PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2

Punjab State Board PSEB 7th Class Maths Book Solutions Chapter 12 Algebraic Expressions Ex 12.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.2

1. Fill in the blanks :

(i) 5y + 7y = ……………..
(ii) 3xy + 2xy = ……………..
(iii) 12a2 – 7a2 = ……………..
(iv) 8mn2 – 3mn2 = ……………..
Solution:
(i) 12y
(ii) 5xy
(iii) 5a2
(iv) 5mn2

2. Add the following algebraic expressions 

(a) 3xy2, 7xy2
Solution:
Given terms are like terms. Their coefficients are 3 and 7.
Required sum is given as :
3xy2 + 7xy2 = (3 + 7) xy2
= 10xy2

(b) 7x, – 3x, 2x
Solution:
7x + (- 3x) + 2x = (7 – 3 + 2) x
= 6x

(c) 12p2q, 3p2q, – 5p2q
Solution:
(12p2q) + (3p2q) + (- 5p2q)
= (12 + 3 – 5) p2q
= 10p2q

(d) 3x2, – 8x2, – 5x2, 13x2
Solution:
3x2 + (- 8x)2 + (- 5x)2 + 13x2
= (3 – 8 – 5 + 13) x2
= 3x2

PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2

3. Add the following algebraic expressions.

(a) x + y and 2x – 3y
Solution:
(a) Horizontal method:
(x + y) + (2x – 3y)
= x + 2x + y – 3y
= 3x – 2y

Column method:
PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2 1

(b) 5a + 7b and 3a – 2b
Solution:
Horizontal method:
(5a + 7b) + (3a – 2b)
= 5a + 3a + 7a – 2b
= 8a + 5b.

Column method:
PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2 2

(c) 3m + 2n, 7m – 8n, 2m – n
Solution:
Horizontal method:
(3m + 2n) + (7m – 8n) + (2m – n)
= 3m + 7m + 2m + 2n – 8n – n
= 12m – 7n

Column method:
PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2 3

(d) 3x2 + 2x – 7 and 5x2 – 7x + 8
Solution:
Horizontal method:
(3x2 + 2x – 7) + (5x2 – 7x + 8)
= 3x2 + 5x2 + 2x – 7x – 1 + 8
= 8x2 – 5x + 1

Column method:
PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2 4

(e) m2 + 2n2 – p2, – 3m2 + n2 + 2p2 and 4m2 – 3n2 + 5p2
Solution:
Horizontal method:
(m2 + 2n2 – p2) + (- 3m2 + n2 + 2p2) + (4m2 – 3n2 + 5p2)
= m2 – 3m2 + 4m2 + 2n2 + n2 – 3n2 – p2 + 2p2 + 5p2
= 2m2 + 0n2 + 6p2

Column method:
PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2 5

(f) 3xy + 7x2 – 2y2, 2xy + y2 and 2x2 + y2
Solution:
Horizontal method:
(3xy + 7x2 – 2y2) + (2xy + y2) + (2x2 + y2)
= 3xy + 2xy + 7x2 + 2x2 – 2y2 + y2 + y2
= 5xy + 9x2 + 0y2

Column method:
PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2 6

PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2

4. Simplify the following algebraic expressions by combining like terms.

(a) -5ax + 3xy + 2xy – 8ax
Solution:
– 5ax + 3xy + 2xy – 8ax
= – 5ax – 8ax + 3xy + 2xy
= – 13ax + 5xy.

(b) 3m – 2n + 5m – 3m + 8n
Solution:
3m – 2n + 5m – 3m + 8n
= 3m + 5m – 3m – 2n + 8n
= 5m + 6 n.

(c) 3pq – 15r2 – 3l2m2 + 2r2 + 2l2m2 – 5pq
Solution:
3pq – 15r2 – 3l2m2 + 2r2 + 2l2m2 – 5pq
= 3pq – 5pq – 15r2 + 2r2 – 3l2m2 + 2l2m2
= – 2pq – 13r2 – 2l2m2.

(d) 4x3 + 7x2 – 3x + 2 – 2x3 – 2x2 + 7x – 3
Solution:
4x3 + 7x2 – 3x + 2 – 2x3 – 2x2 + 7x – 3
= 4x3 – 2x3 + 7x2 – 2x2 – 3x + 7x + 2 – 3
= 2x3 + 5x2 + 4x – 1.

