Class 5

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 6 Measurement Ex 6.5 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 6 Measurement Ex 6.5

Question 1.
The cost of 1 m cloth for pants is ₹ 265.50 and there is 24 m cloth in a roll. Find the cost of one bundle.
Solution:
Cost of 1 m cloth for pants = ₹ 265,50
Cost of 24 m cloth in a roll
= ₹ 265.50 × 24
= ₹ 6372.00
= ₹ 6372

Question 2.
The weight of a box of mangoes is 32.4 kg. A shopkeeper wants to make 6 packets from this. How many kilograms of mangoes will be there in each packet?
Solution:
The weight of the box of mangoes = 32.4 kg
Number of packets = 6
Weight of mangoes in each box = 32.4 kg ÷ 6

= 5.4 kg

Question 3.
A vessel contains 28.5 7 oil. It is poured into. 5 small containers. How much milk will be there in one small container?
Solution:
Quantity of milk in the given vessel = 28.5 l
Number of small containers = 5
Quantity of milk in each of small container = 28.5 ÷ 5

= 5.7 l

Question 4.
1 bundle of copies weighs 9.8 kgs. Find the weight of 14 such bundles.
Solution:
Weight of 1 bundle of copies = 9.8 kg
Weight of 14 bundles of copies
= 9.8 × 14 kg
= 137.2 kg.

Question 5.
The length of a stick is 12.7 cm. Find the length of 7 such sticks.
Solution:
The length of 1 stick = 12.7 cm
The length of 7 sticks = 12.7 × 7 cm
= 88.9 cm

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 3 HCF and LCM MCQ Questions and Answers.

PSEB 5th Class Maths Chapter 3 HCF and LCM MCQ Questions

Tick (✓) the right answer :

Question 1.
Which number is the smallest even Prime number ? ………
(a) 0
(b) 1
(c) 2
(d) 4
Answer:
(c) 2

Question 2.
Which number is neither Prime nor Composite ?
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(a) 1

Question 3.
Which numbers are Prime numbers between 70 and 80 ?
(a) 71, 72, 73
(b) 71, 75, 79
(c) 71, 80
(d) 71, 73, 79.
Answer:
(d) 71, 73, 79.

Question 4.
HCF of 75 and 90 = ……
(a) 5
(b) 10
(c) 15
(d) 20.
Answer:
(c) 15

Question 5.
LCM of 12, 18 and 24 = …….
(a) 72
(b) 36
(c) 48
(d) 24
Answer:
(a) 72

Question 6.
If HCF of any two numbers is 8 then out of following which can not be LCM of that numbers ?
(a) 48
(b) 60
(c) 24
(d) 56
Answer:
(b) 60

Question 7.
What is length of the largest tape which can measure the lengths of 24 m and 30 m ?
(a) 4 m
(b) 5 m
(c) 6 m
(d) 7 m.
Answer:
(c) 6 m

Question 8.
What is the smallest number which is divisible by 8 and 12 ?
(a) 16
(b) 48
(c) 72
(d) 24
Answer:
(d) 24

Question 9.
LCM of 26 and 39 = ……
(a) 13
(b) 78
(c) 39
(d) 26
Answer:

Question 10.

(a) 5
(b) 65
(c) 12
(d) 13.
Answer:
(d) 13.

Question 11.
Which number is composite number in the following?
(a) 43
(b) 23
(c) 21
(d) 37.
Answer:
(c) 21

Question 12.
Out of following, which number is multiple of 19?
(a) 171
(b) 172
(c) 173
(d) 174.
Answer:
(a) 171

Question 13.
HCF of 15, 45 and 105 = ………
(a) 15
(b) 5
(c) 30
(d) 45.
Answer:
(a) 15

Question 14.
What is the HCF of two prime numbers ?
(a) 1
(b) 2
(c) 3
(d) 4
Answer:
(a) 1

Question 15.
Three bells ring with the time gap of 10 min, 15 min and 20 min respectively in a school. If all bells are rung together at 9:00 am then after how long the bells would ring together again ?
(a) 11:00 o’clock
(b) 08:00 o’clock
(c) 10:00 o’clock
(d) 12:00 o’clock
Answer:
(c) 10:00 o’clock

Read this pattern carefully and answer questions (16 – 20)

Question 16.
Read the above pattern and find the sum of first 6 Odd numbers.
(a) 30
(b) 12
(c) 25
(d) 36.
Answer:
(d) 36.

