Punjab State Board PSEB 8th Class Maths Book Solutions Chapter 1 Rational Numbers InText Questions and Answers.
PSEB 8th Class Maths Solutions Chapter 1 Rational Numbers InText Questions
Try These : (Textbook Page No.4)
Question 1.
Fill in the blanks in the following table :
Answer:
[Note : Rational numbers are not closed under division.]
e.g., \(\frac {2}{3}\) ÷ 0 = ? This is not defined. That’s why our answer in the table is ‘No’.
Try These : (Textbook Page No.6)
Question 1.
Complete the following table:
Answer:
Try These : (Textbook Page No.9)
Question 1.
Complete the following table:
Answer:
Think, Discuss and Write : (Textbook Page No.11)
1. If a property holds for rational numbers, will it also hold for integers ? For whole numbers ? Which will ? Which will not ?
Answer:
( i ) Any property which is true for rational numbers is also true for integers except for any integers ‘a’ and ‘b’ (a ÷ b) is not necessarily an integer.
(ii) All properties which are true for rational numbers are also true for whole numbers also except:
- For ‘a’ and ‘b’ being whole numbers (a – b) may not be a whole number.
- For ‘a’ and ‘b’ being whole numbers (b ≠ 0), a ÷ b may not be a whole number.
Try These : (Textbook Page No.13)
1. Find using distributivity :
Question (i).
\(\left\{\frac{7}{5} \times\left(\frac{-3}{12}\right)\right\}+\left\{\frac{7}{5} \times \frac{5}{12}\right\}\)
Answer:
\(\left\{\frac{7}{5} \times\left(\frac{-3}{12}\right)\right\}+\left\{\frac{7}{5} \times \frac{5}{12}\right\}\)
= \(=\frac{7}{5} \times\left[\frac{-3}{12}+\frac{5}{12}\right]\)
= \(\frac{7}{5} \times\left[\frac{-3+5}{12}\right]\)
= \(\frac{7}{5} \times \frac{2}{12}\)
= \(\frac{7}{5} \times \frac{1}{6}\)
= \(\frac {7}{30}\)
Question (ii).
\(\left\{\frac{9}{16} \times \frac{4}{12}\right\}+\left\{\frac{9}{16} \times \frac{-3}{9}\right\}\)
Answer:
\(\left\{\frac{9}{16} \times \frac{4}{12}\right\}+\left\{\frac{9}{16} \times \frac{-3}{9}\right\}\)
= \(\frac{9}{16} \times\left[\frac{4}{12}+\left(\frac{-3}{9}\right)\right]\)
= \(\frac{9}{16} \times\left[\frac{12+(-12)}{36}\right]\) …..(LCM = 36)
= \(\frac{9}{16} \times\left[\frac{0}{36}\right]\)
= \(\frac{9}{16} \times 0\)
= 0.
Try These : (Textbook Page No.17)
1. Write the rational number for each point labelled with a letter:
Question (i).
Answer:
Here, the rational number for-
the point A is \(\frac {1}{5}\)
the point B is \(\frac {4}{5}\)
the point C is \(\frac {5}{5}\) or 1.
the point D is \(\frac {8}{5}\)
the point E is \(\frac {9}{5}\)
Question (ii).
Answer:
Here, the rational number for-
the point F is \(\frac {-2}{6}\) or \(\frac {-1}{3}\).
the point G is \(\frac {-5}{6}\).
the point H is \(\frac {-7}{6}\).
the point I is \(\frac {-8}{6}\) or \(\frac {-4}{3}\).
the point J is \(\frac {-11}{6}\).