5. Subtract the algebraic expressions.

(a) – 3x2 from 7x2
Solution:
7x2 – (- 3x2) = 7x2 + 3x2 = 10x2

(b) – 3ab from 10ab
Solution:
10ab – (- 3ab) = 10ab + 3ab = 13 ab

PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2

(c) a + b from a – b
Solution:
(a – b) – (a+ b)
= a – b – a – b
= -2b

(d) 15m + 10n from 2m – 16n
Solution:
2m – 6n – (15m + 10n)
= 2m – 15m – 6n – 10n
= – 13m – 16n

(e) 2x + 8y – 3z from – 3x + 2y + z
Solution:
– 3x + 2y + z – (2x + 8y – 3z)
= – 3x + 2y + z – 2x – 8y + 3z
= – 5x – 6y + 4z

(f) 18m2 + 3n2 – 2mn – 7 from 3m2 – 2n2 + 8mn – 8m + 4
Solution:
(3m2 – 2n2 + 8mn – 8m + 4) – (18m2 + 3n2 – 2mn – 7)
= 3m2 – 2n2 + 8mn – 8m + 4 – 18m2 – 3n2 + 2mn + 7
= 3m2 – 18m2 – 2n2 – 3n2 + 8mn + 2mn – 8m + 4 + 7
= – 15m2 – 5n2 + 10mn – 8m + 11

6. What should be subtracted from l – 2m + 5n to get 2l – 3m + 4n ?
Solution:
(l – 2m + 5n) – (2l – 3m + 4n)
= l – 2l – 2m + 3m + 5n – 4n
= -l + m + n.
Hence, -l + m + n should be subtracted.

7. What should be added to 3x2 + 2xy – y2 to obtain x2 – 7xy + 3y2 ?
Solution:
(x2 – 7xy + 3y2) – (3x2 + 2xy – y2)
= x2 – 3x2 – 7xy – 2xy + 3y2 + y2
= – 2x2 – 9xy + 4y2.

PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2

8. Subtract 3a2 + 2b2 – 8ab + 8 from the sum of a2 – b2 + 7ab + 3 and 2a2 + 4b2 – 18ab + 7
Solution:
First add a2 – b2 + 7ab + 3 and 2a2 + 4b2 – 18ab + 7
(a2 – b2 + 7ab + 3) + (2a2 + 4b2 – 18ab + 7)
= a2 + 2a2 – b2 + 4b2 + 7ab – 18ab + 3 + 7
= 3a2 + 3b2 – 11ab + 10 …… (1)
Now we subtract 3a2 + 2b2 – 8ab + 8 from (1)
3a2 + 3b2 – 11ab + 10 – (3a2 + 2b2 – 8ab + 8)
= 3a2 – 3a2 + 3b2 – 2b2 – 11ab + 8ab + 10 – 8
= 0a2 + b2 – 3ab + 2
= b2 – 3ab + 2

9. How much x2 + 3xy + y2 is less than 2x2 + 5xy – y2 ?
Solution:
(2x2 + 5xy – y2) – (x2 + 3xy + y2)
= 2x2 – x2 + 5xy – 3xy – y2 – y2
= x2 + 2xy – 0y2
Hence, x2 + 3xy + y2 is less than 2x2 + 5xy – y2 by x2 + 2xy – 2y2.

10. Multiple Choice Questions :

Question (i).
The algebraic expression for “Number 5 added to three times the product of numbers m and n” is.
(a) 5 + 3mn
(b) 3 + 5mn
(c) (5 + 3) mn
Answer:
(a) 5 + 3mn

PSEB 7th Class Maths Solutions Chapter 12 Algebraic Expressions Ex 12.2

Question (ii).
The sum of algebraic expressions 3x + 11 and 2x – 7 is
(a) 5x + 4
(b) x + 4
(c) 5x – 18
Answer:
(a) 5x + 4

Question (iii).
Subtraction of a + b from 2a + 3b.
(a) a + 2b
(b) – a – 2b
(c) 3a + 4b
(d) a + b
Answer:
(a) a + 2b

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