Question 17.
Read the above pattern and find the sum of first 10 Odd numbers.
(a) 20
(b) 50
(c) 100
(d) 40.
Answer:
(c) 100

Question 18.
Read the above pattern and find the sum of first 8 Even numbers.
(a) 16
(b) 24
(c) 72
(d) 64.
Answer:
(c) 72

Question 19.
Read the above pattern and find sum of first 9 even numbers.
(a) 19
(b) 18
(c) 45
(d) 90.
Answer:
(d) 90.

Question 20.
On a given road, the poles are erected at a distance of 24 m each and piles of stones are lying at a distance of 30 m each. If the 1st pile of stones is lying adjacent to the first pole, at what distance will the pole and the pile of stones be together again ?
(a) 100 m
(b) 110 m
(c) 150 m
(d) 120 m.
Answer:
(d) 120 m.

Question 21.
What is the length of the largest inchitape which can measure the lengths of 24 m and 30 m completely:
(a) 4 m
(b) 5 m
(c) 6 m
(d) 7 m.
Answer:
(c) 6 m

Question.
Write the smallest number which is divisible by 8 and 12.
Solution:
The smallest number which is divisible by 8 and 12 = LCM of 8 and 12.

= 2 × 2 × 2 × 3 = 24

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 3 HCF and LCM Ex 3.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 3 HCF and LCM Ex 3.3

Question 1.
Find LCM of the following :
(a) 5, 10
(b) 6,18
(c) 25, 50
(d) 9, 24
Solution:
(a) Multiples of 5 = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, …….
Multiples of 10 = 10, 20, 30, 40, 50, ……..
Common multiples of 5 and 10 = 10, 20, 30, 40, 50, ……….
The lowest common multiple = 10
So, LCM of 5 and 10 = 10

(b) Multiples of 6 = 6, 12, 18, 24, 30, 36, 42, 48, 54, …….
Multiples of 18 = 18, 36, 54, ……….
Common multiples of 6 and 18 = 18, 36, 54, ………
The lowest common multiple = 18
So, LCM of 6 and 18= 18

(c) Multiples of 25 = 25, 50, 75, 100, 125, 150, …….., …….
Multiples of 50 = 50, 100, 150, 200, ……, ……, ……..
Common multiples of 25 and 50= 50, 100, 150, ………..
The lowest common multiple = 50
So, LCM of 25 and 50 = 50

(d) Multiples of 9 = 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108, ………
Multiples of 24 = 24, 48, 72, 96, …., ….., …….
Common multiples of 9 and 24 = 72,
So, LCM of 9 and 24 = 72

Question 2.
Find LCM of the follówing:
(a) 4, 8 and 12
(b) 6, 12 and 24
(e) 15, 18 and 27
(d) 24, 36 and 40
Solution:
(a) Multiples of 4 = 4, 8, 12, 16, 20, 24, 28, 32, 36,. 40, 44, 48,
Multiples of 8 = 8, 16, 24, 32, 40, 48, …….
Multiples of 12 = 12, 24, 36, 48, 60, ……..
Common multiples of 4, 8 and 12 = 24, 48
The lowest common multiple = 24
So, LCM of 4, 8, 12 = 24

(b) Multiples of 6 = 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, ……
Multiples of 12 = 12, 24, 36, 48, 60, 72, …….
Multiples of 24 = 24, 48, 72, 96, ……..
Common multiples of 6, 12 and 24 = 24, 48, 72, …..
The lowest common multiple = 24
So, LCM of 6, 12, 24 = 24

LCM of 15, 18 and 27 = 3 × 3 × 5 × 2 × 3 = 270

LCM of 24, 36 and 40 = 2 × 2 × 2 × 3 × 3 × 5 = 360

Question 3.
Find LCM of following using Prime factorisation :
(a) 32,40
(b) 24, 36
(c) 15, 30 and 45
(d) 40, 44 and 48
Solution:
(a)

