Punjab State Board PSEB 9th Class Maths Book Solutions Chapter 2 Polynomials MCQ Questions with Answers.
PSEB 9th Class Maths Chapter 2 Polynomials MCQ Questions
Multiple Choice Questions and Answer
Answer each question by selecting the proper alternative from those given below each question to make the statement true:
Question 1.
The value of p(x) = x3 + x2 – 3x – 3 at x = – 1 is ………….. .
A. 1
B. – 1
C. 0
D. – 3
Answer:
C. 0
Question 2.
For the polynomial p(x), If p(2) = 0. then …………….. is a factor of p(x).
A. (x – 2)
B. (x + 2)
C. (x2 – 2)
D. (x2 + 2)
Answer:
A. (x – 2)
Question 3.
Dividing 2x3 + 6x2 + x + 5 by (x + 3), the remainder is ………………. .
A. 2
B. 3
C. 1
D. 0
Answer:
A. 2
Question 4.
……………. should be subtracted from x3 + 3x2 + 2x + 10, so that the result is exactly divisible by (x + 3).
A. 1
B. 2
C. 3
D. 4
Answer:
D. 4
Question 5.
………………… should be added to x3 – 5x2 + x – 8, so that the result Is exactly divisible by (x – 5).
A. 2
B. – 2
C. – 3
D. 3
Answer:
D. 3
Question 6.
…………………. is one of the zeros of the polynomial x3 – 6x2 + 2x – 12.
A. 2
B. – 2
C. 6
D. – 6
Answer:
C. 6
Question 7.
If x + 3 is a factor of x3 + 6x2 + 11x + k, then k = ……………….. .
A. 2
B. 3
C. 4
D. 6
Answer:
D. 6
Question 8.
………………….. should be added to x2 – 8, so that the result is exactly divisible by (x + 3).
A. 1
B. – 1
C. 3
D. – 3
Answer:
B. – 1
Question 9.
If x – 1 is a factor of 4x3 + 3x2 – 4x + k, then k = ………… .
A. 4
B. 1
C. 3
D. – 3
Answer:
D. – 3
Question 10
………………. is one of the factors of 2x4 + x3 – 14x2 – 19x – 6.
A. (x – 1)
B. (x + 1)
C. (x + 3)
D. (x – 2)
Answer:
B. (x + 1)
Question 11.
When x3 + 64 is divided by x + 4, the quotient is ………………. .
A. (x – 4)
B. (x + 8)
C. (x + 16)
D. x2 – 4x + 16
Answer:
D. x2 – 4x + 16
Question 12.
x3 + 3x2 + 3x + 2 = (x + 2) (……………..)
A. x – 2
B. x2 + 1
C. x2 – x – 1
D. x2 + x + 1
Answer:
D. x2 + x + 1
Question 13.
The factors of x2 – x – 12 are .
A.(x + 6) and (x – 2)
B. (x – 4) and (x – 3)
C. (x + 4) and (x + 3)
D. (x – 4) and (x + 3)
Answer:
D. (x – 4) and (x + 3)
Question 14.
The factors of x2 – 100 are ………………. .
A. (x – 20) and (x – 5)
B. (x – 25) and (x – 4)
C. (x – 10)2
D. (x + 10) and (x – 10)
Answer:
D. (x + 10) and (x – 10)
Question 15.
x2 – 2 + \(\frac{1}{x^{2}}\) = ………………………
A. \(\left(x+\frac{1}{x}\right)\left(x-\frac{1}{x}\right)\)
B. \(\left(x-\frac{1}{x}\right)^{2}\)
C. \(\left(x-\frac{1}{x}\right)^{3}\)
D. \(\left(x+\frac{1}{2}\right)^{2}\)
Answer:
B. \(\left(x-\frac{1}{x}\right)^{2}\)
Question 16.
If x2 + mx – 28 = (x – 7) (x + 4), then m = ………………….. .
A. 3
B. – 3
C. 11
D. – 11
Answer:
B. – 3
Question 17.
105 × 95 = ………………. .
A. 9500
B. 10,500
C. 9925
D. 9975
Answer:
D. 9975
Question 18.
(110)3 = …………………… .
A. 330
B. 3300
C. 33.000
D. 13,31,000
Answer:
D. 13,31,000
Question 19.
(15)3 – (9)3 – (6)3 = ………………….
A. 1215
B. 2430
C. – 810
D. 810
Answer:
B. 2430
Question 20.
If x + 3 is one of the factors x3 + 2x2 – ax – 18, then a = …………………. .
A. 3
B. – 3
C. 9
D. – 9
Answer:
C. 9