands digit is 7, which is greater than 5, so, ten thousands digit is increased by 1 and 7900 is replaced by 0000.
∴ The required number = 30000.
(b) In the number 80901, the thousands digit is 0, which is less than 5, so, ten thousands digit remains the same and 0901 is replaced by 0000.
∴ The required number = 80000.
(c) In the number 46580, the thousands digit is 6, which is greater than 5, so, ten thousands digit is increased by 1 and 6580 is replaced by 0000.
∴ The required number = 50000.
(d) In the number 12550, the thousands digit is 2, which is less than 5, so, ten thousands digit remains the same and 2550 is replaced by 0000.
∴ The required number = 10000.
(e) In the number 99998, the thousands digit is 9, which is greater than 5, ten thousands is increased by 1 and 9998 is replaced by 0000.
∴ The required number = 100000.
(f) In the number 10001, thousands digit is 0, which is less than 5, so, ten thousands digit remains the same and 0001 is replaced by 0000.
∴ The required number = 10000.
(g) In the number 23235, the thousands digit is 3, which is less than 5, so, ten thousands digit remains the same and 3235 is replaced by 0000.
∴ The required number = 20000.
(h) In the number 23568, the thousands digit is 3, which is less than 5, so, ten thousands digit remains the same and 3568 is replaced by 0000.
∴ The required number = 20000.

PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.4

Question 5.
Round off the following numbers to the nearest tens, nearest hundreds and nearest thousands :
(a) 1625
(b) 1982
(c) 25200
(d) 21218
(e) 35462
(f) 39126
(g) 65915
(h) 99199.
Solution:
(a) 1625 rounded off to the nearest tens = 1630, 1625 rounded off to the nearest hundred = 1600, 1625 rounded off to the nearest thousands = 2000.
(b) 1982 rounded off to the nearest tens = 1980, 1982 rounded off to the nearest hundred = 2000, 1982 rounded off to the nearest thousands = 2000.
(c) 25200 rounded off to the nearest tens = 25200, 25200 rounded off to the nearest hundred = 25200, 25200 rounded off to the nearest thousands = 25000
(d) 21218 rounded off to the nearest tens = 21220, 21218 rounded off to the nearest hundred = 21200, 21218 rounded off to the nearest thousands = 21000.
(e) 35462 rounded off to the nearest tens = 35460, 35462 rounded off to the nearest hundred = 35500, 35462 rounded off to the nearest thousands = 35000
(f) 39126 rounded off to the nearest tens = 39130, 39126 rounded off to the nearest hundred = 39100, 39126 rounded off to the nearest thousands = 39000
(g) 65915 rounded off to the nearest tens = 65920, 65915 rounded off to the nearest hundreds = 65900, 65915 rounded off to the nearest thousands = 66000
(h) 99199 rounded off to the nearest tens = 99200, 99199 rounded off to the nearest hundreds = 99200, 99199 rounded off to the nearest thousands = 99000

Question 6.
Write the smallest and greatest number that can be rounded off to the nearest thousand, to get 5000 ?
Solution:
The smallest number that can be rounded off to the nearest thousands to get 5000 = 4500 The greatest number which can be rounded off to the nearest thousands, to get 5000 = 5499.

Question 7.
If the rounding off of 341 to the nearest tens is 340 write all the numbers which while rounding off to the nearest tens give the figure of 340?
Solution:
All the numbers which while rounding off to the nearest tens give the figure of 340 = 335, 336, 337, 338, 339, 340, 341, 342, 343, 344.

PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 1 Numbers Ex 1.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 1 Numbers Ex 1.3

Question 1.
Fill in the blanks using the signs <, >, or = :
(a) 8072 PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3 1 1872
0b) 9876 PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3 1 6789
(c) 21916 PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3 1 29161
(d) 40234 PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3 1 32234
(e) 35003 PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3 1 35003
(f) 60104 PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3 1 60140
(g) 52838 PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3 1 45885
(h) 99999 PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3 1 100000.
Solution:
(a) >
(b) >
(c) <
(d) >
(e) =
(f) <
(g) >
(h) <

Question 2.
Write the greatest number from the following :
(a) 8172, 2578, 8127, 8728, 8527
(b) 60060, 66006,60600,66660, 60006
(c) 58031, 13258, 35185, 81135, 86311 .
(d) 47443, 73434, 44473, 74437, 34474
(e) 872,31827,5183,31725,40426.
Solution:
(a) 8728
(b) 66660
(c) 86311
(d) 74437
(e) 40426.

PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3

Question 3.
Write the smallest number from the following :
(a) 9064, 7372,8938, 9746,9942
(b) 81018, 80108, 80810, 18018, 10018
(c) 32334, 23443, 24334, 33342, 32343
(d) 927,39272,93227,46238,27999
(e) 43148, 448i3, 48134, 34148, 13481.
Solution:
(a) 7372
(b) 10018
(c) 23443
(d) 927
(e) 13481.