32 = 2 × 2 × 2 × 2 × 2
40 = 2 × 2 × 2 × 5
Common factors = 2 × 2 × 2
Remaining factors = 2 × 2 × 5
So, LCM = 2 × 2 × 2 × 2 × 2 × 5 = 160

(b) 24 = 2 × 2 × 2 × 3
36 = 2 × 2 × 3×3

Common factors = 2 × 2 × 3
Remaining factors = 2 × 3
So, LCM = 2 × 2 × 2 × 3 × 3 = 72

(c) 15 = 3 × 5
30 = 2 × 3 × 5
45 = 3 × 3 × 5

Common factors = 3 × 5
Remaining factors = 2 × 3
So, LCM = 3 × 5 × 2 × 3 = 90

(d) 40 = 2 × 2 × 2 × 5
44 = 2 × 2 × 11
48 = 2 × 2 × 2 × 2 × 3

Common factors = 2 × 2
Remaining factors = 5 × 11 × 2 × 2 × 3
So, LCM = 2 × 2 × 2 × 2 × 5 × 3 × 11
= 2640

Question 4.
Find LCM of following using Division method :
(a) 15, 20
(b) 12, 38
(c) 30, 45 and 50
(d) 40, 68 and 60
Solution:
(a)

LCM of 15 and 20 = 2 × 2 × 5 × 3 = 60
(b)

LCM of 12 and 38 = 2 × 2 × 3 × 19 = 228

(c)

LCM of 30, 45 and 50 = 2 × 3 × 3 × 5 × 5 = 450

(d)

LCM of 40, 68 and 60 = 2 × 2 × 2 × 3 × 5 × 17 = 2040

Question 5.
Find the smallest number which is divisible by 12, 15 and 20 completely ?
Solution:
LCM of 12, 15 and 20
LCM = 2 × 2 × 3 × 5 = 60
Smallest number which is divisible by 12, 15 and 20 = 60

Question 6.
One child jumps 3 feet high and another jumps 4 feet high. If both the children continue jumping together in same direction then after how many feet they will be together again ?
Solution:
We are to find the LCM of 3 and 4
LCM = 3 × 4 = 12
They will be together again after 12 feet.

Question 7.
How many minimum number of students are required from a class to make groups of 4 each and 5 each so that no student is left ?
Solution:
We are to find the LCM of 4 and 5
LCM = 4 × 5 = 20
Number of students required = 20

Question 8.
Three bells ring with a time gap of 10 min, 20 min and 30 min respectively in a school. If all bells are rung together at 8:00 am then after how long the beUs would ring together again ?
Solution:
We are to find the LCM of 10, 20 and 30
LCM = 2 × 5 × 2 × 3 = 60

The bells will ring together after 60 min. i.e. 1 hours.
Thus, the bells will ring together at 9:00 am

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 6 Measurement Ex 6.4 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 6 Measurement Ex 6.4

1. Add the following :

Question 1.
7 km 7.50 m and 2 km 575 m
Solution:

= 10 km 325 m

Question 2.
4 kg 500 g and 9 kg 825 g
Solution:

= 14 kg 325 kg

Question 3.
5 l 925 ml and 7 l 650 ml
Solution:

= 13 l 575 ml

Question 4.
10 m, 3 m 85 cm and 6 m 25 cm
Solution:

= 20 m 10 cm

Question 5.
8 kg 700 g, 975 g and 2 kg 350 g
Solution:

= 12 kg 25 g

2. Subtract:

Question 1.
7 km 625 m from 12 km 300 m
Solution:

= 4 km 675 m

Question 2.
3 kg 650 g from 8 kg
Solution:

= 4 kg 350 g

Question 3.
5 l 850 ml from 10 l 350 ml
Solution:

= 4 l 500 ml

Question 4.
9m 60 cm from 15 m
Solution:

= 5 m 40 cm

Question 5.
13 l from 25 l 765 ml
Solution:

= 12 l 765 ml

Question 3.
Anand has bought 2 kg 350 g onions. 1 kg 750 g potatoes. How many kilograms of vegetables has he bought?
Solution:
Quantity of onions bought by Anand = 2 kg 350 g
Quartity of potatoes bought by Anand = 1 kg 750 g
Total quantity of vegetables bought = 4 kg 100 g

Question 4.
Ajay has travelled 150 km 400 m distancebybus, 120 km 650 m by taxi. How much distance has he covered?
Solution:
Distance travelled by bus = 150 km 400 m
Distance travelled by taxi = 120 km 650 m
Total distance travelled by him = 271 km 50 m

Question 5.
Three containers contained 10 l 350 ml, 9 l 850 ml and 11 l oil respectively. Find the total quantity of oil contained in three containers.
Solution:
First container contains oil = 10 l 350 ml
Second container contains oil = 9 l 850 ml
Third container contains oil = 11 l 000 ml
The total quantity of oil contained in three containers = 31 l 200 ml

Question 6.
Anita bought 7 m 30 cm cloth. She used 2 m 50 cm cloth for her suit. Find the remaining length of the cloth.
Solution:
Length of cloth bought by Anita = 7 m 30 cm
Length of cloth used for suit = 2 m 50 cm
Remaining length of cloth = 4 m 80 cm

Question 7.
A family consumes 10 kg 750 g wheat and 4 kg 500 g rice in a month. Find the difference of consumption of rice and wheat.
Solution:
Quantity of wheat consumed = 10 kg 750 g
Quantity of rice consumed = 4 kg 500 g
Difference of consumption of rice and wheat = 6 kg 250 g

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 6 Measurement Ex 6.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 6 Measurement Ex 6.3

1. Find the amount of liquid in the following:

Question 1.

Question 2.

Solution:
1l 800 ml = 1.800 l

Question 3.

Solution:
1 l 500 ml= 1.500 l

Question 4.

Solution:
1 l 100 ml 1.100 l

Question 5.

Solution:
2 l 0 ml = 2.000 l

2. Colour the following scales vessels according to the given quantity:

Question 1.

Solution:

Question 2.

Solution:

Question 3.

Solution:

Question 4.

Solution:

Question 5.

Solution:

3. Fill in the blanks:

Question 1.
3.125 l = ………………. l …………………. ml
Solution:
3.125 l = 3 l 125 ml

Question 2.
8.720 kl = …………… kl …………….. l
Solution:
8.720 kl = 8 kl 720 l

Question 3.
…………….., l = 4 l 948 ml
Solution:
4.498 l = 4 l = 948 ml

Question 4.
………………….. kl = 15 kl 650 l
Solution:
15.650 kl = 15 kl 650 l

Question 5.
18.045 l = …………….. l …………….. ml
Solution:
18.045 l = 18 l 45 ml

4. Convert:

Question 1.
7.6 l into mililitres
Solution:
7.6 l = 7.6 × 1000 ml
= 7600 ml

Question 2.
250 ml into litres
Solution:
250 ml = \(\frac{250}{1000}\) l
= 0.250 l

Question 3.
4.25 kl into litres
Solution:
4.25 kl = 4.25 × 1000 l
= 4250 l

Question 4.
0.845 l into mililitres
Solution:
0.845 l = 0.845 × 1000 ml
= 845 ml

Question 5.
92 l into kilolitres
Solution:
92 l = \(\frac{92}{1000}\) kl
= 0.092 kl

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 3 HCF and LCM Ex 3.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 3 HCF and LCM Ex 3.2

Question 1.
Write the Prime numbers from the following :

Solution:
(a) 5, 7, 3
(b) 2, 11, 13
(c) 5
(d) 41, 23, 17, 19
(e) 41, 37, 47.

Question 2.
Write the composite numbers from the following :

Solution:
(a) 14, 9, 6
(b) 21, 12, 18
(c) 32, 15
(d) 10, 25, 9
(e) 24, 49, 50.

