Class 4

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) Ex 4.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 4 Money (Currency) Ex 4.3

1. Manveet bought following things in a fair. How much money will she pay to the shopkeeper?

Question 1.

Solution:

Question 2.

Solution:

Question 3.

Solution:

Question 4.

Solution:

2. Supreet bought the following things and gave money. How much amount will the shopkeeper return to Supreet?

Question 1.

Solution:

Question 2.

Solution:

Question 3.
Avneet bought a chocolate worth of ₹ 72 and a juice worth ₹ 35. What amount will Avneet pay to shopkeeper?
Solution:
Cost price of a chocolate = ₹ 72
Cost price of juice = ₹ 35
Total cost of both = ₹ 107

Avneet will pay ₹ 107 to shopkeeper.

Question 4.
Supreet bought a school bag worth ₹ 365. He gave ₹ 500 to shopkeeper. How much money will be returned by the shopkeeper?
Solution:
Amount given to shopkeeper = ₹ 500
Cost price of a school bag = ₹ 365

Shopkeeper will return ₹ 135 to him.

Question 5.
Vinod bought a book worth ₹ 247.75, copies worth ₹ 180.60 and a pen worth ₹ 35.20. How much did he spend in all?
Solution:
Cost price of a book = ₹ 247.75
Cost price of note books = ₹ 180.60
Cost price of a pen = ₹ 35.20
Total cost of all the items = ₹ 463.55

He spent ₹ 463.55.

Question 6.
Tanisha wants to buy a battery car worth ₹ 945 for her $other. She has ₹ 820. How much money does she require more to buy it?
Solution:
Cost price of the battery car = ₹ 945
She has money with her = ₹ 820
More money requirement to buy it = ₹ 125

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.3

(1 metre = 100 cm)

Question 1.
Convert into metre:
(a) 400 cm = ……. m
Solution:
4 m

(b) 700 cm = ……. m
Solution:
7 m

(c) 200 cm = …….. m
Solution:
2 m

(d) 800 cm = ……. m
Solution:
8 m

(e) 500 cm = ……….. m
Solution:
5 m

(f) 900 cm = …….. m
Solution:
9 in.

Question 2.
Convert into centimetres :
(a) 3 m = …… cm
Solution:
3 m = 3 × 100 cm
= 300 cm

(b) 6 m = …… cm
Solution:
6 m = 6 × 100 cm
= 600 cm

(c) 4 m = …… cm
Solution:
4 m = 4 × 100 cm
= 400 cm

(d) 9 m = ……. cm
Solution:
9 m = 9 × 100 cm
= 900 cm

(e) 2 m = …….. cm
Solution:
2 m = 2 × 100 cm
= 200 cm

(f) 5m = ……. cm
Solution:
5 m = 5 × 100 cm
= 500 cm

Question 3.
Mohit measures length of given items with help of a 30 cm scale. Show this length in metre and centimetres.

Solution:

1. 1 m 8 cm.
2. 1 m 32 cm.
3. 3 m 5 cm.
4. 4 m 50 cm.

Question 4.
Estimate the distance in metres and also find the actual distance with the help of metre rod or measurement tape.

Solution:
Try yourself.

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) Ex 4.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 4 Money (Currency) Ex 4.2

1. Add the amount of the following currency notes:

Question 1.

Solution:
₹ 170

Question 2.

Solution:
₹ 310

Question 3.

Solution:
₹ 525

Question 4.

Solution:
₹ 230

Question 5.