Question 4.
Arrange the following numbers in ascending order :
(a) 9036, 6309, 9610, 699, 1000
(b) 37492, 94713, 49273, 61047, 52364
(c) 63918, 36829, 45261, 61514, 63819
(d) 36118, 70225, 27052, 36343, 52073
(e) 28136, 28236, 28853, 28534, 28435.
Solution:
(a) 699, 1000, 6309, 9036, 9610
(b) 37492, 49273, 52364, 61047, 94713
(c) 36829, 45261, 61514, 63819, 63918
(d) 27052, 36118, 36343, 52073, 70225
(e) 28136, 28236, 28435, 28534, 28853.

Question 5.
Arrange the following numbers in descending order :
(a) 7084, 8084, 4048, 5074, 6785
(b) 61272,71262,51721,41112, 62271
(c) 72280, 82720, 87220, 82270, 28780
(d) 99063, 93083, 94835, 99093, 96039
(e) 83226, 86203, 28306, 28603, 27503.
Solution:
(a) 8084, 7084, 6785, 5074, 4048
(b) 71262, 62271, 61272, 51721, 41112
(c) 87220,82720,82270, 72280, 28780
(d) 99093, 99063; 96039, 94835, 93083
(e) 86203, 83226, 28603, 28306, 27503.

Question 6.
Write the greatest and smallest 5-digits numbers using digits 6, 7, 8, 4 and 1.
Solution:
The greatest number = 87641
The smallest number = 14678

PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.3

Question 7.
Write the greatest and smallest 5-digits numbers using digits 5, 8, 3, 0 and 9.
Solution:
The greatest number = 98530
The smallest number = 30589

Question 8.
Write the greatest and smallest 5-digits numbers using different digits.
Solution:
The greatest number = 98765
The smallest number = 10234

PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 1 Numbers Ex 1.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 1 Numbers Ex 1.2

Question 1.
Write the place value of underlined digits in the following numbers :
(a) 8326
(b) 54588
(c) 90008
(d) 99234
(e) 49716
(f) 47168
(g) 63184
(i) 29999.
Solution:
(a) 8326 The place value of underlined digit i.e. 2 = 2 × 10 = 20
(b) 54588 The place value of underlined digit i.e. 4 = 4 × 1000 = 4000
(c) 90008 The place value of underlined digit i.e. 8 = 8 × 1 = 8
(d) 99234 The place value of underlined digit i.e. 9 = 9 × 10000 = 90000
(e) 49716 The place value of underlined digit i.e. 7 = 7 × 100 = 700
(f) 47168 The place value of underlined digit i.e. 7 = 7 × 1000 = 7000
(g) 63184 The place value of underlined digit i.e. 6 = 6 × 10000 = 60000
(h) 29999 The place value of underlined digit i.e. 2 = 2 × 10000 = 20000

Question 2.
Write the face value of underlined digits in the following numbers :
(a) 82232
(b) 54180
(c) 90811
(d) 12994
(e) 11973
(f) 24716
(g) 11631
(h) 59999.
Solution:
(a) 82232 The face value of underlined digit i.e. 2 = 2
(b) 54180 The face value of underlined digit i.e. 4 = 4
(c) 90811 The face value of underlined digit i.e. 8=8
(d) 12994 The face value of underlined digit i.e. 9=9
(e) 11973 The face value of underlined digit i.e. 7 = 7
(f) 24716 The face value of underlined digit i.e. 7=7
(g) 11631 The face value of underlined digit i.e. 6 = 6
(h) 59999 The face value of underlined , digit i.e. 5 = 5

PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2

Question 3.
Write the following numbers in the expanded form :
(a) 232
(b) 4180
(c) 27811
(d) 82994
(e) 10073
(f) 43710
(g) 61639
(h) 26999.
Solution:
(a)
PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2 1
The expanded form of 232 = 200 + 30 + 2

(b)
PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2 2
The expanded form of 4180 = 4000 + 100 + 80 + 0

(c)
PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2 3
The expanded form of 27811 = 20000 + 7000 + 800 + 10 + 1

(d)
PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2 4
The expanded form of 82994 = 80000 + 2000 + 900 + 90 + 4

PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2

(e)
PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2 5
The expanded form of 10073 = 10000 + 70 + 3

(f)
PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2 6
The expanded form of 43710 = 40000 + 3000 + 10

(g)
PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2 7
The expanded form of 61639 = 60000 + 1000 + 600 + 30 + 9

(h)
PSEB 5th Class Maths Solutions Chapter 1 Numbers Ex 1.2 8
The expanded form of 26999 = 20000 + 6000 + 900 + 90 + 9