Question 3.
Find HCF of following numbers using Prime factorisation.
(a) 18, 27
(b) 21, 63
(c) 80, 100
(d) 42, 98.
Solution:

Prime factorisation of 18 = 2 × 3 × 3
Prime factorisation of 27 = 3 × 3 × 3
Common Prime Factors = 3 and 3
∴ HCF of 18 and 27 = 3 × 3 = 9

Prime factorisation of 21 = 3 × 7
Prime factorisation of 63 = 3 × 3 × 7
Common Prime Factors = 3 and 7
∴ HCF of 21 and 63 = 3 × 7 = 21

Prime factorisation of 80 = 2 × 2 × 2 × 2 × 5
Prime factorisation of 100 = 2 × 2 × 5 × 5
Common Prime Factors = 2, 2 and 5
HCF of 80 and 100 = 2 × 2 × 5 = 20

Prime factorisation of 42 = 2 × 3 × 7
Prime factorisation of 98 = 2 × 7 × 7
Common Prime Factors = 2 and 7
HCF of 42 and 98 = 2 × 7 = 14

Question 4.
Find HCF of following numbers using Prime factorisation :
(a) 30, 50, 70
(b) 24, 32, 40
(b) 36, 60, 72
(d) 25, 30, 35.
Solution:

Prime factorisation of 30 = 2 × 3 × 5
Prime factorisation of 50 = 2 × 5 × 5
Prime factorisation of 70 = 2 × 5 × 7
Common Prime Factors = 2 and 5
∴ HCF of 30, 50 and 70 = 2 × 5 = 10

Prime factorisation of 24 = 2 × 2 × 2 × 3
Prime factorisation of 32 = 2 × 2 × 2 × 2 × 2
Prime factorisation of 40 = 2 × 2 × 2 × 5
Common Prime Factors = 2, 2 and 2
∴ HCF of 24, 32 and 40 = 2 × 2 × 2 = 8

Prime factorisation of 36 = 2 × 2 × 3 × 3
Prime factorisation of 60 = 2 × 2 × 3 × 5
Prime factorisation of 72 = 2 × 2 × 2 × 3 × 3
Common Prime Factors = 2, 2 and 3
∴ HCF of 36, 60 and 72 = 2 × 2 × 3 = 12

Prime factorisation of 25 = 5 × 5
Prime factorisation of 30 = 2 × 3 × 5
Prime factorisation of 35 = 5 × 7
Common Prime Factor = 5
∴ HCF of 25, 30, 35 = 5

Question 5.
Find HCF of following numbers using Prime factorisation :
(a) 42, 84
(b) 45, 90
(c) 16, 64, 80
(d) 45, 90, 105.
Solution:

Prime factorisation of 42 = 2 × 3 × 7
Prime factorisation of 84 = 2 × 2 × 3 × 7
Common Prime Factors = 2, 3 and 7
∴ HCF of 42, 84 = 2 × 3 × 7 = 42

Prime factorisation of 45 = 3 × 3 × 5
Prime factorisation of 90 = 2 × 3 × 3 × 5
Common Prime Factors = 3, 3 and 5
HCF of 45, 90 = 3 × 3 × 5 = 45

Prime factorisation of 16 = 2 × 2 × 2 × 2
Prime factorisation of 64 = 2 × 2 × 2 × 2 × 2 × 2
Prime factorisation of 80 = 2 × 2 × 2 × 2 × 5
Common Prime Factors = 2, 2, 2 and 2
∴ HCF of 16, 64, 80 = 2 × 2 × 2 × 2 = 16

Prime factorisation of 45 = 3 × 3 × 5
Prime factorisation of 90 = 2 × 3 × 3 × 5
Prime factorisation of 105 = 3 × 5 × 7
Common Prime Factors = 3 and 5
∴ HCF of 45, 90 and 105 = 3 × 5 = 15

Question 6.
Find HCF of following numbers using Division method :
(a) 48, 60
(b) 120, 140
(c) 12, 18, 64
(d) 60, 96, 128
Solution:
(a)

∴ HCF of 120 and 140 = 20
(c) First find HCF of any two numbers say 12 and 18.

∴ HCF of 12, 18 and 64 = 2

(d) First find HCF of any two numbers say 60 and 96.

∴ HCF of 60 and 96 = 12
Now find HCF of 12 and 128

∴ HCF of 60, 96, 128 = 4

Question 7.
Find the largest number which divides 60, 75 and 90 without leaving any remainder.
Solution:
The largest number which divides 60, 75 and 90 without leaving any remainder = HCF of 60, 75 and 90
First find HCF of any two numbers say 60 and 75.