Solution:
₹ 157

2. Find the sum of following amounts :

Question 1.
₹ 200, ₹ 50, ₹ 20
Solution:
₹ 200, ₹ 50, ₹ 20

Question 2.
₹ 350, ₹ 165, ₹ 75
Solution:
₹ 350, ₹ 165, ₹ 75

Question 3.
₹ 470, ₹ 105, ₹ 55
Solution:
₹ 470, ₹ 105, ₹ 55

Question 4.
₹ 250, ₹ 90, ₹ 110
Solution:
₹ 250, ₹ 90, ₹ 110

Question 5.
₹ 200, ₹ 160, ₹ 50
Solution:
₹ 200, ₹ 160, ₹ 50

3. Find the difference (subtract) of following amounts :

Question 1.
₹ 200 and ₹ 150
Solution:
₹ 200. ₹ 150

Question 2.
₹ 450 and ₹ 200
Solution:
₹ 450, ₹ 200

Question 3.
₹ 500 and ₹ 270
Solution:
₹ 500, ₹ 270

Question 4.
₹ 120 and ₹ 75
Solution:
₹ 120, ₹ 75

Question 5.
₹ 300 and ₹ 125
Solution:
₹ 300, ₹ 125

4. Put (✓) on the currency note or coins which are required for buying given things :

Question 1.

Solution:

Question 2.

Solution:

Question 3.

Solution:

Question 4.

Solution:

Question 5.

Solution:

5. Draw required currency notes and coins for buying things as tender.

Question 1.

Solution:

Question 2.

Solution:

Question 3.

Solution:

Question 4.

Solution:

Question 5.

Solution:

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 4 Money (Currency) Ex 4.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 4 Money (Currency) Ex 4.1

1. Draw 50 paise coins for given notes/coins :

Question 1.

Solution:

= Take four coins of 50 paise

Question 2.

Solution:

= Take ten coins of 50 paise

Question 3.

Solution:

= Take twenty coins of 50 paise

Question 4.

Solution:

= Take fourteen coins of 50 paise

Question 5.

Solution:

= Take eight coins of 50 paise.

2. Draw notes/coins, converting 50 paise into rupees.

Question 1.

Question 2.

Solution:

Question 3.

Solution:

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.2

Question 1.
Measure the length of given items in cm and mm :
(a)

Solution:
7 cm 8 mm

(b)

Solution:
3 cm 4 mm

(c)

Solution:
3 cm 8 mm

(d)

Solution:
6 cm 5 mm.

Question 2.
Measure the length of line segments in cm and mm :
(a)

Solution:
3 cm 7 mm

(b)

Solution:
4 cm 6 mm

(c)

Solution:
5 cm 2 mm

(d)

Solution:
6 cm 8 mm

(e)

Solution:
8 cm 3 mm

(f)

Solution:
12 cm 5 mm

Question 3.
Measure the length and breadth of given currency notes :

(a) Length ……. = ……. cm …. mm
(b) Breadth …… = …… cm …… mm

(c) Length ……. = ……. cm …. mm
(d) Breadth …… = …… cm …… mm
Solution:
Take a ₹2000 and a ₹200 note and measure their length and breadth
(a) 16 cm 8 mm
(b) 6 cm 6 mm
(c) 14 cm 6 mm
(d) 6 cm 6 mm

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Ex 5.1 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Ex 5.1

Question 1.
Complete the table

Solution:
Take the above mentioned items and measure each of them and complete the table.

Question 2.
Find the distance between given dots and give the following answers:

(a) Distance from point A to B
= ……… cm
Solution:
4 cm

(b) Distance from point B to D
= ……… cm
Solution:
6 cm

(c) Distance from point A to E
= ……… cm
Solution:
5 cm

(d) Distance from point C to D
= ……… cm
Solution:
4 cm

(e) Distance from point B to E
= …….. cm
Solution:
11 cm

(f) Distance from point A to D
= …….. cm
Solution:
6 cm.

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 5 Measurement Revision Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 5 Measurement Revision Exercise

Question 1.
The length of pencil is 19 ………
(centimetre, kilogram, metre)
Solution:
Centimeter

Question 2.
Weight of a brick is 3 ……..
(litre, kilogram, metre)
Answer:
Kilogram

Question 3.
There is 2 …….. water in the jug.
(litre, kilogram, metre)
Solution:
Litre

Question 4.
Draw a picture on weighing scale showing less and more weight.