∴ HCF of 60 and 75 = 15
Now, find HCF of 15 and 90

The greatest number which divides 60, 75 and 90 = 15

Question 8.
There are three drums that contain 36l, 45l, and 72l milk respectively. Find the largest vessel which can measure milk of all the three drums completely.
Solution:

The capacity of the largest vessel that can measure milk of all the three drums completely = 9 l.

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 6 Measurement Ex 6.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 6 Measurement Ex 6.2

1. Find the weight.

Question 1.

Question 2.

Solution:
2 kg 250g = 2.250 kg

Question 3.

Solution:
1 kg 50 g = 1.50 kg

Question 4.

Solution:
2 kg 150 g = 2.150 kg

Question 2.
Tick ( ✓) the required weights for the following :

Solution:

3. Fill in the blanks :

Question 1.
2.850 kg = ……………….. kg …………… g
Solution:
2.850 kg = 2 kg 850 g

Question 2.
15.790 g = …………… g ……………….. mg
Solution:
15.790 g = 15 g 790 mg

Question 3.
……………….. kg = 12 kg 625 g
Solution:
12.625 kg = 12 kg 625 g

Question 4.
……………….. kg = 7 kg 75 g
Solution:
7.075 kg = 7 kg 75 g

Question 5.
……………….. g = 10 g 800 mg
Solution:
10.800 g = 10 g 800 mg

4. Convert :

Question 1.
3.275 g into mg
Solution:
3.275 g = 3.275 × 1000 mg = 3275 mg

Question 2.
8050 g into kg
Solution:
8050 g = \(\frac{8050}{1000}\) kg= 8.050 kg

Question 3.
4.2 kg into g
Solution:
4.2 kg = 4.2 × 1000 g = 4200 g

Question 4.
865 mg into g
Solution:
865 mg = \(\frac{865}{1000}\) g = 0.865 g

Question 5.
520 g into kg
Solution:
520 g = \(\frac{520}{1000}\) kg = 0.520 kg

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 6 Measurement Ex 6.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 6 Measurement Ex 6.1

1. Find the length:

Question 1.

Question 2.

Solution:
11 cm 0 cm = 11 cm

Question 3.

Solution:
4 cm 2 mm = 4.2 cm

Question 4.

Solution:
5 cm 8 mm = 5.8 cm

2. Measure the length of line segments in cm and draw on your notebooks.

Question 1.

Solution:
3.6 cm

Question 2.

Solution:
4.4 cm

Question 3.

Solution:
1.9 cm

Question 4.

Solution:
6 cm

Question 5.

Solution:
2.7 cm

Question 6.

Solution:
4.5 cm

3. Fill in the blanks:

Question 1.
3.45 m = …………….. m ……………….. cm
Solution:
3 m 45 cm

Question 2.
5.75 m = ……………. m ……………. cm
Solution:
5 m 75 cm

Question 3.
10.850 km = ………………. km …………….. m
Solution:
10 km 850 m

Question 4.
………………….. m = 4 m 25 cm
Solution:
4.25 m

Question 5.
……………… km = 7 km 375 m
Solution:
7.375 km

4. Convert the following:

Question 1.
4.5 cm into mm
Solution:
4.5 cm = 4.5 × 10 mm = 45 mm

Question 2.
270 m into km
Solution:
270 m = \(\frac{270}{1000}\) km = 0.270 km

Question 3.
5.82 km into m
Solution:
5.82 = 5.82 × 1000 m = 5820 m

Question 4.
0.65 m into cm
Solution:
0.65 = 0.65 × 100 cm = 65 cm

Question 5.
18 mm into m
Solution:
18 mm = \(\frac{18}{1000}\) m = 0.018 m

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 3 HCF and LCM Ex 3.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 5 Maths Chapter 3 HCF and LCM Ex 3.1

Question 1.
Write the first five multiples of the following numbers :
(a) 5
(b) 9
(c) 10
(d) 12
(e) 16
(f) 17
Solution:
(a) Multiples of 5 = 5, 10, 15, 20, 25
(b) Multiples of 9 = 9, 18, 27, 36, 45
(c) Multiples of 10 = 10, 20, 30, 40, 50
(d) Multiples of 12 = 12, 24, 36, 48, 60
(e) Multiples of 16 = 16, 32,48, 64, 80
(f) Multiples of 17 = 17, 34, 51, 68, 85

Question 2.
Find the factors of the given numbers :

Solution:
(a) 1, 5
(b) 1, 2, 4, 8
(c) 1, 2, 7, 14
(d) 1, 2, 3, 4, 6, 12
(e) 1, 5, 25
(f) 1, 2, 3, 4, 6, 9, 12, 18, 36

Question 3.
Write the factors of the following numbers :
(a) 18
(b) 24
(c) 35
(d) 36
(e) 45
(f) 21
Solution:
(a) 1, 2, 3, 6, 9, 18
(b) 1, 2, 3, 4, 6, 8, 12, 24
(c) 1, 5, 7, 35
(d) 1, 2, 3, 4, 6, 9, 12, 18, 36
(e) 1, 3, 5, 9, 15, 45
(f) 1, 3, 7, 21.

Question 4.
Find out the even numbers from the following :

Solution:
(a) 12, 34, 16, 28
(b) 48, 72, 90
(c) 450, 568, 664, 98
(d) 456, 968, 604, 888
(e) 136, 446, 1278
(f) 168, 5864.

Question 5.

Solution:
(a) 11, 23, 19, 35
(b) 45, 69, 97
(c) 451, 215, 789, 983
(d) 237, 739
(e) 631, 135, 249, 1279, 2851
(f) 49, 765, 1729, 9261, 6859.

Question 6.
Fill in the blanks :
(a) If 4 × 9 = 36 then factors of 36 are …….. and ………
(b) If 8 × 7 = 56 then factors of 56 are ……… and ……….
(c) If 3 × 5 × 6 = 90 then factors of 90 are ……., ……. and …….
(d) If 8 × 10 = 80, the multiple of 8 and 10 is ……….
(e) If 2 × 3 × 5 = 30, then 30, is the multiple of …….., ………. and ……..
Solution:
(a) 4, 9
(b) 8, 7
(c) 3, 5, 6
(d) 80
(e) 2, 3, 5.

Question 7.
Write True or False:

(a) 24 is a factor of 24. ____
(b) 2 is a factor of every number. ____
(c) 24 is an even number. ____
(d) 136 is an odd number. ____
(e) There are infinite multiples of a number. ____
(f) 36 is a multiple of 5 and 7. ____
(g) Sum of two even numbers is an odd number. ____
(h) Smallest even number is 0. ____
(i) 152 is an odd number. ____
(j) There are five single digit even numbers. ____
Solution:
(a) True
(b) False
(c) True
(d) False
(e) True
(f) False
(g) False
(h) False
(i) False
(j) False

Question 8.
Observe the Factorisation Pattern and complete :

Solution:

Question 9.
Look at the pattern and solve:

Solution:

Question 10.
Understand and complete the following:

Answer:

Punjab State Board PSEB 5th Class Maths Book Solutions Chapter 7 Geometry MCQ Questions and Answers.

PSEB 5th Class Maths Chapter 7 Geometry MCQ Questions

Multiple Choice Questions

Question 1.
Name the angle marked on the cover of book.

(a) Right angle
(b) Acute angle
(c) Obtuse angle
(d) Straight angle.
Answer:
(a) Right angle

Question 2.
The angle of 90° is called :
(a) Right angle
(b) Obtuse angle
(c) Acute angle
(d) Straight angle.
Answer:
(a) Right angle

Question 3.
The angle greater than 90° is called:
(a) Acute angle
(b) Right angle
(c) Obtuse angle
(d) Straight angle.
Answer:
(c) Obtuse angle

Question 4.
Make the axis of symmetry of the given figure.

Answer:

Question 5.

In the given figure angles have been marked. Write them in their columns in the table

Answer:
Obtuse angle : 4, 5, 6, 7 ;
Right angle : 2 ;
Acute angle : 1, 3, 8