Solution:

Question 5.
Colour the given container having capacity upto 2 litre

Solution:

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 8 Perimeter and Area MCQ Questions and Answers.

PSEB 4th Class Maths Chapter 8 Perimeter and Area MCQ Questions

Question 1.
Sum of the length of all sides of a closed figure is called ………
(a) Perimeter
(b) Area
(c) Shadow
(d) None of these
Answer:
(a) Perimeter

Question 2.
Find the perimeter of a triangle having sides 5 cm, 7 cm and 9 cm :
(a) 15 cm
(b) 20 cm
(c) 27 cm
(d) 21 cm.
Answer:
(d) 21 cm.

Question 3.
Find the perimeter of a shape if each side of square is 1 cm :
(a) 12 cm
(b) 7 cm
(c) 28 cm
(d) 14 cm

Answer:
(a) 12 cm

Question 4.
The perimeter of given figure is 22 m. The four sides of this figure are 4 m, 6 m, 6 m and 3 m. Find the fifth side.

(a) 4 m
(b) 3 m
(c) 5 m
(d) 2 m.
Answer:
(b) 3 m

Question 5.
Find the perimeter of a square whose side is 5 cm.
(a) 25 cm
(b) 15 cm
(c) 20 cm
(d) 16 cm.
Answer:
(c) 20 cm

Question 6.
Find the perimeter of a rectangle whose length is 4 cm and breadth is 5 cm ?
(a) 9 cm
(b) 12 cm
(c) 15 cm
(d) 18 cm.
Answer:
(d) 18 cm.

Question 7.
Find the area of the given figures :

Which figure has greater area ?
(a) (iv)
(b) (iii)
(c) (i)
(d) (ii).
Answer:
(a) (iv)

Question 8.
Find the area of a square whose side is 6 cm.
(a) 24 square cm
(b) 36 cm
(c) 36 square cm
(d) 12 square cm
Answer:
(b) 36 cm

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 8 Perimeter and Area Ex 8.3 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 8 Perimeter and Area Ex 8.3

Question 1.
Colour the area covered by each figure :

Solution:

Solution:

Solution:

Solution:

Note: You can fill any colour.

Question 2.
Find the area of each figure on the basis of number of squares if side of each square is 1 cm and area of each square is 1 square cm.

Solution:
(a) Number of squares = 13
Area of the figure = 13 × 1 cm² = 13 cm²

(b) Number of squares = 20
Area of the figure = 20 × 1 cm² = 20 cm²

(c) Number of squares = 5
Area of the figure = 5 × 1 cm² = 5 cm²

(d) Number of squares = 9
Area of the figure = 9 × 1 cm² = 9 cm²

(e) Number of squares = 12
Area of the figure = 12 × 1 cm² = 12 cm²

(f) Number of squares = 16
Area of the figure = 16 × 1 cm² = 16 cm²

Question 3.
How many square cm area is covered by each figure ?

Solution:
(a) 6
(b) 7
(c) 10
(d) 7
(e) 13
(f) 4

Question 4.
In a notebook with squares draw your favourite figure in which the number of square boxes are:
(a) 20
(b) 27
(c) 15.
Solution:
Try yourself

Question 5.
Look at this picture. Can you divide the figure into four equal parts. How many squares are there in each part?
Solution:
Number of squares = 12
Number of parts into which to be divided = 4
Number of squares in each part = 12 ÷ 4 = 3

Punjab State Board PSEB 4th Class Maths Book Solutions Chapter 8 Perimeter and Area Ex 8.2 Textbook Exercise Questions and Answers.

PSEB Solutions for Class 4 Maths Chapter 8 Perimeter and Area Ex 8.2

Which of the following figures have covered more surface. Tick the figure which (✓) has greater area.

(a)

Solution:
First Figure

(b)

Solution:
Second Figure

(c)

Solution:
First Figure